How To Select User Selected Checkbox If Several With Same Name php - php

Question

I want to make it so the select boxes user selects stays selected encase validation fails later in my form the rest of the form works perfect but I cant seem to figure how to do this for select boxes without changing all the names can someone please help I have created this which contains just my form checkboxes and the action I will be doing later on so you can see what I require
<form id="form1" name="form1" method="post" action="<?php echo $_SERVER['PHP_SELF']; ?>">
<div id="desert_l">
<label for="hnumber"><div class="bookerror"></div>Desert Choice </label>
</div>
<div id="desert_f">
<table width="275">
<tr>
<td width="113">
<label>
<input type="checkbox" name="desgroup[]" value="Vanila Cheesecake"<?php if (isset($dessgroup) && ($dessgroup == "Vanila Cheesecake"))
{
echo ' checked="checked""';
}
?> />
Vanilla Cheesecake</label></td>
<td width="94"><input type="checkbox" name="desgroup[]" value="Carrot Cake"<?php if (isset($dessgroup) && ($dessgroup == "Carrot Cake"))
{
echo ' checked="checked""';
}
?> />
Carrot Cake</td>
<td width="52"><input type="checkbox" name="desgroup[]" value="Jelly"<?php if (isset($dessgroup) && ($dessgroup == "Jelly"))
{
echo ' checked="checked""';
}
?> />
Jelly</td>
</tr>
<tr>
<td><label>
<input type="checkbox" name="desgroup[]" value="Fruit Cheesecake"<?php if (isset($dessgroup) && ($dessgroup == "Fruit Cheesecake"))
{
echo ' checked="checked""';
}
?> >
Fruit Cheesecake</label></td>
<td><input type="checkbox" name="desgroup[]" value="Fruit Flan"<?php if (isset($dessgroup) && ($dessgroup == "Fruit Flan"))
{
echo ' checked="checked""';
}
?> />
Fruit Flan</td>
<td> </td>
</tr>
<tr>
<td><label>
<input type="checkbox" name="desgroup[]" value="Fruit Platter"<?php if (isset($dessgroup) && ($dessgroup == "Fruit Platter"))
{
echo ' checked="checked""';
}
?> />
Fruit Platter</label></td>
<td><input type="checkbox" name="desgroup[]" value="Chocolate Cake"<?php if (isset($dessgroup) && ($dessgroup == "Chocolate Cake"))
{
echo ' checked="checked""';
}
?>/>
Chocolate Cake</td>
<td> </td>
</tr>
</table>
<p>
<input type="submit" name="submit" id="submit" value="Submit" />
</p>
<p><span class="bookerror">
<?php
$dessgroup = $_POST['desgroup'] ;
if (isset ($_POST['submit']))
{
if (isset ($dessgroup))
{
echo "<h2>Desert Choice</h2>";
// Show Deserts Selected
for($i=0; $i < count($dessgroup); $i++)
{
echo $dessgroup[$i]."</br>";
}}
else
{
echo "You Must Select At Least 1 Desert" ;
}
}
?>
</span></p>
<p>Please Choose The Number Specified In Your Menu Choice<br />
</p>
</div>
</form>

Answer 1

Instead of
<input type="checkbox" name="desgroup[]" value="Vanila Cheesecake"<?php if (isset($dessgroup) && ($dessgroup == "Vanila Cheesecake"))
{
echo ' checked="checked""';
}
?> />
try
<input type="checkbox" name="desgroup[]" value="Vanila Cheesecake"<?php if (isset($_POST['desgroup']) && is_array($_POST['desgroup']) && in_array("Vanila Cheesecake", $_POST['desgroup']))
{
echo ' checked="checked""';
}
?> />
It would save you a lot of typing though if you would use arrays consequently.
$arr = array('possible value 1', 'possible value 2');
foreach ($arr as $val) {
?>
<input type="checkbox" name="desgroup[]" value="<?php echo $val; ?>"<?php if (isset($_POST['desgroup']) && is_array($_POST['desgroup']) && in_array($val, $_POST['desgroup']))
{
echo ' checked="checked""';
}
?> />
<?php
}

Answer 2

Try this
<input type="checkbox" name="desgroup[]" value="Vanila Cheesecake" <?php echo ((isset($dessgroup) && ($dessgroup == "Vanila Cheesecake")))?'checked="checked"':''; ?> />