Require()'ing a Class to use in Inheritance - php

I just have a simple question here... I was working on developing a forum application for my website, and while updating some of the old methods I used (my old code is horrid) I came across - not for the first time - OOP devices.
I have quite a few classes that my system uses, and redefining the same function(s) for them over and over, so I decided to create a base class that would carry the functionality.
I've been trying to use require() on the base class then extend the class off of it...
<?php
require(//path to base class);
class User extends BaseClass {
// code
}
?>
But I don't know how to check if it's there, and it doesn't seem to be inheriting the base class's only function...
public function __get($what) {
if(property_exists($this, $what)) {
return $this->{$what};
} else {
return null;
}
}
Since when I try to retrieve a variable from the User class (e.g. $user->Username) it returns NULL. The variable is marked as private in the class, but before I tried to do inheritance that wasn't an issue.

It sounds like you are wanting to get after your variables in your parent class but do not want to use getter methods to do so. Marking these variables protected will indeed allow your child classes access to those properties, but in cases where you want your base class to enforce processing before setting/getting, marking the properties protected will not cut it.
In your case it sounds like you are marking your variables protected as a workaround. However you can still use private variables in your base class and allow access to them in your child classes as follows:
class BaseClass
{
private $strValue = "We the people....";
public function __get($what)
{
if(isset($this->{$what})) {
return $this->{$what};
}
return null;
}
}
class ChildClass extends BaseClass
{
private $intValue = 255;
public function __get($what)
{
if(isset($this->{$what})) {
return $this->{$what};
} else if(parent::__get($what) != null) {
return parent::__get($what);
}
return null;
}
}
//Try it out
$child = new ChildClass();
var_dump($child->strValue); //"We the people...."
var_dump($child->intValue); //255
In this example the BaseClass uses the __get() magic method to lookup its own properties and the ChildClass overrides it to do the same. In the ChildClass if it cannot find a requested property, then it diverts to the parent's version.
As long as you don't override your properties you can use private variables throughout and access them as if they were public outside of your class scope.

just use
class_exists() to make sure your class is there.

Related

Extension inheritance in PHP?

When developing in C#, and you had many classes that used the same exact code, you could rely on another class to hold the generic information, making it easier to modify these classes.
I was wondering if there was anything like that in PHP?
class Dog extends Animal {
private $animalManager
public function __construct(AnimalManager $animalManager) {
$this->animalManager = $animalManager;
}
}
class Cat extends Animal {
private $animalManager
public function __construct(AnimalManager $animalManager) {
$this->animalManager = $animalManager;
}
}
class Fish extends Animal {
private $animalManager
public function __construct(AnimalManager $animalManager) {
$this->animalManager = $animalManager;
}
}
class Animal {
// Nothing, yet...
}
What C# would allow you to do is, store the $animalManager and the constructor assignement in the 'Animal' class somehow, making it constant in 1 place if you ever needed to change it.
The thing is, PHP does this quite neatly.Every extending class inherits everything from the extended class. This means the parent's (in this case animal) construct will run whenever you call one of the extending classes.
However, you overwrite your parent's class when you call __construct() within the child. Therefore you'd need to specifically call parent::__construct() to run the parent constructor.
class Animal {
//Private vars can't be directly accessed by children.
//You'd have to create a function in the parent return it.
public $animalManager
//This function will automatically be called if you leave the
//constructor out of the extended class
public function __construct($animalManager) {
$this->animalManager = $animalManager;
}
//If you want $animalManager to be private
//Call like $fish->getAnimalManager();
//Though I do not see the use of this.
public function getAnimalManager(){
return $this->animalManager
}
}
class Fish extends Animal {
//You do not need to do this if you leave the construct out of this class
public function __construct($animalManager) {
parent::__construct($animalManager);
//Do whatever you like here
}
}
Example with only the parent constructor:
class Fish extends Animal {
//The parent's constructor is called automatically as it's not
//Being overwritten by this class
public function test(){
var_dump($this->animalManager);
}
}
Note that you would also not need to initiate the parent class seperately. Just call it like so;
$fish = new Fish(myAnimalManager);
$am = $fish->animalManager;
echo $am;
A draft has been added by Ben Scholzen for generics here.
But all I can see is type parameters and no wildcards. It supports generic functions and generic constructors. It also supports Bounds.
Unlike C# and Java, PHP will have its type arguments fully reified, which means we can reflectively know the run time parameter of desired function/constructor.
Backward compatibility is not a concern here, because type parameters and raw types can never be compatible. So the legacy code won't be compatible with Generics.

