Convert PHP file To PDO [closed] - php

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i am beginer to php and i need your help.i want to make the following code to PDO to have a json output for an android app i am trying to bulit.I tryed a lot of solution but nothing correct came because of the JSON responce.I couldn also find good example and tutorials.Also i am new as i said with php so i am afraid to try complicated scenarios
here is the php code
This is my Config file
db_config.php
<?php
define('DB_USER', "root"); // db user
define('DB_PASSWORD', ""); // db password (mention your db password here)
define('DB_DATABASE', "androidhive"); // database name
define('DB_SERVER', "localhost"); // db server
?>
This is connection file
db_connect.php
<?php
class DB_CONNECT {
// constructor
function __construct() {
// connecting to database
$this->connect();
}
// destructor
function __destruct() {
// closing db connection
$this->close();
}
/**
* Function to connect with database
*/
function connect() {
// import database connection variables
require_once __DIR__ . '/db_config.php';
// Connecting to mysql database
$con = mysql_connect(DB_SERVER, DB_USER, DB_PASSWORD) or die(mysql_error());
// Selecing database
$db = mysql_select_db(DB_DATABASE) or die(mysql_error()) or die(mysql_error());
// returing connection cursor
return $con;
}
/**
* Function to close db connection
*/
function close() {
// closing db connection
mysql_close();
}
}
?>
get_all_products.php
<?php
/*
* Following code will list all the products
*/
// array for JSON response
$response = array();
// include db connect class
require_once __DIR__ . '/db_connect.php';
// connecting to db
$db = new DB_CONNECT();
// get all products from products table
$result = mysql_query("SELECT *FROM products") or die(mysql_error());
// check for empty result
if (mysql_num_rows($result) > 0) {
// looping through all results
// products node
$response["products"] = array();
while ($row = mysql_fetch_array($result)) {
// temp user array
$product = array();
$product["pid"] = $row["pid"];
$product["name"] = $row["name"];
$product["price"] = $row["price"];
$product["created_at"] = $row["created_at"];
$product["updated_at"] = $row["updated_at"];
// push single product into final response array
array_push($response["products"], $product);
}
// success
$response["success"] = 1;
// echoing JSON response
echo json_encode($response);
} else {
// no products found
$response["success"] = 0;
$response["message"] = "No products found";
// echo no users JSON
echo json_encode($response);
}
?>
I know is very easy for someone with experience but i am strungle with it.please help because i have a strick deadline and no time now for deaper search.Thank you
**Would it be helpfull if i post what i have done?I didnt post it for space reason**s
EDIT
THIS IS WHAT I HAVE DONE SO FAR ANY IDEAS?
$db = new PDO("mysql:host=$dbhost;dbname=$dbname;", $dbuser, $dbpass);
$query = "Select * FROM products";
//execute query
try {
$stmt = $db->prepare($query);
$result = $stmt->execute(HAVE NO IDEA!!!!);
}
catch (PDOException $ex) {
$response["success"] = 0;
$response["message"] = "Database Error!";
die(json_encode($response));
}
$rows = $stmt->fetchAll();
if ($rows) {
$response["success"] = 1;
$response["message"] = "Post Available!";
$response["posts"] = array();
foreach ($rows as $row) {
$post = array();
$post["pid"] = $row["pid"];
$post["name"] = $row["name"];
$post["price"] = $row["price"];
//update our repsonse JSON data
array_push($response["posts"], $post);
}
// echoing JSON response
echo json_encode($response);
} else {
$response["success"] = 0;
$response["message"] = "No Post Available!";
die(json_encode($response));
}
?>

