UPDATE with form php/mysql - php

Question

I found this code online and now im trying to make it work. I get an error when I press Edit from the first page.
Notice: Undefined variable: id in edit_form2.php on line 19
I'm not sure why this variable isn't included in the code, where should it go? or does it have something to do with my table?
Database = album
Table = data_employees
1. id primaray key & a_i
2. name
3. address
When I press the edit button the next page should load the existing data from the database. Now it just turns up empty + the error code I wrote. What should I do?
edit.php
<td align="center">DATA</td>
</tr>
<tr>
<td>
<table border="1">
<?php
include"dbinc.php";//database connection
$order = "SELECT * FROM data_employees";
$result = mysql_query($order);
while ($row=mysql_fetch_array($result)){
echo ("<tr><td>$row[name]</td>");
echo ("<td>$row[employees_number]</td>");
echo ("<td>$row[address]</td>");
echo ("<td>Edit</td></tr>");
}
?>
</table>
edit_form2.php
<?php
include "dbinc.php";//database connection
$order = "SELECT * FROM data_employees
where employees_number='$id'";
$result = mysql_query($order);
$row = mysql_fetch_array($result);
?>
<form method="post" name=form action="edit_data2.php">
<input type="hidden" name="id" value="<?php echo "$row[employees_number]"?>">
<tr>
<td>Name</td>
<td>
<input type="text" name="name"
size="20" value="<?php echo "$row[name]"?>">
</td>
</tr>
<tr>
<td>Address</td>
<td>
<input type="text" name="address" size="40"
value="<?php echo "$row[address]"?>">
</td>
</tr>
<tr>
<td align="right">
<input type="submit"
name="submit value" value="Edit">
</td>
</tr>
</form>
edit_data2.php
<?php
//edit_data.php
include "dbinc.php";
$name = $_POST["name"];
$address = $_POST["address"];
$id = $_POST["id"];
$order = "UPDATE data_employees
SET name='$name',
address='$address'
WHERE
employees_number='$id'";
mysql_query($order);
header("location:edit.php");
?>

Answer 1

$id variable must be declared before use; like-
$id = mysql_real_escape_string($_GET['id']);

Answer 2

This line is wrong
<input type="hidden" name="id" value="<?php echo "$row[employees_number]"?>">
try
<input type="hidden" name="id" value="<?php echo $row['employees_number']?>">
So quite likely as the input field does not get built properly the browser is ignoring that field completely.

Answer 3

edit.php
replace
echo ("<tr><td>$row[name]</td>");
echo ("<td>$row[employees_number]</td>");
echo ("<td>$row[address]</td>");
echo ("<td>Edit</td></tr>");
with
echo "<tr><td>".$row['name']."</td>";
echo "<td>".$row['employees_number']."</td>";
echo "<td>".$row['address']."</td>";
echo "<td>Edit</td></tr>";
edit_form.php
<form method="post" name=form action="edit_data2.php">
<input type="hidden" name="id" value="<?php echo "$row[employees_number]"?>">
<tr>
<td>Name</td>
<td>
<input type="text" name="name"
size="20" value="<?php echo "$row[name]"?>">
</td>
</tr>
<tr>
<td>Address</td>
<td>
<input type="text" name="address" size="40"
value="<?php echo "$row[address]"?>">
</td>
</tr>
<tr>
should be
<?php
$id = mysql_real_escape_string($_GET['id']);include "dbinc.php";//database connection
$order = "SELECT * FROM data_employees
where employees_number='$id'";
$result = mysql_query($order);
$row = mysql_fetch_array($result);
?>
<form method="post" name=form action="edit_data2.php">
<input type="hidden" name="id" value="<?php echo $row['employees_number']; ?>">
<tr>
<td>Name</td>
<td>
<input type="text" name="name"
size="20" value="<?php echo $row['name']; ?>">
</td>
</tr>
<tr>
<td>Address</td>
<td>
<input type="text" name="address" size="40"
value="<?php echo $row['address']; ?>">
</td>
</tr>
<tr>
and like Mukesh Soni said, you need to grab te id from the url