PHP+MySQL Printing query results - php

Question

I used to print MySQL query results like this:
$query="SELECT fname,lname,email FROM users";
$result=mysql_query($query);
$num=mysql_numrows($result);
mysql_close();
$i=0;
echo '<table BORDERCOLOR=black>';
?>
<tr>
<th>Vardas</th><th>Pavarde</th><th>E-Mail</th>
</tr>
<?php
while ($i < $num) {
$field1=mysql_result($result,$i,"fname");
$field2=mysql_result($result,$i,"lname");
$field3=mysql_result($result,$i,"email");
echo "<td>";
echo $field1;
echo "</td>";
echo "<td>";
echo $field2;
echo "</td>";
echo "<td>";
echo $field3;
echo "</td>";
echo "</tr>";
$i++;
}
echo "</table>";
But this time I have to use something different , and I was wondering how can I print out my results when using the function/query shown below:
Query code (in 'class DB'):
function query($querytext) {
$rs = mysql_query($querytext, $this->_link);
if($this->_debug) {
$this->addDebugMessage("\t<tr>\n\t\t<td class=\"debug_nr\">".$this->_queryCount++."</td>\n\t\t<td class=\"debug_queInfo\"><b>Query: (".#mysql_num_rows($rs).")</b></td>\n\t\t<td>" . htmlspecialchars($querytext) . "</td>\n\t</tr>\n");
if(mysql_error() != '') {
$this->addDebugMessage("\t<tr>\n\t\t<td class=\"debug_nr\">".$this->_queryCount++."</td>\n\t\t<td class=\"debug_queInfo\"><b>Error #".mysql_errno($this->_link)." :</b></td>\n\t\t<td>" . htmlspecialchars(mysql_error($this->_link)) . "</td>\n\t</tr>\n");
}
}
if($rs) {
$num_rows = #mysql_num_rows($rs);
if($num_rows) {
if($num_rows > 0) {
$rsarray = array();
while($line = mysql_fetch_array($rs , MYSQL_ASSOC)) {
array_push($rsarray, $line);
}
mysql_free_result($rs);
return $rsarray;
} else {
return false;
}
} else {
if(mysql_affected_rows($this->_link) > 0) {
return true;
} else {
return false;
}
}
} else {
return false;
}
}
(in 'class User')
function findUser($phrase){
global $DB;
$results=$DB->query("SELECT * FROM users WHERE fname LIKE '%'$phrase'%' OR lname LIKE '%'$phrase'%' OR email LIKE '%'$phrase'%'");
return $results;
}
In index.php (what do I use to print this out?):
$USER->findUser("john");
or maybe it should be
$results= $USER->findUser("john);
OR
$results=DB->findUser("john");

Answer 1

Seems you have a typo
function findUser($phrase){
global $DB;
$DB->query("SELECT * FROM users WHERE fname LIKE '%'$phrase'%' OR lname LIKE '%'$phrase'%' OR email LIKE '%'$phrase'%'");
}
There is extra quotes in your query.
function findUser($phrase){
global $DB;
$DB->query("SELECT * FROM users WHERE fname LIKE '%$phrase%' OR lname LIKE '%$phrase%' OR email LIKE '%$phrase%'");
}