Try this approach:
<?php
$response = array()
try {
//connection
$db = new PDO("mysql:host=$dbhost;dbname=$dbname;", $dbuser, $dbpass);
$db->setAttribute(PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION);
//prepare
$query = "Select * FROM products";
$stmt = $db->prepare($query);
//get resutlt
$result = $stmt->execute();
if ($stmt->rowCount > 0) {
$response["success"] = true;
$response["message"] = "Post Available!";
//populate post array
while($row = $stmt->fetch()){
$response["posts"][] = $row;
}
}else{
$response["success"] = false;
$response["message"] = "No Post Available!";
}
}
catch (PDOException $ex) {
$response["success"] = false;
$response["message"] = "Database Error!";
}
echo json_encode($response);
?>
Prepared statements and stored procedures
using fetch all:
$rows = $stmt->fetchAll();
var_dump($rows);
$response["posts"] = $rows;

Related

Php Webservices: Get Multiple Records from MySQL and encode it in JSON array

I am newbie to PHP webservices using MySQL. I follow this tutorial. I created one table -> loan_applications using phpmyadmin. Currenlty I have 3 records in table related to id 1. I would like to retrive all 3 records and would like to encode it in json.
I tried multiple way and tried googling but unable to get proper json array in response. Here is my get_applications_list.php
<?php
require_once 'include/DB_Functions.php';
$db = new DB_Functions();
// json response array
$response = array();
if (isset($_GET['id'])) {
// receiving the post params
$id = $_GET['id'];
$applications = $db -> getApplicationsList($id);
if ($applications) {
// got applications successfully
$response["status"] = 0;
$response["id"] = $applications["id"];
$response["application_id"] = $applications["application_id"];
$response["requested_amount"] = $applications["requested_amount"];
$response["interest_per_day"] = $applications["interest_per_day"];
$response["gst"] = $applications["gst"];
$response["tenure"] = $applications["tenure"];
$response["processing_fees"] = $applications["processing_fees"];
$response["amount_user_get"] = $applications["amount_user_get"];
$response["amount_user_pay"] = $applications["amount_user_pay"];
$response["application_latitude"] = $applications["application_latitude"];
$response["application_longitude"] = $applications["application_longitude"];
$response["application_status"] = $applications["application_status"];
$response["created_at"] = $applications["created_at"];
$response["updated_at"] = $applications["updated_at"];
$response["message"] = "Applications details fetched successfully";
echo json_encode($response);
} else {
// applications failed to store
$response["status"] = 1;
$response["message"] = "Unknown error occurred in getting details!";
echo json_encode($response);
}
} else {
// receiving the post params
$response["status"] = 2;
$response["message"] = "Required parameters is missing!";
echo json_encode($response);
}
?>
Here is my DB_Functions.php
<?php
class DB_Functions {
private $conn;
// constructor
function __construct() {
require_once 'DB_Connect.php';
// connecting to database
$db = new Db_Connect();
$this->conn = $db->connect();
}
// destructor
function __destruct() {
}
public function getApplicationsList($id){
$stmt = $this->conn->prepare("SELECT * FROM loan_applications WHERE id = ?");
$stmt->bind_param("s", $id);
$stmt->execute();
$applications = $stmt->get_result()->fetch_assoc();
$stmt->close();
if($applications){
return $applications;
}else {
return false;
}
}
}
?>
Here is response which I am getting :
{"status":0,"id":1,"application_id":1,"requested_amount":5000,"interest_per_day":"0.50","gst":18,"tenure":28,"processing_fees":"5.00","amount_user_get":4705,"amount_user_pay":5700,"application_latitude":"9.999999999","application_longitude":"9.999999999","application_status":1,"created_at":"2018-10-10 21:45:17","updated_at":"0000-00-00 00:00:00","message":"Applications details fetched successfully"}
I am getting only one record but i need all 3 record which associated with id 1. I tried lot but unable to get.
So multiple problems here
1 - Although unsure but Currenlty I have 3 records in table related to id 1 seems incorrect statement. If id is primary key, you cannot have 3 records against one id
2 - $stmt->get_result()->fetch_assoc(); will always return one row, to get multiple rows or collection of rows you will need to do it like following
if ($result = $mysqli->query($query)) {
/* fetch associative array */
while ($row = $result->fetch_assoc()) {
printf ("%s (%s)\n", $row["Name"], $row["CountryCode"]);
}
/* free result set */
$result->free();
}
3 - Its quite clear from following code that you are actually sending only one row back
if ($applications) {
// got applications successfully
$response["status"] = 0;
$response["id"] = $applications["id"];
$response["application_id"] = $applications["application_id"];
$response["requested_amount"] = $applications["requested_amount"];
$response["interest_per_day"] = $applications["interest_per_day"];
$response["gst"] = $applications["gst"];
$response["tenure"] = $applications["tenure"];
$response["processing_fees"] = $applications["processing_fees"];
$response["amount_user_get"] = $applications["amount_user_get"];
$response["amount_user_pay"] = $applications["amount_user_pay"];
$response["application_latitude"] = $applications["application_latitude"];
$response["application_longitude"] = $applications["application_longitude"];
$response["application_status"] = $applications["application_status"];
$response["created_at"] = $applications["created_at"];
$response["updated_at"] = $applications["updated_at"];
$response["message"] = "Applications details fetched successfully";
echo json_encode($response);
}
You should do it like this
$applications = getAllApplications(); //returns array of applications
$response['applications'] = $applications; // if they keys you want to send and database fields are same you don't need to set them separately
return json_encode($response);

