I have a form on an HTML/PHP page.
I have the same exact code on other pages on the site, and it works fine. I cannot figure it out.
Form:
<form method="post" action="<?php echo $_SERVER['PHP_SELF']; ?>">
<input name="prize_id" type="hidden" value="<?php echo $prize_id; ?>" />
<input name="ContestEntry" type="submit" class="submit" value="Enter me in the Raffle!" />
</form>
I looked at the HTML source code, and the action populates the correct page, and $prize_id populates the correct info in the value.
PHP:
if(isset($_POST['ContestEntry'])){
//...code to enter data into form, irrelevent since it won't post anything anyway.
}
else {
echo 'Nothing posted from form';
}
"Nothing posted from form" always shows, and no data is being entered into the database. I've tried changing the form name to 5 different things, thinking maybe there was a conflicting name somewhere, but nothing works.
Any ideas?
If all you need to achieve is check whether the form is submitted or not, it's better to check that the request type is a POST:
if ($_SERVER['REQUEST_METHOD'] === 'POST') {
// Process form
} else {
// Nothing posted!
}
Also change your submit button to:
<button type="submit">Submit</button>
and see what happens
The code you posted actually works for me.
But, if you still can't get it working, I would try checking to see if prize_id is set rather than the button. The PHP script is executed when the form is submitted.
Also, I would recommend that you don't use $_SERVER['PHP_SELF'] as the form action. According to https://stackoverflow.com/a/14093363/3593228, that can make it easy for attackers to insert malicious data. Instead, leave the action empty.
The if Condition is not working because you put it on Button, instead of this just make an hidden field in the form to check form is submit or not like as you already have one. Or make new for this form.
<input name="prize_id" type="hidden" value="<?php echo $prize_id; ?>" />
Consider adding what you're looking for as another hidden field:
<form method="post" action="<?php echo $_SERVER['PHP_SELF']; ?>">
<input name="prize_id" type="hidden" value="<?php echo $prize_id; ?>" />
<input name="ContestEntry" type="hidden" value="Enter me in the Raffle!" />
<input type="submit" class="submit" />
</form>
Related
I have a problem of getting the value of an input element. Thanks in advance for help! This is the sample code:
<form action="#" method="POST">
<input name="X" value="3" />
<?php
//question: how can I put the value of input in a variable
//$_POST['X']; isn't applicable since I am in the same form.
?>
</form>
<form action="<?php echo htmlspecialchars($_SERVER["PHP_SELF"]);?>" method="POST">
<input name="X" value="3" />
<input type="submit" value="Submit">
</form>
<?php
if(isset($_POST['X']) == true){
echo $_POST['X'];
}
?>
First of all submitting a form on its own page is a bad practice because whenever you reload the page the form will submit everytime.
Best approach is that you set the action attribute of form to another file or link.
fileOne.php (where your form is located):
<form action="anotherfile.php" method="POST">
<input name="X" value="3" />
<button type="submit" name="submitForm">Submit</button>
</form>
Then in anotherfile.php you will do this:
$check = $_POST["submitForm"];
If(isset($check))
{
$myInputValue = $_POST["X"];
header("Location: fileOne.php/?val".$myInputValue);
}
Then in fileOne.php you can get the variable and its value which is sent via link in the browser like this:
$getInputValue = $_GET["val"];
Now you can echo out the $getInputValue variable wherever you want.
If the the information is not sensitive this is the best approach you got. But if it is, try saving that value in the session and retrieving in the file where you want. I hope it helps. Typed code via app so it might throw an error. But i think this code will work fine. Good luck!
I have a script that users can submit certain data, and after a submit they can "review" the output and go back to previous page or submit to it again and there is my proble, the submitted page: How can I submit it again to write it to a file?
form.html
<form method="post" action="vaihe2.php">
<input name="laskuttaja" type="text" value="Nimi" size="25">
<input name="submit" type="submit" value="Lähetä" />
</form>
vaihe2.php
<?
$laskuttaja = $_POST['laskuttaja'];
$data = '<B>'.$laskuttaja.'</b>';
echo $data;
?>
So how can I post that $data to next page(vaihe3.php) with submit and let the script write it to a file. I know how php write file works but the post to third page is not working.
If you wat to go back, the secret is in the value of the input.
<input name="laskuttaja" type="text" value="<?php echo(isset($_POST['laskuttaja'])?$_POST['laskuttaja']:"Nimi";?>" size="25"/>
To 'save' data to the next page use $_SESSIONs. They're simple to use. Just remember everywhere you use them, you must have session_start(); on LINE 1! Can't stress that enough!
$_SESSION['data']=$data;
on your third page:
echo$_SESSION['data'];
More on sessions here.
In vaihe2.php
<form method="post" action="vaihe3.php">
<?
