How to get japanese wiki link from my english wiki link? - php

Task: We have wikipedia English page and need to retrieve the same page address in Japanese.
suggested to parse http://en.wikipedia.org/wiki/Mini 4wd?action=raw results (there are other languages links in the bottom), but this way is too inefficient. Are there any other ways is the one real option?
We found some API in Wiki that seems fine for single word. but for two words like - Kamen rider, mini 4wd ... it doesn't work.
My code is not working
$url = 'https://en.wikipedia.org/w/api.php?action=query&prop=langlinks&format=json&lllimit=100&llprop=url&lllang=ja&titles=Kamen rider';
$url = rawurldecode(urlencode($url));
echo $url;
// outputs: https://en.wikipedia.org/w/api.php?action=query&prop=langlinks&format=json&lllimit=100&llprop=url&lllang=ru&titles=Mini+4wd
// and then the rest your logic whatever it is the rest
$header[] = "Accept: application/json";
$header[] = "Accept-Encoding: gzip";
$ch = curl_init();
curl_setopt( $ch, CURLOPT_HTTPHEADER, $header );
curl_setopt($ch,CURLOPT_ENCODING , "gzip");
curl_setopt($ch, CURLOPT_SSL_VERIFYPEER, false);
curl_setopt($ch, CURLOPT_SSL_VERIFYHOST, 0);
curl_setopt($ch, CURLOPT_CUSTOMREQUEST, 'GET');
curl_setopt( $ch, CURLOPT_URL, $url );
curl_setopt( $ch, CURLOPT_RETURNTRANSFER, true );
$response = json_decode(curl_exec($ch));
/* echo '<pre>';
print_r($response);
echo '</pre>'; */
exit;

Two words doesn't work because its not properly formatted. Kamen<space>rider and mini<space>4wd has spaces. You need it to be converted first. Consider this example:
$url = 'https://en.wikipedia.org/w/api.php?action=query&prop=langlinks&format=json&lllimit=100&llprop=url&lllang=ru&titles=Mini 4wd';
$url = rawurldecode(urlencode($url));
echo $url;
// outputs: https://en.wikipedia.org/w/api.php?action=query&prop=langlinks&format=json&lllimit=100&llprop=url&lllang=ru&titles=Mini+4wd
// and then the rest your logic whatever it is the rest
$contents = file_get_contents($url);
$contents = json_decode($contents, true);
// echo '<pre>';
// print_r($contents);
// echo '</pre>';
Sample Fiddle

Kindly try this code it works. Your $keywords = 'Mini 4wd';
$url = 'https://en.wikipedia.org/w/api.php?action=query&prop=langlinks&format=json&lllimit=100&llprop=url&lllang=ja&titles='.$keywords.'&redirects=';
$url1 = rawurldecode(urlencode($url));
$ch = curl_init();
// set url
curl_setopt($ch, CURLOPT_URL, $url1);
//return the transfer as a string
curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1);
curl_setopt($ch, CURLOPT_SSL_VERIFYHOST, 0);
curl_setopt($ch, CURLOPT_SSL_VERIFYPEER, 0);
// $output contains the output string
$output = curl_exec($ch);
$info = curl_getinfo($ch);
$exec = explode('"url":"',$output);
$exe = explode('",',$exec[1]);
$URL = $exe[0];
Output :
<p>Wikipedia Help here as <?php echo $URL;?></p>