500 Internal Server Error with PDO connecting to MySQL

I'm connecting to a MySQL database with PHP, and in the beginning I used the mysql_ methods. I then found out that these methods are deprecated, so I've switched to PDO, and am now in the midst of changing my code (and I don't have any experience with PHP PDO). Now I'm getting an error and I (and also my colleague) cannot figure out why I get it, and the code is very straightforward, so I'm not sure..
I have a script that configures connection variables like this:
<?php
define('DB_USER', "user"); // db user
define('DB_PASSWORD', "password"); // db password
define('DB_DATABASE', "myDB"); // database name
define('DB_SERVER', "localhost"); // db server
?>
Then I've defined a class for connecting to the database:
<?php
/**
* A class file to connect to database
*/
class DB_CONNECT {
private $con;
// constructor
function __construct() {
// connecting to database
$this->connect();
}
// destructor
function __destruct() {
// closing db connection
$this->con = null;
}
/**
* Function to connect with database
*/
function connect() {
try {
// import database connection variables
require_once __DIR__ . '/db_config.php';
$this->con = new PDO("mysql:host=".DB_SERVER.";dbname=".DB_DATABASE.";charset=utf8mb4", DB_USER, DB_PASSWORD);
$this->con -> setAttribute(PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION);
return $con;
} catch (PDOException $ex) {
die("Error connecting to DB: ".$ex->getMessage());
}
}
}
?>
Now I'm running this next script, which fetches all items from one table in my database:
<?php
// array for JSON response
$response = array();
// include db connect class
require_once __DIR__ . '/db_connect.php';
// connecting to db
$db = new DB_CONNECT();
// get all products from products table
//$result = mysql_query("SELECT * FROM ITEM") or die(mysql_error());
$query = "SELECT * FROM ITEM";
$stmt = $db->prepare($query); //eror here!
$stmt -> execute();
//foreach($db->query("SELECT * FROM ITEM") as $row) {
// $response["products"] = array();
//}
// check for empty result
if ($stmt->fetchColumn() > 0 ) {
// looping through all results
// products node
$response["products"] = array();
while ($row =$stmt->fetch(PDO::FETCH_ASSOC)) {
// temp user array
$product = array();
$product["name"] = $row["name"];
$product["am"] = $row["am"];
// push single product into final response array
array_push($response["products"], $product);
}
// success
$response["success"] = 1;
// echoing JSON response
echo json_encode($response);
} else {
// no products found
$response["success"] = 0;
$response["message"] = "No products found";
// echo no users JSON
echo json_encode($response);
}
?>
It's this:
$this->$con = new PDO(etc...
^---
$con is undefined in this context, which means you're doing the equivalent of $this->null = new PDO ....
Try $this->con instead. Note the lack of $ on con.

