I have a very simple PHP question about replacing in string.
For example, our string is this :
This is a test - spam text
and i need to convert this string to this :
This is a test
I mean i want to detect the place of - charachter and delete everything after that.
How to do it ?
One of the possible solutions:
$result = substr($str, 0, strpos($str, '-'));
use substr to return part of a string and strpos to find the position of the first occurrence of a substring in a string
$str = 'This is a test - spam text';
$newStr = substr($str, 0, strpos($str, '-'));
// start ^ end ^
Try
$str = "This is a test - spam text";
$str = substr($str, 0, strpos( $str, '-'));
strpos() detects where - is.
You can use Regular expressions to match anything after the - character.
This should work
/-.*/
When you match the string then you can replace the content using simple string functions.
Related
I need to know how to do this reliably with the least amount of calls.
I have a string and I need to remove the 8th character from it. It doesn't matter what the char is, I just need to remove ONLY the 8th char.
I came up with this but a little too unwieldy for me.
// 12345678901234567890
$str = '5NMSG3AB1AH353158';
// after removing char, result should be:
// 5NMSG3A1AH353158
$r = str_split($str);
unset($r[7]);
echo join('', $r);
Possibly Regex?
Here are some solutions:
$str = substr($str, 0, 7) . substr($str, 8);
$str = substr_replace($str, '', 7, 1);
$str = preg_replace('/(.{7})./', '$1', $str, 1);
$str = preg_replace('/.{7}\K./', '', $str, 1);
I'd go for substr() or better substr_replace() as this will certainly be fastest and most easy to read.
substr_replace makes this very simple.
$string = substr_replace($string, '', 7, 1);
It can also take an array of strings as its first parameter, and do the same replacement in all of them, which can be pretty handy.
Like this
$str = '5NMSG3AB1AH353158';
echo preg_replace('/^(.{7})./', '\1', $str);
Output:
5NMSG3A1AH353158
Sandbox
Explanation
^ start of string
(...) capture
. match any
{7} seven times
. match any one time
Then the replacement
\1 first capture group
Basically capture the first 7 chars, then match the 8th, and replace that with the captured 7 chars. Which effectively removes the 8th.
UPDATE
here is another way I like (I haven't used that function sense college, I think):
$s = '5NMSG3A1AH353158';
echo substr_replace($s,'',7,1); //strings are 0 based
sandbox
substr_replace() replaces a copy of string delimited by the start and (optionally) length parameters with the string given in replacement.
mixed substr_replace( mixed $string, mixed $replacement, mixed $start [, mixed $length ] )
http://php.net/manual/en/function.substr-replace.php
Simple.
I have a long string that I want everything from the first "-" on to be removed and the remaining saved.
I have tried rtrim and this does not work. can figure explode so that will not work
Use substr() with strpos().
$str = "3568206020-1201103628-13107292-0001";
//extract the substring from start to the first occurrence of the character `-`.
$str = substr($str, 0, strpos($str, "-"));
Output - 3568206020
I am running into a problem trying to do a replacement on a few strings. Essentially what I have is a bunch of prices on my page that look like
RMB148.00
What i am trying to do is run a replace on only the last 2 numbers so i can do something like
RMB14800
Preg replace works fine for the RMB part because it is always there.
My problem is the last two numbers can be anything it all depends on the price so I cant just remove and replace, I need to just wrap HTML <sup> tags around them.
$string = $product['price'];
$string = preg_replace('/[\x00-\x1F\x80-\xFF]/', '', $string);
echo preg_replace('/RMB/', '<sup class="currency-sym">RMB</sup>', $string, 1);
Assuming the last two characters are digits, you could just
$string=preg_replace('/(\d\d)$/', '<sup class="currency-sym">\1</sup>', $string);
If not,
$string=preg_replace('/(..)$/', '<sup class="currency-sym">\1</sup>', $string);
should do the trick.
Alternativly use
$string=substr($string,0,-2).'<sup class="currency-sym">'.substr($string,-2).'</sup>';
Here is a regex solution that looks for the final digit notation at the end of your string.
$string = 'RMB148.00';
$string = preg_replace('/(\d+)\.(\d{2})\z/','$1<sup>$2</sup>',$string);
echo $string;
You could use the following with the explode () function
$string = explode ('.', $product['price']);
$new_string = $string[0].'<sup>'. $string [1]. '</sup>';
And do the regex for the RMB the same way.
Code.
<?php
$string = '14842.00';
$string = substr($string, 0, strlen($string) - 2) . '<sup>' . substr($string, strlen($string) - 2, 2) . '</sup>';
echo $string;
Try online sandbox.
Explanation.
substr($s, $i, $l) gets $l symbols of $s, started from $i index (indexes starts from zero).
So first substr($string, 0, strlen($string) - 2) gets all string except last two symbols.
Second substr($string, strlen($string) - 2, 2) gets only last two symbols.
More about substr.
You should use a pattern matching regex. Note the $1 in the replacement argument matches (\d{2}) in the pattern argument. preg_replace() only replaces the matched pattern. This pattern matches . followed by any two digits. Since . is not included in the replacement argument it does not show up in your $string.
