I am learning some PHP/MYSQL over a tutorial and I think that syntax has changed since that tutorial was produced. Please help me out, this are my first steps with PHP/MYSQL. I have been stuck here for some hours now. Connection to DB is successful, but can't query any data.
I run local wamp server and here is the code:
PHP 5.4
MYSQL 5.6
Here is the error:
You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'table' at line 1
<?php
//error_reporting(E_ALL);
require 'connect.php';
$result = $db->query("SELECT * FROM table") or die($db->error);
print_r($result);
?>
If table is the name of your table then you need to escape it with back ticks:
$result = $db->query("SELECT * FROM `table`") or die($db->error);
This is because table is one of MySQL reserved words and the rule is that if you need to use them then they need to be escaped with backticks.
$result = $db->query("SELECT * FROM `table`") or die($db->error);
$result = $db->fetch_array("SELECT * FROM `table`") or die($db->error);
print_r($result);
You are just selecting it. You need to fetch it as an array.
Also as #vee noticed, you need to use backticks => ` around the word table because table is a MySQL reserved word.
Related
I'm almost sorry to ask this question but I'm drawing a complete blank. I'm getting the following error:
"You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'WHERE number='7'' at line 1"
It seems whenever I try to use just an integer in the following code, I get the syntax error;
$go = mysql_query("UPDATE $db1 SET count='$t1c', WHERE number='$input2'") or die(mysql_error());
As you can see the page gets the value, that's not the issue.. it just doesn't seem to like the WHERE = 7 part. I've tried with and without the quote marks, I've tried changing that column in the table from a int to a varchar. Still get the same thing yet the code BEFORE this piece that runs:
$check1 = mysql_query("SELECT * FROM $db1 WHERE number='$input2'");
Run's absolutely fine. It finds the value where number equals $input2...
Can someone help me PLEASE? I'm drawing a complete blank here :/
Remove the , in the query:
mysql_query("UPDATE $db1 SET count='$t1c' WHERE number='$input2'");
Remove comma(,) which is placed before WHERE in UPDATE query
$go = mysql_query("UPDATE $db1 SET count='$t1c' WHERE number='$input2'") or die(mysql_error());
Change
"UPDATE $db1 SET count='$t1c', WHERE number='$input2'"
to
"UPDATE $db1 SET count='$t1c' WHERE number='$input2'"
The comma shouldn't be there (before WHERE) and is causing an error.
number is a reserved word in mysql sql
it is better not to name columns with that words or you need to backtick them in query
example:
`number`=3
mysql reserved words
I am getting an error when other same page is working good but another gives an error on same query code.
Here is my code what is wrong with this?
$ttt = mysql_query("SELECT * FROM like WHERE (user_id='$user_id' AND sound_id='$sound_id')",$link) or die(mysql_error());
error
You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'like WHERE (user_id='' AND sound_id='')' at line 1
like is an SQL reserved word and you should use "like" inside backticks ``
$ttt = mysql_query("SELECT * FROM `like` WHERE (user_id='$user_id' AND sound_id='$sound_id')",$link) or die(mysql_error());
like
Is a reserved word and cannot be used as a tablename the way you try to. Either try setting it into backticks or rename the table.
like is a reserved keyword use backtick for it
`like`
https://dev.mysql.com/doc/refman/5.5/en/reserved-words.html
Usage of LIKE in mysql
select * from table where username like '%aaa';
select * from table where username like '%aaa%';
select * from table where username like 'aaa%';
etc
As a rule you shouldn't use reserved words, but if you must, and for the purpose of this question, put brackets around it.
$ttt = mysql_query
("SELECT *
FROM [like]
WHERE (user_id='$user_id' AND sound_id='$sound_id')",$link) or die(mysql_error());
Like is reserved word. Better to change your table name or surrounded with back tick like this like
Try this.