JSON returns all NULL

I am trying to get a JSON from a MySQL database, but it does not recover anything. Here my code:
db_config.php
<?php
/*
* All database connection variables
*/
define('DB_USER', "root"); // db user
define('DB_PASSWORD', ""); // db password (mention your db password here)
define('DB_DATABASE', "biblioapp"); // database name
define('DB_SERVER', "localhost"); // db server
?>
db_connect
<?php
/**
* A class file to connect to database
*/
class DB_CONNECT{
// constructor
function __construct() {
// connecting to database
$this->connect();
}
// destructor
function __destruct() {
// closing db connection
$this->close();
}
/**
* Function to connect with database
*/
function connect() {
// import database connection variables
require_once __DIR__ . '/db_config.php';
// Connecting to mysql database
$con = mysql_connect(DB_SERVER, DB_USER, DB_PASSWORD) or die(mysql_error());
// Selecing database
$db = mysql_select_db(DB_DATABASE) or die(mysql_error()) or die(mysql_error());
// returing connection cursor
return $con;
}
/**
* Function to close db connection
*/
function close() {
// closing db connection
mysql_close();
}
}
?>
get_products_details.php
<?php
$response = array();
// include db connect class
require_once __DIR__ . '/db_connect.php';
// connecting to db
$db = new DB_CONNECT();
// check for post data
$search = '';
if (isset($_POST['search'])){
$search = strtolower($_POST['search']);
// get a product from products table
$result = mysql_query("SELECT * FROM registres WHERE titol LIKE '%".$search."%' OR autor LIKE '%".$search."%'");
if (!empty($result)) {
// check for empty result
if (mysql_num_rows($result) > 0) {
$result = mysql_fetch_array($result);
$product = array();
$product["id"] = $result["id"];
$product["titol"] = $result["titol"];
$product["autor"] = $result["autor"];
$product["descripcion"] = $result["descripcion"];
// success
$response["success"] = 1;
// user node
$response["product"] = array();
array_push($response["product"], $product);
// echoing JSON response
echo json_encode($response);
} else {
// no product found
$response["success"] = 0;
$response["message"] = "No product found";
// echo no users JSON
echo json_encode($response);
}
} else {
// no product found
$response["success"] = 0;
$response["message"] = "No product found";
// echo no users JSON
echo json_encode($response);
}
} else {
// required field is missing
$response["success"] = 0;
$response["message"] = "Required field(s) is missing";
// echoing JSON response
echo json_encode($response);
}
?>
get_all_products.php
<?php
// array for JSON response
$response = array();
// include db connect class
require_once __DIR__ . '/db_connect.php';
// connecting to db
$db = new DB_CONNECT();
// get all products from products table
$result = mysql_query("SELECT *FROM registres") or die(mysql_error());
// check for empty result
if (mysql_num_rows($result) > 0) {
// looping through all results
// products node
$response["registres"] = array();
while ($row = mysql_fetch_array($result)) {
// temp user array
$product = array();
$product["id"] = $result["id"];
$product["titol"] = $result["titol"];
$product["autor"] = $result["autor"];
$product["descripcion"] = $result["descripcion"];
// push single product into final response array
array_push($response["registres"], $product);
}
// success
$response["success"] = 1;
// echoing JSON response
echo json_encode($response);
} else {
// no products found
$response["success"] = 0;
$response["message"] = "No products found";
// echo no users JSON
echo json_encode($response);
}
?>
If I go to localhost/json/get_product_details.php I receive this:
{"success":0,"message":"Required field(s) is missing"}
If i go to localhost/json/get_all_products.php I receive this:
{"registres":[{"id":null,"titol":null,"autor":null,"descripcion":null},{"id":null,"titol":null,"autor":null,"descripcion":null},{"id":null,"titol":null,"autor":null,"descripcion":null},{"id":null,"titol":null,"autor":null,"descripcion":null},{"id":null,"titol":null,"autor":null,"descripcion":null}],"success":1}
What's wrong here? Thanks...
while ($row = mysql_fetch_array($result)) {
$product = array();
$product["id"] = $result["id"];
Your results are not in $result, but in $row :
$product["id"] = $row["id"];
I see nothing common with json in your issue :-)
The only problem you have - empty values in array you've created.
You didn't give us any information about table structure you have, and values you are trying to debug.
So just a quick fix to start better debugging could be:
while ($row = mysql_fetch_array($result, MYSQL_ASSOC)) {
$response["registres"][] = $row;
}
but reviewing your code I want to suggest you to stop using deprecated mysql_ calls. Use mysqli or PDO.