Save object clone as protected property

I intend to create a clone of an object's parent within the constructor of that parent. In short:
class ParentClass {
protected $property;
public function __construct() {
$this->property = clone $this;
}
}
class ChildClass extends ParentClass {
}
This works all fine, yet the problem with this code is the protected property getting populated with an instance of the ChildClass, in case the ChildClass is instantiated. I would however like it to be an instance of the ParentClass regardless of the class $this refers to.
I could of course combine debug_backtrace and new self() (in order to avoid endless recursion of constructor invocations) and assign the resulting ParentClass instance to the property, though such a soluation is verbose, as debug backtrace only returns string names of caller classes and methods.
Lastly, I could combine new self() and the provision of an argument to the instantiation of the object indicating if a "new self" should be created, but I dislike the solution because of its ugliness and redundancy.
Is there a way in PHP to find a "clone of self"?
As discussed in the comments, I think the reason this pattern is not working for you is that you have a poorly designed object hierarchy. In the example, ChildClass is a "type of" ParentClass, but also internally references a copy of ParentClass to do some delegated work.
From the comments, what you have must look something like this:
class BasicLogger {
protected $delegated_logger;
public function __construct() {
// initialise $this->delegated_logger somehow
}
public function logMessage($message, $flags) {
{
$prepared_message = $this->prepareMessage($message, $flags);
$this->deliverMessage($prepared_message);
}
private function prepareMessage($message, $flags) {
// implementation here
}
protected function deliverMessage($prepared_message) {
// implementation here
}
}
class MailLogger extends BasicLogger {
protected function deliverMessage($prepared_message) {
// different implementation here
if ( $mail_sending_failed ) {
$this->delegated_logger->logMessage('Oops, MailLogger failed...');
}
}
}
However, BasicLogger is actually performing multiple roles in the object hierarchy:
defining the interface that all loggers should adhere to (here represented as a single logMessage method)
providing a shared implementation of prepareMessage that all loggers will use, and an implementation of logMessage that depends on it plus a deliverMessage function
providing a specific implementation of deliverMessage that will be completely over-written by child classes
providing a mechanism for complex implementations to delegate to simpler implementations, without a way of distinguishing between the two
The first three roles should be separated into an interface, an abstract base class, and a simple implementation:
interface Logger {
public function logMessage($message, $flags = null);
}
abstract class BaseLogger implements Logger {
public function logMessage($message, $flags = null) {
{
$prepared_message = $this->prepareMessage($message, $flags);
$this->deliverMessage($prepared_message);
}
private function prepareMessage($message, $flags) {
// implementation here
}
abstract protected function deliverMessage($prepared_message);
}
class BasicTextLogger extends BaseLogger {
protected function deliverMessage($prepared_message) {
// implementation here
}
}
You can then use instances of BasicTextLogger wherever you need, including in other implementations of BaseLogger.
You might want to put the logic of having a delegated logger (the 4th role of my BasicLogger above) into another class for reuse. BasicTextLogger shouldn't inherit this behaviour, or you'll end up needing to provide a logger to a logger to a logger to a logger, ad infinitum.
abstract class ComplexLogger extends BaseLogger {
protected $delegated_logger;
public function __construct( Logger $delegated_logger ) {
if ( $delegated_logger instanceOf ComplexLogger ) {
throw new Exception('Attempted to delegate one complex logger to another; danger of recursion, so disallowed.');
} else {
$this->delegated_logger = $delegated_logger;
}
}
}
class MailLogger extends ComplexLogger {
protected function deliverMessage($prepared_message) {
// different implementation here
if ( $mail_sending_failed ) {
$this->delegated_logger->logMessage('Oops, MailLogger failed...');
}
}
}
This then allows you to perform Dependency Injection to provide your complex logger with a simple logger to delegate to:
$my_logger = new MailLogger( new BasicTextLogger() );
$my_logger->logMessage('Hello World!');
This may seem like a lot of different classes and interfaces, but each now has a clear responsibility. You could put the whole $delegated_logger logic into MailLogger, but you'd have to copy and paste it if you had another complex logger later. You might also be able to ignore the Logger interface, and just type-hint for classes deriving from the BaseLogger class, but it's possible you'll want an implementation that doesn't use prepareMessage at all - for instance, a DoNothingLogger.