$ttt = mysql_query("SELECT * FROM like_table WHERE user_id=$user_id AND sound_id=$sound_id",$link) or die(mysql_error());
I have a following code:
<?php
include("config.php");
$key = 'blahblah';
$sql = "INSERT INTO softversions SET key='$key'";
$result = mysql_query($sql) or die ($mysql_error());
echo "dude";
?>
This gives me an error:
You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'key='svksskjfvns'' at line 1
The thing is that I've used this script about a hundred times on other pages and it worked.
Table and field names are 100% correct.
I don't understand what is going on.
Do you see the syntax error there?
KEY is a reserved word in MySQL and you need to escape it using backticks to use it as a column name and also you should not use SET when inserting.
$sql = "INSERT INTO softversions (`key`) VALUES ('$key')";
key is a reserved word in MySQL. To use it as a column, you need to escape it every time you call it.
$sql = "INSERT INTO softversions SET `key`='$key'";
$sql = "INSERT INTO softversions(keyName) values('{$key}')";
This question already has an answer here:
Syntax error due to using a reserved word as a table or column name in MySQL
(1 answer)
Closed 8 years ago.
Hopefully someone can help me out. All I am trying to do is insert a record into a database, but I keep getting the message
You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'order (pid,uid,projecttitle,username,amount,odate) values (,,'','',,'6-2' at line 1` on my page.
Here is the main part of the code. I would be grateful for anyone that can help me out.
<?
extract($_REQUEST);
//print_r($_REQUEST);
//query fetch user & project info
//$queryorder="select * from project p where p.pid='".$id."'";
$queryorder="select * from users u,project p where p.pid='".$id."' and u.uid='".$_SESSION['key']."'";
$resultorder=executequery($queryorder,$link);
$rowo=mysql_fetch_assoc($resultorder);
//print_r($rowo);
//get today date
$createddate=date("n-j-Y");
//order
$order="insert into order (pid,uid,projecttitle,username,amount,odate)
values (".$rowo['pid'].",".$rowo['uid'].",'".$rowo['projectname']."','".$rowo['username']."',".$rowo['price'].",'".$createddate."')";
mysql_query($order) or die(mysql_error());
//end of insert order query
?>
<? //headtag.php conatain all javascript & css files
include('headtag.php');
?>
<body>
ORDER is a mysql keyword. Try this:
INSERT INTO `order` ...
order is a keyword. You need to escape it with backticks.
insert into `order` (pid,uid,projecttitle,username,amount,odate)...
You must supply a value for each column.
(,,'','',,'6-2'
You obviously have no values for pid, uid and amount.
Try this: (you are supplying empty values to that query)
$order="insert into order (pid,uid,projecttitle,username,amount,odate)
values (".(int)$rowo['pid'].",". (int)$rowo['uid'].",'".$rowo['projectname']."','".$rowo['username']."',". (float)$rowo['price'].",'".$createddate."')";
mysql_query($order) or die(mysql_error());
The second thing that will cause mysql syntax error is the table name - order is a reserved keyword in mysql, so you need to quote it. The beginning of the query will then be:
INSERT INTO `order` (...
I am working on a social networking site for my company and I am setting up the messaging system.
I have a table in the database called "mail" and for some reason the simplest SELECT query is returning an error.
here's the code:
$sql = "SELECT * FROM mail WHERE to='$username'";
$result = mysql_query($sql) or die(mysql_error());
while($row = mysql_fetch_assoc($result)){
$from = $row['from'];
$content = $row['content'];
echo "<tr><td>$from</td><td>$content</td></tr>";
}
It is returning this error; You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'to='cody'' at line 1
I have used this type of query with the same syntax a hundred times before I have no idea whats wrong this time.
A few notes: The database connection works fine, "to", "from" and "content" are columns in my "mail" table.
Thanks in advance for your help
TO is a reserved word. Try the following instead
$sql = "SELECT * FROM mail WHERE `to`='$username'";
Reserved words are permitted as
identifiers if you quote them as
described in Section 8.2,
Reference
"TO" is also a keyword try encapsulating the field name with a backtick `
I think the problem occurs due to this
to='$username'
$username is a Php variable so check out