Related

How to get results from udemy api with search

I have the same problem as here How to get results from Udemy Api with search? which unfortunately doesn't have an answer.
I'm able to retrieved the title etc, from this URL for example, https://www.udemy.com/api-2.0/courses/238934/?fields[course]=#all (you'll see the results in your browser) this URL works as well https://www.udemy.com/api-2.0/search-suggestions?q=java but not this one https://www.udemy.com/api-2.0/courses/?search=java
As mentioned here https://www.udemy.com/developers/affiliate/methods/get-courses-list/
get /api-2.0/courses/?search=java should work?
Here is my code:
$url = "https://www.udemy.com/api-2.0/courses/?search=java";
$ch = curl_init();
curl_setopt($ch, CURLOPT_SSL_VERIFYPEER, false);
curl_setopt($ch, CURLOPT_RETURNTRANSFER, true);
curl_setopt($ch, CURLOPT_URL,$url);
$c_id = base64_encode('XXX');
$c_sid = base64_encode('XXX');
curl_setopt($ch,CURLOPT_HTTPHEADER,array('X-Udemy-Client-Id: '.$c_id.'','X-Udemy-Client-Secret: '.$c_sid.'',"Authorization: base64 encoded value of client-id:client-secret","Accept: application/json, text/plain, */*"));
curl_setopt($ch, CURLINFO_HEADER_OUT, true);
$result=curl_exec($ch);
curl_close($ch);
$result = json_decode($result);
$title = $result->title;
If someone could please shed some light on this.
Based on ADyson comments, here is the answer (just update the code with your own clientID and clientSecret ID from Udemy):
I've basically updated the CURLOPT_HTTPHEADER:
Code:
$url = "https://www.udemy.com/api-2.0/courses/?search=java";
$ch = curl_init();
curl_setopt($ch, CURLOPT_SSL_VERIFYPEER, false);
curl_setopt($ch, CURLOPT_RETURNTRANSFER, true);
curl_setopt($ch, CURLOPT_URL,$url);
//HTTP username.
$clientID = 'XXX';
//HTTP password.
$clientSecret = 'XXX';
//Create the headers array.
$headers = array(
'Content-Type: application/json',
'Authorization: Basic '. base64_encode("$clientID:$clientSecret")
);
//Set the headers that we want our cURL client to use.
curl_setopt($ch, CURLOPT_HTTPHEADER, $headers);
curl_setopt($ch, CURLINFO_HEADER_OUT, true);
$result=curl_exec($ch);
// echo curl_getinfo($ch, CURLINFO_HEADER_OUT);
// echo curl_getinfo($ch,CURLINFO_HTTP_CODE);
curl_close($ch);
$json = json_decode($result, true);
// return $result;
foreach($json['results'] as $results) {
$title = $results['title'];
echo $title.'<br>';
}
Results: (Course titles based on this search: https://www.udemy.com/api-2.0/courses/?search=java)
Java Programming Masterclass for Software Developers
Java Programming for Complete Beginners
Java In-Depth: Become a Complete Java Engineer!
The Complete Java Certification Course
Etc.

What on my PHP Curl call do I need to add to read a response's custom headers?

I tried a few several ways to read the responses custom header but have not been able to. I know the response I get is served by nginx and the custom header names start with X-......
$endpoint = 'url here';
$ch = curl_init( $endpoint );
curl_setopt($ch, CURLOPT_RETURNTRANSFER, true);
curl_setopt($ch, CURLOPT_VERBOSE, 1);
curl_setopt($ch, CURLOPT_HEADER, 1);
curl_setopt($ch, CURLOPT_HEADERFUNCTION, 'cbFunc');
$result = curl_exec($ch);
print_r( curl_getinfo($ch ) );
The PHP manual is an excellent reference guide an a good starting point when you run into problems like this.
CURLOPT_HEADERFUNCTION [Set value to] A callback accepting five parameters.
hence
log_headers('init');
$endpoint = 'url here';
$ch = curl_init( $endpoint );
curl_setopt($ch, CURLOPT_RETURNTRANSFER, true);
curl_setopt($ch, CURLOPT_VERBOSE, 1);
curl_setopt($ch, CURLOPT_HEADER, 1);
curl_setopt($ch, CURLOPT_HEADERFUNCTION, 'log_headers');
$result = curl_exec($ch);
$headers=log_headers();
print_r($headers);
function log_headers($ch=false, $headers=false)
{
static $hdrs;
if (is_array($hrs) && $ch===$headers===false) {
return $hdrs[];
} elseif ($ch==='init') {
$hdrs=array();
return 0;
}
$hdrs[]=$headers;
return strlen($headers);
}