Overriding methods in PHP?

In other OO languages like Java we can override a function, possible using keywords/annotations like implements, #override etc.
Is there a way to do so in PHP? I mean, for example:
class myClass {
public static function reImplmentThis() { //this method should be overriden by user
}
}
I want user to implement their own myClass::reImplementThis() method.
How can I do that in PHP? If it is possible, can I make it optional?
I mean, if the user is not implementing the method, can I specify a default method or can I identify that the method is not defined (can I do this using method_exists)?
<?php
abstract class Test
{
abstract protected function test();
protected function anotherTest() {
}
}
class TestTest extends Test
{
protected function test() {
}
}
$test = new TestTest();
?>
This way the class TestTest must override the function test.
Yes, there is. You have the option to override a method by extending the class and defining a method with the same name, function signature and access specifier (either public or protected) it had in the base class. The method should not be declared abstract in the base class or you will be required to implement it in the derived class. In you example it would look something like this:
class MyClass {
public static function reImplmentThis() { //this method should be overriden by user
}
}
class MyDerivedClass extends MyClass {
public static function reImplmentThis() { //the method you want to call
}
}
If the user does not overrides it, MyDerivedClass will still have a reImplmentThis() method, the one inherited from MyClass.
That said, you need to be very careful when invoking extended static methods from your derived class to stay out of trouble. I encourage you to refactor your code to extend instance methods unless you have a very specific need to extend static classes. And if you decide there is no better way than extending static classes please be sure to understand Late Static Binding pretty well.
Yes, its possible to check if the method is implemented or not and get a whole lot more of information about a class using PHP Reflection.
This touches on several OOP subjects.
First, simply overriding an method declared in a parent class is as simple as re-declaring the method in an inheriting class.
E.g:
class Person {
public function greet(string $whom) {
echo "hello $whom!";
}
}
class Tommy extends Person {
public function greet(string $whom = "everyone") {
echo "Howdy $whom! How are you?";
}
}
$a = new Tommy();
$a->greet('World');
// outputs:
// Howdy World! How are you?
If on the overriding method you wan to reuse the logic of the overriden one, it's just a matter of calling the parent's method from the extending class::
class Tommy
{
public function greet(string $whom)
{
// now with more emphasis!!!
echo parent::greet(strtoupper($whom)) . "!!!!";
}
}
Now Tommy::greet() calls Person::greet(), but modifies the result before returning it.
One thing to note is that overriding methods have to be compatible with the overriden one: the method visibility can't be more restrictive than the original one (it's OK to increase visibility), and the number and type of required arguments can't conflict with the original delcaration.
This works, because the type of the arguments does not clash with the original, and we have less required arguments than on the parent:
class Leo extends Person {
public function greet(string $whom = "gorgeous", string $greet = "Whatsup" ) {
echo "$greet $whom. How are you?";
}
}
But this doesn't, since there are additional required arguments. This would make impossible to switch the original class for this one transparently, and thus would throw a Warning:
class BadBob extends Person {
public function greet(string $whom, string $greet ) {
echo "$greet $whom. How are you?";
}
}
Additionally, you mention in your question that "this method should be overriden by the user". If you require client classes to actually implement the method, you have a couple of options:
Abstract classes & methods
These are methods where the implementation is left empty, and that extending classes have to implement to be valid. In we changed our original class Person to:
abstract class Person {
public function greet(string $whom) {
echo "hello $whom!";
}
public abstract function hide();
}
Since now the class contains an abstract method, it needs to be declared as an abstract class as well.
Now it is not possible to instantiate Person directly, you can only extend it in other classes.
Now all our existing Person extending classes would be wrong, and trying to execute the previous code would throw a fatal error.
An example of a valid class extending Person now would be:
class Archie extends Person {
public function hide() {
echo "Hides behind a bush";
}
}
Any class that extends Person must declare a public hide() method.
Interfaces
Finally, you mention interfaces. Interfaces are contracts that implementing classes have to fulfill. They declare a group of public methods without an implementation body.
E.g.:
interface Policeman {
public function arrest(Person $person) : bool;
public function help($what): bool;
}
Now we could have class that extended Person and implemented Policeman:
class Jane extends Person implements Policeman {
public function hide() {
echo "Jane hides in her patrol-car";
}
public function arrest(Person $person): bool{
// implement arrest method
return false;
}
public function shoot($what): bool {
// implements shoot() method
return false;
}
}
Importantly, while it's possible to extend only one class (there is no multiple inheritance in PHP), it is possible to implement multiple interfaces, and the requirements for each of those have to be fulfilled for the class to be valid.