$laskuttaja = $_POST['laskuttaja'];
$data = '<B>'.$laskuttaja.'</b>';
echo $data;
echo "<input name=\"laskuttaja\" type=\"hidden\" value=\"".$laskuttaja."\" size=\"25\">";
?>
<input name="submit" type="submit" value="anything" />
</form>
Here you are passing laskuttaja as hidden field and on post will be available to you in third page.
Now data flow as per your requirement. User fills data in form.html -> reviews on vaihe2 and confirms -> gets written in vaihe3.
Could you post the form conditionally back to itself until validated by checkbox? the action would change to "vaihe3.php" ?
<form method="post" action="<?php if ($_POST["valid"]==1) {echo 'vaihe3.php';} ?>">
<input name="laskuttaja" type="text" value="<?php if ($_POST['laskuttaja']!=='') {echo '$_POST[laskuttaja]'} else {echo 'Nimi';} ?>" size="25">
<?php if (isset ($_POST['laskuttaja') && $_POST['laskuttaja']!=="") {
echo 'Please Confirm your answers: <input name="valid" type="checkbox" value="1" />'; } ?>
<input name="submit" type="submit" value="Lähetä" />
</form>
Otherwise, the mention above about CURL would be another option. Or - since your using PHP anyways, you could write the values of form submission to a session array and make them available to all pages until you empty the array.
I want to create a hidden field in my HTML page, all good, just a simple <input> field. Then, I'm trying to read the value of that input field as the page loads the first time, so the closest I've gotten to that is using a $_GET statement. I'm simply trying to echo out the value so that I can see that it's working like such:
<input type="hidden" name="selection" value="fixtures">
<?php
echo $_GET['selection']
and that just gives me nothing, if I try:
echo "<h1>$_GET['selection']</h1>
then I get 0.
Question is - what <form> parameters you have? Did you submit form? Simples example for it will be:
//form.php
<form method="GET" action="next.php">
<input type="hidden" name"selection" value="fixtures" />
<input type="submit" name="submit_btn" value="Send" />
</form>
//next.php
echo '<h1>'.$_GET['selection'].'</h1>';
You can achieve same thing with:
Link
I have one page with a simple post form
<form name="click" action="UserOrders.php" method="post">
<input type="hidden" name="amount" value="<?php echo $total ?>">
<input type="image" src="/Templates/images/UpdateButton.png" name="submit">
</form>
and the only thing I want to check is if it submits.. In the other page "UserOrders.php" I just wrote
<?php
if ($_POST['submit']){
echo $_SESSION['ID'];
}
It seems to me irregular that it doesn't work and I would like another set of eyes to check it out.
(if i put the echo $_SESSION['ID'] outside the brackets, it works.)
An input type="image" only defines that image as the submit button and not as an input that can carry over a value to the server. source
An alternative way to see if the form was submitted is to check $_SERVER['REQUEST_METHOD']
if ('POST' === $_SERVER['REQUEST_METHOD']) {
// submitted
}
I agree with the previous answer. You are not actually putting any information to the form and therefore there is nothing for the new form to react to. $_POST['submit"] is looking for data that was sent and not for the method of sending.
There's no actual submit button. You need a
<form action="UsersOrders.php" method="POST">
<input type="whatever you want" name="input">
<input type="submit" name="submit">
</form>
Now if you go into UsersOrders.php and do what you did before:
if($_POST['submit']) {
echo $_POST['input'];
}
You will actually get some input.
got a small problem, this code
<form action="<?php echo $_SERVER['PHP_SELF']; ?>" method="post">
<?php
...
echo '<input name="textfield" type="text" id="textfield" value="Roger" />';
echo 'Hello, '.$_POST['textfield'].'<br>';
...
?></p>
</form>
should echo out "Hello, Roger", as roger is the default value, yet it gives out only "Hello, " and nothing else. Any suggestions?
edit: yes, there's a form.
Thanks!
You are echoing the text box and at the same time hoping to gets its value, which is not possible.
echo '<input name="textfield" type="text" id="textfield" value="Roger" />';
echo 'Hello, '.$_POST['textfield'].'<br>';
You need to first submit the form with method set to post and only then you can get its value.
Example:
<form action="<?php echo $_SERVER['PHP_SELF']; ?>" method="post">
...
<input name="textfield" type="text" id="textfield" value="Roger" />
...
<input name="submit" type="submit" id="submit" value="submit" />
</form>
PHP
if (isset($_POST['submit']))
{
echo 'Hello, '.$_POST['textfield'].'<br>';
}
Try print_r($_POST) or var_dump($_POST) to see if any POST data gets submitted.
Edit: Did you specify POST as the submit method in your form tag? Do you submit the form? Please show the entire <form>-Tag.
If this is, exactly, your code then the problem is that the $_POST is not set yet since no form is submitted.
check the css (is it hidden..?=
check the source for the page (does the input field appear?)
don't forget to wrap the input in a form if you want to submit it back to the same page.
My guess it, that the server doesn't allocate $_GET and/or $_POST. You could check that in the php configuration.
Have a look if you can access the data via $_REQUEST, which should unify get and post data.