php next page blank for search result - php

Question

my default load page is ok with next and prev results.. but for search results i can get only first page then blank for the next page. let say total search results row is 9, it display 3 pages with next link. but when i click the next link, it queries no result on the page 2. here is my code:
echo '<table><tr><td>';
echo '<form method="post" name="frmSearch" action="mypage.php>
Search by name
<input type="text" name="txtSearch">
<input type="submit" name="submit" value="Search">
</form>';
$per_page = 5;
$page = 1;
if (isset($_GET['page']))
{
$page = intval($_GET['page']);
if($page < 1) $page = 1;
}
$start_from = ($page - 1) * $per_page;
$Prev_Page = $page - 1;
$Next_Page = $page + 1;
if (!$_POST){
//$sql = "SELECT * FROM mytable LIMIT $start_from, $per_page";
//$totalr = mysql_query("SELECT COUNT(*) FROM mytable");
//$totalr = mysql_fetch_row($totalr);
//$totalr = $totalr[0];
//$total_pages = $totalr / $per_page;
//$total_pages = ceil($total_pages);
//$listresult = mysql_query($sql);
//$total = mysql_num_rows($listresult);
}
else {
if ($_POST['txtSearch']!="") {$cond1 = " name LIKE
'%".$_POST['txtSearch']."%' ";} else {$cond1 = 1; }
$sql = "SELECT * FROM mytable WHERE ".$cond1." LIMIT $start_from, $per_page";
$totalr = mysql_query("SELECT COUNT(*) FROM mytable WHERE name LIKE
'%".$_POST['txtSearch']."%' ");
$totalr = mysql_fetch_row($totalr);
$totalr = $totalr[0];
$total_pages = $totalr / $per_page;
$total_pages = ceil($total_pages);
$listresult = mysql_query($sql);
$total = mysql_num_rows($listresult);
}
if($total == 0){
echo "<center>No records found.</center>";
}
echo "<span style='float:right;margin-top:8px;'>[ <a href='new.php'>Add New</a>
]</span></td></tr>";
echo "<table>
<tr>
<th>ID</th>
<th>Name</th>
</tr>
";
while ($_POST = mysql_fetch_assoc($listresult)){
echo "<tr>";
echo "<td>" . $_POST['id'] . "</td>";
echo "<td>" . $_POST['name'] . "</td>";
echo "</tr>";
}
echo "</table>";
echo "</table>";
echo $totalr." result";
echo "<br>";
if ($Prev_Page) {
echo " <a href ='{$_SERVER['PHP_SELF']}?page=$Prev_Page'><< Prev</a> ";
}
if ($totalr > $per_page) {
for($i = 1; $i <= $total_pages; ++$i)
{
echo "<a href='{$_SERVER['PHP_SELF']}?page=$i'>$i</a> | ";
}
}
if ($page!=$total_pages) {
echo " <a href='{$_SERVER['PHP_SELF']}?page=$Next_Page'>Next >></a> ";
}

Answer 1

maybe you need to use SELECT COUNT(*) FROM mytable WHERE name LIKE '%$search%' ... remember to escape the $_POST['txtSearch']