Bing Image search API v5.0 example for PHP

I'm trying, without success, to get some results using Bing's Image search API without HTTP/Request2.php component (as used in the official examples).
I understand that the only two required parameters to make a very primitive call are q which is the query string and the subscription key. The key must be sent using headers. After looking around I found this very simple example to send headers with PHP:
$sURL = "https://api.cognitive.microsoft.com/bing/v5.0/images/search?q=cats";
$aHTTP = array(
'Ocp-Apim-Subscription-Key' => 'xxxxxxx',
);
$context = stream_context_create($aHTTP);
$contents = file_get_contents($sURL, false, $context);
echo $contents;
But it does not output anything. Would you kindly help me with a very basic example of use of Bing's API?
SOLVED
Thanks to Vadim's hint I changed the way headers are sent and now output is a Json encoded result. (Remember to add your API subscription key.)
$sURL = "https://api.cognitive.microsoft.com/bing/v5.0/images/search?q=cats";
$ch = curl_init();
curl_setopt($ch, CURLOPT_URL, $sURL);
curl_setopt($ch, CURLOPT_TIMEOUT, '1');
curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1);
curl_setopt($ch, CURLOPT_SSL_VERIFYPEER, false);
curl_setopt($ch, CURLOPT_HTTPHEADER, array(
'Content-Type: multipart/form-data',
'Ocp-Apim-Subscription-Key: xxxxx'
));
$content = curl_exec($ch);
echo $content;
Just another tip. The syntax of query filters and other parameters change form version to version. For example the following work correctly in version 5.0:
To search only for JPEG images of cats and get 30 results use:
q=cats&encodingFormat='jpeg'&count=30
To search only for 'portrait' aspect images with size between 200x200 and 500x500 use:
q=cats&aspect=Tall&size=Medium
Try using cURL
$sURL = "https://api.cognitive.microsoft.com/bing/v5.0/images/search?q=cats";
$key = "xxxxxxx";
$ch = curl_init();
curl_setopt($ch, CURLOPT_URL, $sURL);
curl_setopt($ch, CURLOPT_TIMEOUT, '1');
curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1);
curl_setopt($ch, CURLOPT_HEADER, 'ocp-apim-subscription-key:$key');
$content = curl_exec($ch);
echo $content;
Here is my working code..
Replace ******** with your bing subscription key.
$sURL = "https://api.cognitive.microsoft.com/bing/v5.0/images/search?q=microsoft-surface&count=6&mkt=en-US";
$ch = curl_init();
curl_setopt($ch, CURLOPT_URL, $sURL);
curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1);
curl_setopt($ch, CURLOPT_SSL_VERIFYPEER, false);
curl_setopt($ch, CURLOPT_HTTPHEADER, array(
'Content-Type: multipart/form-data',
'Ocp-Apim-Subscription-Key: *******************'
));
$contents = curl_exec($ch);
$myContents = json_decode($contents);
if(count($myContents->value) > 0) {
foreach ($myContents->value as $imageContent) {
echo '<pre/>';
print_r($imageContent);
}
}

