Getting Mysql field from an array - php

Question

I have the following script to display files inside a directory
<?PHP
# The current directory
$directory = dir("./");
# If you want to turn on Extension Filter, then uncomment this:
$allowed_ext = array(".deb", ".ext", ".ext", ".ext", ".ext", ".ext");
$do_link = TRUE;
$sort_what = 0; //0- by name; 1 - by size; 2 - by date
$sort_how = 0; //0 - ASCENDING; 1 - DESCENDING
# # #
function dir_list($dir){
$i=0;
$dl = array();
if ($hd = opendir($dir)) {
while ($sz = readdir($hd)) {
if (preg_match("/^\./",$sz)==0) $dl[] = $sz;$i.=1;
}
closedir($hd);
}
asort($dl);
return $dl;
}
if ($sort_how == 0) {
function compare0($x, $y) {
if ( $x[0] == $y[0] ) return 0;
else if ( $x[0] < $y[0] ) return -1;
else return 1;
}
function compare1($x, $y) {
if ( $x[1] == $y[1] ) return 0;
else if ( $x[1] < $y[1] ) return -1;
else return 1;
}
function compare2($x, $y) {
if ( $x[2] == $y[2] ) return 0;
else if ( $x[2] < $y[2] ) return -1;
else return 1;
}
}else{
function compare0($x, $y) {
if ( $x[0] == $y[0] ) return 0;
else if ( $x[0] < $y[0] ) return 1;
else return -1;
}
function compare1($x, $y) {
if ( $x[1] == $y[1] ) return 0;
else if ( $x[1] < $y[1] ) return 1;
else return -1;
}
function compare2($x, $y) {
if ( $x[2] == $y[2] ) return 0;
else if ( $x[2] < $y[2] ) return 1;
else return -1;
}
}
##################################################
# Getting The information
##################################################
$i = 0;
while($file=$directory->read()) {
$file = strtolower($file);
$ext = strrchr($file, '.');
if (isset($allowed_ext) && (!in_array($ext,$allowed_ext)))
{
// dump
}
else {
$temp_info = stat($file);
$new_array[$i][0] = $file;
$new_array[$i][1] = $temp_info[7];
$new_array[$i][2] = $temp_info[9];
$new_array[$i][3] = date("F d, Y", $new_array[$i][2]);
$i = $i + 1;
}
}
$directory->close();
##################################################
# Sorting the information
#################################################
switch ($sort_what) {
case 0:
usort($new_array, "compare0");
break;
case 1:
usort($new_array, "compare1");
break;
case 2:
usort($new_array, "compare2");
break;
}
###############################################################
# Displaying the information
###############################################################
$i2 = count($new_array);
$i = 0;
echo "<table class='CSSTableGenerator'>
<tr>
<td width=290>File name (Download)</td>
<td align=center width=70>Downloads</td>
<td align=center width=70>Depiction</td>
<td align=center width=50>Size</td>
<td align=center width=85>Modified</td>
</tr>";
for ($i=0;$i<$i2;$i++) {
if (!$do_link) {
$line = "<tr><td>" . $new_array[$i][0];
$line .= '</td><td>Depiction</td>';
$line .= "<td>" . number_format(($new_array[$i][1]/1024)) . " KB</td>";
$line .= "<td>" . $new_array[$i][3] . "</td></tr>";
}else{
$line = '<tr><td align=left ><A class="ex1" HREF="' .
$new_array[$i][0] . '">' .
$new_array[$i][0] .
"</A></td>";
$line .= '<td> </td>';
$line .= '<td>Depiction</td>';
$line .= "<td>" . number_format(($new_array[$i][1]/1024)) . " KB</td>";
$line .= "<td>" . $new_array[$i][3] . "</td></tr>";
}
echo $line;
}
echo "</table>";
?>
The output looks like that:
I am trying to fill the downloads column by getting the download counts of each file from mysql table
So i am facing 2 issues here:
How to get the stats using the array of the files $new_array[$i][0]
How can i then add this mysql query output inside $line .= '<td> </td>';
I have tried getting the stats from the table using this:
include("../config.php");
$query = "SELECT stats FROM download WHERE filename='$new_array[$i][0]'";
$result = mysql_query($query);
while ($row = mysql_fetch_array($result)) {
$line .= '<td>' . $row['stats'] . '</td>';
}
but it didn't work, i think the issue is with the array $new_array[$i][0] because i tried writing a filename filename='com.name.app3_2.2-1_iphoneos-arm.deb' and i got the stats of this file

Answer 1

In your "getting the information part", you must initialise your arrays thusly:
##################################################
# Getting The information
##################################################
$i = 0;
$new_array = array();
while($file=$directory->read()) {
$file = strtolower($file);
$ext = strrchr($file, '.');
if (isset($allowed_ext) && (!in_array($ext,$allowed_ext)))
{
// dump
}
else {
$new_array[$i] = array();
$temp_info = stat($file);
$new_array[$i][0] = $file;
$new_array[$i][1] = $temp_info[7];
$new_array[$i][2] = $temp_info[9];
$new_array[$i][3] = date("F d, Y", $new_array[$i][2]);
$i = $i + 1;
}
}
$directory->close();
##################################################
In addition, I have noted that your line:
$query = "SELECT stats FROM download WHERE filename='$new_array[$i][0]'";
Would cause $query to be equal to:
SELECT stats FROM download WHERE filename='Array[0]'
When $i is 0.
What you should do is use the mysqli library thusly:
$mysqli = new mysqli("example.com", "user", "password", "database");
$query = "SELECT stats FROM download WHERE filename=?";
$stmt = $mysqli->prepare($query);
$stmt->bind_param('s', $new_array[$i][0]);
$stmt->execute();
$stmt->bind_result($stats);//stats turns into a reference by default.
while($stmt->fetch()) { //$stats now contains the stats
$line .= '<td>'. htmlentities($stats).'</td>';
}
To deal with the problem of missing cells you just described, you might try:
$mysqli = new mysqli("example.com", "user", "password", "database");
$query = "SELECT stats FROM download WHERE filename=?";
$stmt = $mysqli->prepare($query);
$stmt->bind_param('s', $new_array[$i][0]);
$stmt->execute();
$stmt->bind_result($stats);//stats turns into a reference by default.
$fetched = false;
while($stmt->fetch()) { //$stats now contains the stats
$line .= '<td>'. htmlentities($stats).'</td>';
$fetched = true;
}
if(!$fetched) {
$line .= '<td></td>'
}