Printing only 3 td for row in php - php

Question

I am trying to print the value from database. the database contains the image URL.
I am retrieving the image url through php and printing it.
I have written this code to do so.
code:
<?php
if(! $conn )
{
die('Could not connect: ' . mysql_error());
}
$sql = 'SELECT name,thumbnail,link FROM courses';
mysql_select_db($dbname);
$retval = mysql_query( $sql, $conn );
if(! $retval )
{
die('Could not get data: ' . mysql_error());
}
while($row = mysql_fetch_assoc($retval))
{
echo "<tr>";
echo "<td><a href='".$row['link']."' title='Click to see schedule'><img src='".$row['thumbnail']."'></a></td>";
echo "</tr>";
}
mysql_close($conn);
?>
This code is retriving image URL and displaying images on table. But I want 3 images per row, now it is printing only 1 image per row.
How can i do this?

Answer 1

You need to change your code to only open and close the row every third image. Try this:
$i = 0;
while($row = mysql_fetch_assoc($retval))
{
if($i == 0) {
echo "<tr>";
}
echo "<td><a href='".$row['link']."' title='Click to see schedule'><img src='".$row['thumbnail']."'></a></td>";
if(++$i == 3) {
echo "</tr>";
$i = 0;
}
}
// To close any open rows at the end
if($i % 3 > 0) {
echo "</tr>";
}

Answer 2

$cc = 0;
//initially open table row
echo "<tr>";
while($row = mysql_fetch_assoc($retval))
{
$cc++;
echo sprintf(
'<td><img src="%s"></td>',
$row['link'],
$row['thumbnail']
);
//close tablerow and open new one every 3 rows
if($cc % 3 == 0){
echo "</tr><tr>";
}
}
//close last table row
echo "</tr>";

Answer 3

this code prints data in 3 columns in a row. Please try
$cols=3; $col=0;
$vars = "<table>";
$vars .= "<tr>";
while($row = mysql_fetch_assoc($retval)){
$col++;
$vars .= "<td>".$row['link']."</td>";
if($col==$cols){
$col=0;
$vars .= "</tr><tr>";
}
}
$vars = "</tr>";
$vars .= "</table>";
Hope this helps.