PHP accessing variables from the parent class CLOSED

I've seen a few questions with really similar titles but they where irrelevant to my specific problem.
Basically, I want to access the variables from my core class in a class which extends core, but things seem to be quite complicated compared to other examples. I am using a MVC framework. I've simplified the code below to remove anything that was irrelevant.
index.php
// Load the core
include_once('core.php');
$core = new Core($uri, $curpath);
$core->loadController('property');
core.php
class Core
{
public $uri;
public $curpath;
function __construct($uri, $curpath)
{
$this->uri = $uri;
$this->curpath = $curpath;
}
// Load the controller based on the URL
function loadController($name)
{
//Instantiate the controller
require_once('controller/'.$name.'.php');
$controller = new $name();
}
}
property.php
class Property extends Core
{
function __construct()
{
print $this->curpath;
}
}
Printing $this->curpath just returns nothing. The variable has been set but it is empty.
If I print $this->curpath inside core.php it prints fine.
How can I access this variable?
You are doing it wrong tm
You should be utilizing an autoloader, instead of including files with each class manually. You should learn about spl_autoload_register() and and namespaces, and how to utilize both of them.
Do not generate output in the __construct() methods. That's an extremely bad practice
The variables are still there. That is not the problem. In PHP, when you extend a class, it does not inherit the constructor.
You do not understand how inheritance works. When you call method on instance of extended class it will not execute parent class's method , before calling extended class's methods. They get overwritten , not stacked.
Object variables should not be exposed. You are breaking the encapsulation. Instead og defining them as public you should use protected.
You should extend classes of they are different type same general thing. The extends in PHP means is-a. Which means that, when you write class Oak extends Tree, you mean that all the oaks are trees. The same rule would mean, that in your understanding all Property instances are just a special case of Core instances. Which they clearly ain't.
In OOP, we have principle. One of which is Liskov substitution principle (shorter explanation). And this is the thing your classes are violating.
The problem, I think, lies here:
If you consider a simple inheritance like this one:
class Dog{
public $color;
public function __construct($color){
$this->color = $color;
}
}
class TrainedDog extends Dog{
public $tricks;
public function __construct($color, $tricks){
$this->tricks = $tricks;
parent::__construct($color);
}
}
//Create Dog:
$alfred = new Dog('brown');
//Create TrainedDog
$lassie = new TrainedDog('golden',array('fetch'));
In this example $alfred is a brown dog and $lassie is a golden dog. The two instances are separate from each other, the only thing they have in common is that they both have a property called $color.
If you want a variable that is available in all Dogs for example, you need a class variable:
class Dog{
public $color;
public static $numberOfLegs; //Class variable available in every instance of Dog.
public function __construct($color, $numberOfLegs){
$this->color = $color;
self::$numberOfLegs = $numberOfLegs;
}
}
class TrainedDog extends Dog{
public $tricks;
public function __construct($color, $tricks){
$this->tricks = $tricks;
parent::__construct($color);
echo parent::$numberOfLegs;
}
}
This does not make much sense in many cases though, because if you have two instances of the parent class (in you're case Core), they also share the class variable.
Unless you can ensure that Core is instanciated only once, this approach will not work. If it does only exist once, you can just as well use constant variables to store the 2 properties.
If there exist multiple instances/objects of Core, I'd recommend using a composition (as suggested by Alvin Wong).
class Core{
//Just as you programmed it.
}
class Property{
private $core;
public function __construct($core){
$this->core = $core;
echo $core->curPath;
}
}
Try this
include_once('core.php');
$core = new Core('test', 'path');
$core->loadController('property');
class Property extends Core
{
function __construct($date)
{
print $date->curpath;
}
}
class Core
{
public $uri;
public $curpath;
function __construct($uri, $curpath)
{
$this->uri = $uri;
$this->curpath = $curpath;
}
// Load the controller based on the URL
function loadController($name)
{
//Instantiate the controller
require_once($name.'.php');
$controller = new $name($this);
}
}