$string = preg_replace('/\.(\d{2})$/', '<sup>$1</sup>', $string);
Of course, you could use one preg_replace to do what you want:
$string = preg_replace('/^(RMB)(\d+)(\.(\d{2}))?$/', "<sup class='currency-sym'>$1</sup>$2<sup>$4</sup>", $string);
The second example may be a good idea if you want DOM integrity, otherwise it creates an empty <sup></sup> when there is no decimal.
This question already has answers here:
Closed 10 years ago.
Possible Duplicate:
Preg Replace - replace second occurance of a match
I have a string that includes the word rules twice. I need to find and replace the 2nd word. Tried fooling around with str_replace() but couldn't get anything, the 4th parameter wasn't what I expected.
Here is an example string:
http://localhost/proj1/modstart/admin/index.php?i=rules&sid=397ab1f6b8eb8a17787438a7e2e60ea3&mode=rules
After my replace it should look like this:
http://localhost/proj1/modstart/admin/index.php?i=rules&sid=397ab1f6b8eb8a17787438a7e2e60ea3&mode=manage
I read that preg_replace() could help, but I don't know how to write patterns.
Ideas?
P.S: Don't suggest splitting the string into two variables, that wouldn't serve my needs.
It would be a very good idea to learn about regular expressions. In PHP, you can accomplish your find/replace like this:
$result = preg_replace('/(rules.*?)rules/','$1manage',$str,1);
It basically finds "rules" once, then anything, then rules a second time, then puts it all back before the second match and replaces the word.
To not use a regular expression, and also to not store anything into a second variable, you could use str_replace() with a little magic from strpos():
$string = substr($string, 0, strpos($str, 'rules') + 5) . str_replace('rules', 'whatever', substr($string, strpos($string, 'rules') + 5));
This will take the full string up-to the end of the first instance of rules and then do the string-replacement on the second-part of the string which will contain any other instance of the word.
The same thing, but a little more cleaner (yes, by using a second variable):
$pos = strpos($string, 'rules') + 5;
$string = substr($string, 0, $pos) . str_replace('rules', 'whatever', substr($string, $pos));
If the word to find+replace is dynamic or you want to use a different word on different pages, you could make that a variable, like this:
$findMe = 'rules';
$replaceWith = 'whatever';
$pos = strpos($string, $findMe) + strlen($findMe);
$string = substr($string, 0, $pos) . str_replace($findMe, $replaceWith, substr($string, $pos));
You should use regex >>
$new = preg_replace('/\brules\b(?!.*\brules\b)/', 'manage', $old);
It is a good idea to use word boundaries \b, so it will not match some larger strings that contain "rules", such as "preudorules".
Negative lookahead (?!.*\brules\b) ensures there is no other word "rules" behind, so the one you are replacing is the last one.
I need to know how I can replace the last "s" from a string with ""
Let's say I have a string like testers and the output should be tester.
It should just replace the last "s" and not every "s" in a string
how can I do that in PHP?
if (substr($str, -1) == 's')
{
$str = substr($str, 0, -1);
}
Update: Ok it is also possible without regular expressions using strrpos ans substr_replace:
$str = "A sentence with 'Testers' in it";
echo substr_replace($str,'', strrpos($str, 's'), 1);
// Ouputs: A sentence with 'Tester' in it
strrpos returns the index of the last occurrence of a string and substr_replace replaces a string starting from a certain position.
(Which is the same as Gordon proposed as I just noticed.)
All answers so far remove the last character of a word. However if you really want to replace the last occurrence of a character, you can use preg_replace with a negative lookahead:
$s = "A sentence with 'Testers' in it";
echo preg_replace("%s(?!.*s.*)%", "", $string );
// Ouputs: A sentence with 'Tester' in it
$result = rtrim($str, 's');
$result = str_pad($result, strlen($str) - 1, 's');
See rtrim()
Your question is somewhat unclear whether you want to remove the s from the end of the string or the last occurence of s in the string. It's a difference. If you want the first, use the solution offered by zerkms.
This function removes the last occurence of $char from $string, regardless of it's position in the string or returns the whole string, when $char does not occur in the string.
function removeLastOccurenceOfChar($char, $string)
{
if( ($pos = strrpos($string, $char)) !== FALSE) {
return substr_replace($string, '', $pos, 1);
}
return $string;
}
echo removeLastOccurenceOfChar('s', "the world's greatest");
// gives "the world's greatet"
If your intention is to inflect, e.g singularize/pluralize words, then have a look at this simple inflector class to know which route to take.
$str = preg_replace("/s$/i","",rtrim($str));
The very simplest solution is using rtrim()
That is exactly what that function is intended to be used for:
Strip whitespace (or other characters) from the end of a string.
Nothing simpler than that, I am not sure why, and would not follow the suggestions in this thread going from regex to "if/else" blocks.
This is your code:
$string = "Testers";
$stripped = rtrim( $string, 's' );
The output will be:
Tester