Dynamically Generating Page Numbers - php

Question

I currently have an index.php page which serves as an index for a "My Bookmarks" page. The page returns the results of a MySQL Database Query, into a table, which is automatically generated. The code is only supposed to allow five records per page, before generating an additional page (thus inserting page numbers/links at the bottom) - For some reason, my code just stopped working/producing the page numbers.
What is wrong with my code? I can't seem to find the problem and I don't know what to search on the forum; any guidance is much appreciated.
Here is my index.php code:
<?php
session_start();
//check session first
if (!isset($_SESSION['email'])){
echo "You are not logged in!";
exit();
}else{
//include the header
include ("../includes/header.php");
require_once ('../../mysql_connect.php');
echo ("<center>");
echo ("<div class='bookmarkMenu'><h1 style='text-decoration:underline;'>Q & A Database</h2><p>");
echo ("<p><a class='bookmarkAdd' href=add.php>Add Record</a> ");
echo ("<a class='bookmarkSearch' href=searchform.php>Search Records</a></p><hr /></div><br />");
//Set the number of records to display per page
$display = 5;
//Check if the number of required pages has been determined
if(isset($_GET['p'])&&is_numeric($_GET['p'])){//Already been determined
$pages = $_GET['p'];
}else{//Need to determine
//Count the number of records;
$query = "SELECT COUNT(ID) FROM bookmark";
$result = #mysql_query($query);
$row = #mysql_fetch_array($result, MYSQL_NUM);
$records = $row[0]; //get the number of records
//Calculate the number of pages ...
if($records > $display){//More than 1 page is needed
$pages = ceil($records/$display);
}else{
$pages = 1;
}
}// End of p IF.
//Determine where in the database to start returning results ...
if(isset($_GET['s'])&&is_numeric($_GET['s'])){
$start = $_GET['s'];
}else{
$start = 0;
}
//Make the paginated query;
$query = "SELECT * FROM answers LIMIT $start, $display";
$result = #mysql_query ($query);
//Table header:
echo "<table class='bookmarksTable' cellpadding=5 cellspacing=5 border=1><tr>
<th>ID</th><th>Question</th><th>Answer</th><th>Comment</th><th>*</th><th>*</th></tr>";
//Fetch and print all the records...
while ($row = mysql_fetch_array($result, MYSQL_ASSOC)) {
echo "<tr><td class='bookmarkInfo'>".$row['ID']."</td>";
echo "<td class='bookmarkInfo'>".$row['Question']."</td>";
echo "<td class='bookmarkInfo'>".$row['Answer']."</td>";
echo "<td class='bookmarkInfo'>".$row['Comment']."</td>";
echo "<td class='bookmarkInfo'>Delete</td>";
echo "<td class='bookmarkInfo'>Update</td></tr>";
} // End of While statement
echo "</table>";
mysql_free_result ($result); // Free up the resources.
mysql_close(); // Close the database connection.
//Make the links to other pages if necessary.
if($pages>1){
echo '<br/><table><tr>';
//Determine what page the script is on:
$current_page = ($start/$display) + 1;
//If it is not the first page, make a Previous button:
if($current_page != 1){
echo '<td> Previous </td>';
}
//Make all the numbered pages:
for($i = 1; $i <= $pages; $i++){
if($i != $current_page){ // if not the current pages, generates links to that page
echo '<td> ' . $i . ' </td>';
}else{ // if current page, print the page number
echo '<td>'. $i. '</td>';
}
} //End of FOR loop
//If it is not the last page, make a Next button:
if($current_page != $pages){
echo '<td> Next </td>';
}
echo '</tr></table>'; //Close the table.
}//End of pages links
//include the footer
include ("../includes/footer.php");
}
?>
Much thanks,
-Rockmandew

Answer 1

you should be counting from answers table and do page logics based on that then your query on answers table at the bottom would fit