Blocking the possibility to create classes directly bypassing a factory

In a base class for all the models in our MVC system, I created a factory method BaseCLass::getNew() that returns an instance of the requested child class when called via SomeChildClass::getNew().
Now, I'm looking for a way to force the programmer to use this factory. I.e., idially I'd like that any class created directly, like this:
new SomeChildClass
will throw an exception upon creation, and only classes created by the factory will be usable.
Any ideas how can this be achieved?
Our code is written in PHP, but good chance that your idea will be valuable even if you think on a different language.
edit: I cannot make my constructor private, as the framework constructor in the class that I inherit is public, and php would not allow me this.
By making the constructor of the child class protected. The parent class will have access to all protected methods of the child. Any attempt to directly create the child (ie: new child) will cause a fatal error.
<?php
class factory
{
static public function create()
{
return new child;
}
}
class child extends factory
{
protected function __construct()
{
echo 'Ok';
}
}
$c = factory::create(); // Ok
$c2 = new child; // fatal error
?>
Though this method won't let you throw an exception instead :(
If then absolutely necessary, only debug_backtrace() function comes to mind (besides using singleton for the child itself, or forced object pool patterns using and passing GUID's generated by factory and verified by child). Within the child constructor, look at the 2nd array value to make sure "function" === "create" and "class" === "factory. Throw exception if not matching. I didn't suggest this initially, only because I suspect using debug_backtrace may give a performance hit.
By making the class have a private constructor.
Update -- solution that covers your stated requirements
class Base {
private static $constructorToken = null;
protected static function getConstructorToken() {
if (self::$constructorToken === null) {
self::$constructorToken = new stdClass;
}
return self::$constructorToken;
}
}
class Derived extends Base {
public function __construct($token) {
if ($token !== parent::getConstructorToken()) {
die ("Attempted to construct manually");
}
}
public static function makeMeOne() {
return new Derived(parent::getConstructorToken());
}
}
This solution takes advantage of the object equality rules for stdClass by storing a "magic password" object on the base class which only derived classes can access. You can tweak it to taste.
I wouldn't call it horrible like the debug_backtrace idea, but still I have the impression that things should be done differently.
Declare the class's constructor private, and it can only be called from within the class's own methods like getNew().
there are couple of ways to implement it
make parent class private use magic
user magic function __autoload; check the type of class and through error with not allowed message
http://php.net/manual/en/function.is-a.php
The best way is to define constructor of the class private or protected. But if you cannot do it, you can control where an object of the class is created in the constructor:
trait FactoryChecking
{
protected function checkFactory(string $factoryClass): void
{
$trace = debug_backtrace(DEBUG_BACKTRACE_IGNORE_ARGS);
foreach($trace as $traceItem) {
if ($traceItem['class'] == $factoryClass) {
return;
}
}
throw new Exception('Cannot create class ' . static::class . ' outside of factory');
}
}
class ClassA
{
use FactoryChecking;
public function __construct()
{
$this->checkFactory(Factory::class);
}
}
class Factory
{
public function create(): ClassA
{
return new ClassA();
}
}
Details I described in the article "Forbidding of creating objects outside factory in PHP"

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