file_get_contents not retrieving page contents

OK, before saying this is a duplicate just read a bit....
I have been trying to echo contents of URL that has allow_url_fopen disabled for HOURS now, I have tried every solution posted on stack overflow. EXAMPLE:
$ch = curl_init();
curl_setopt($ch, CURLOPT_URL,$url);
$result = curl_exec($ch);
curl_close($ch);
Doesn't WORK
function curl_get_contents($url)
{
$ch = curl_init();
curl_setopt($ch, CURLOPT_HEADER, 0);
curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1);
curl_setopt($ch, CURLOPT_URL, $url);
$data = curl_exec($ch);
curl_close($ch);
return $data;
}
Doesn't WORK
$url = "http://www.google.com";
$ch = curl_init();
curl_setopt($ch, CURLOPT_URL, $url);
curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1);
$data = curl_exec($ch);
curl_close($ch);
echo $data;
Doesn't WORK
fopen("cookies.txt", "w");
$url="http://adfoc.us/1575051";
$ch = curl_init();
$header=array('GET /1575051 HTTP/1.1',
'Host: adfoc.us',
'Accept:text/html,application/xhtml+xml,application/xml;q=0.9,*/*;q=0.8',
'Accept-Language:en-US,en;q=0.8',
'Cache-Control:max-age=0',
'Connection:keep-alive',
'Host:adfoc.us',
'User-Agent:Mozilla/5.0 (Macintosh; Intel Mac OS X 10_8_4) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/27.0.1453.116 Safari/537.36',
);
curl_setopt($ch,CURLOPT_URL,$url);
curl_setopt($ch,CURLOPT_RETURNTRANSFER,true);
curl_setopt($ch,CURLOPT_CONNECTTIMEOUT,0);
curl_setopt( $ch, CURLOPT_COOKIESESSION, true );
curl_setopt($ch,CURLOPT_COOKIEFILE,'cookies.txt');
curl_setopt($ch,CURLOPT_COOKIEJAR,'cookies.txt');
curl_setopt($ch,CURLOPT_HTTPHEADER,$header);
$result=curl_exec($ch);
curl_close($ch);
Doesn't WORK
// create the Gateway object
$gateway = new Gateway();
// set our url
$gateway->init($url);
// get the raw response, ignore errors
$response = $gateway->exec();
Doesn't WORK
$file = "http://www.example.com/my_page.php";
if (function_exists('curl_version'))
{
$curl = curl_init();
curl_setopt($curl, CURLOPT_URL, $file);
curl_setopt($curl, CURLOPT_RETURNTRANSFER, 1);
$content = curl_exec($curl);
curl_close($curl);
}
else if (file_get_contents(__FILE__) && ini_get('allow_url_fopen'))
{
$content = file_get_contents($file);
}
else
{
echo 'You have neither cUrl installed nor allow_url_fopen activated. Please setup one of those!';
}
This doesn't work.
The page I am trying to use file_get_contents on is not on my website. I am trying to use file_get_contents so i can make a simple API for the site owner by reading a page and checking if a certain word is present on the page.
But yeah if anyone has any suggestions PLEASE post below :)
You can check first weather the site is available or not for example a sample code
Code taken from here:
<?php
$cURL = curl_init('http://www.technofusions.com/');
curl_setopt ( $cURL , CURLOPT_RETURNTRANSFER , true );
// Follow any kind of redirection that are in the URL
curl_setopt ( $cURL , CURLOPT_FOLLOWLOCATION , true );
$result = curl_exec ( $cURL );
// Getting HTTP response code
$answer = curl_getinfo ( $cURL , CURLINFO_HTTP_CODE );
curl_close ( $cURL );
if ( $answer == ' 404 ' ) {
echo ' The site not found (ERROR 404)! ' ;
} else {
echo ' It looks like everything is working fine ... ' ;
}
?>
For a full answer you can got to this tutorial Curl IN PHP

How to echo the cURL result in PHP?

Here is a URL→ https://ajax.googleapis.com/ajax/services/search/images?v=1.0&q=snoopy&rsz=1
and this is my php code
<?php
$url = "https://ajax.googleapis.com/ajax/services/search/images?"."v=1.0&q=snoopy";
$ch = curl_init();
curl_setopt($ch, CURLOPT_URL, $url);
curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1);
$body = curl_exec($ch);
curl_close($ch);
$json = json_decode($body);
?>
I wanna echo all of the image urls from its result
(For example: http://img2.wikia.nocookie.net/__cb20110331075248/peanuts/images/6/62/Snoopy.gif )
But I have no idea how to echo them.
Hope someone could help me, thanks!
Maybe like this:
<?php
$url = "https://ajax.googleapis.com/ajax/services/search/images?" .
"v=1.0&q=barack%20obama&userip=INSERT-USER-IP";
// sendRequest
// note how referer is set manually
$ch = curl_init();
curl_setopt($ch, CURLOPT_URL, $url);
curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1);
curl_setopt($ch, CURLOPT_REFERER, 'http://example.com');
$body = curl_exec($ch);
curl_close($ch);
// now, process the JSON string
$pics = json_decode($body);
$ret='';
if($pics){
foreach($pics->responseData->results as $pic)
$ret .= $pic->url.'<br>';
}
echo $ret;
?>
in order to echo the exact result just use:
echo $body; //echoes json string
if you want to echo the exact link, echo like this:
echo $json->responseData->results[0]->url; //echoes http://img2.wikia.nocookie.net/__cb20110331075248/peanuts/images/6/62/Snoopy.gif
or you can foreach() twice (or once...) then echo $res->url directly :) your choise!

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