How to calculate a running total? - php

Question

I have looked at the other (many closed) running total questions in PHP however none satisfy
This is my query
<?php
$query = "SELECT SUM(game_total) AS totalgames,
SUM(goals) AS totalgoals,
FROM player
WHERE year between 2006 and 2013
AND month between 1 and 12
GROUP BY
year,
month between 1 and 3,
month between 4 and 6,
month between 7 and 9,
month between 10 and 12
ORDER BY year ASC, month ASC";
$rquery = mysql_query($query) or die(mysql_error());
$show2 = '';
while ($row = mysql_fetch_array($rquery)){
$games = $row['totalgames'];
$goals = $row['totalgoals'];
$gpg = $games == 0 ? 0 : number_format($goals/$games,2);
}
?>
If I echo the results of the query completing the loop I get the following result
+---------+----------+-----------+
| Goals | Games | GPG |
+---------+----------+-----------+
| 8 | 15 | 0.53 |
+---------+----------+-----------+
| 2 | 12 | 0.17 |
+---------+----------+-----------+
| 2 | 12 | 0.17 |
+---------+----------+-----------+
| 13 | 21 | 0.62 |
+---------+----------+-----------+
etc etc
However, I want to calculate a running GPG in the following manner
Goals/Games=GPG
8/15=0.53
10/27=0.37 (8+2/15+12)=GPG
12/39=0.31 (10+2/27+12)=GPG
25/60=0.41 (12+13/39+21)=GPG
and I want to echo it like this
0.53,0.37,0.31,0.41 etc etc
how would I do this?

Answer 1

$count = 0;
while ($row = mysql_fetch_array($rquery)){
$count++;
$games = (int)$row['totalgames'];
$goals = (int)$row['totalgoals'];
$totalGames = 0;
$totalGoals = 0;
$totalGames += $goalData['games'];
$totalGoals += $goalData['goals'];
echo $totalGoals/$totalGames;
echo ($count === mysql_num_rows($rquery)-1) '' : ',';
}
There we go, running total GPG as it iterates, commas separated without making an extra array. That what you're looking for?