PHP MySQL Select script

I am working on an app that needs to select data from a MySQL database. I am currently testing the PHP script via my browser to make sure that it is returning the correct data. The issue is currently it returns the exception "Database Error!". I have included my PHP script.
get_agencies_by_city.php
<?php
/*
* Following code will get all agencies matching the query
* Returns essential details
* An agency is identified by agency id
*/
require("DB_Link.php");
$city = ($_GET['City']);
//query database for matching agency
$query = "SELECT * FROM agency WHERE City = $city";
//Execute query
try {
$stmt = $db->prepare($query);
$result = $stmt->execute();
}
catch (PDOException $ex) {
$response["success"] = 0;
$response["message"] = "Database Error!";
die(json_encode($response));
}
//Retrieve all found rows and add to array
$rows = $stmt->FETCHALL();
if($rows) {
$response["success"] = 1;
$response["message"] = "Results Available!";
$response["agencys"] = array();
foreach ($rows as $row) {
$agency = array();
$agency["AgencyID"] = $row["AgencyID"];
$agency["AgencyName"] = $row["AgencyName"];
$agency["Address1"] = $row["Address1"];
$agency["City"] = $row["City"];
$agency["State"] = $row["State"];
$agency["Zip"] = $row["Zip"];
$agency["Lat"] = $row["Lat"];
$agency["Lon"] = $row["Lon"];
//update response JSON data
array_push($response["agencys"], $agency);
}
//Echo JSON response
echo json_encode($response);
} else {
$response["success"] = 0;
$response["message"] = "No Agency found!";
die(json_encode($response));
}
?>
Here is the DB_Link.php
<?php
// These variables define the connection information the MySQL database
// set connection...
$options = array(PDO::MYSQL_ATTR_INIT_COMMAND => 'SET NAMES utf8');
try
{
$db = new PDO("mysql:host={$host};dbname={$dbname};charset=utf8", $username, $password, $options);
}
catch(PDOException $ex)
{
die("Failed to connect to the database: " . $ex->getMessage());
}
$db->setAttribute(PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION);
$db->setAttribute(PDO::ATTR_DEFAULT_FETCH_MODE, PDO::FETCH_ASSOC);
if(function_exists('get_magic_quotes_gpc') && get_magic_quotes_gpc())
{
function undo_magic_quotes_gpc(&$array)
{
foreach($array as &$value)
{
if(is_array($value))
{
undo_magic_quotes_gpc($value);
}
else
{
$value = stripslashes($value);
}
}
}
undo_magic_quotes_gpc($_POST);
undo_magic_quotes_gpc($_GET);
undo_magic_quotes_gpc($_COOKIE);
}
header('Content-Type: text/html; charset=utf-8');
session_start();
?>
You should rewrite your query to this, as it is a prepared statement and your query will be much safer (and working)!
//your code
try {
$statement = $dbh->prepare("SELECT * FROM agency WHERE city = :city");
$statement->execute(array('city' => $city));
// rest of your code
}
// and the exception
catch (PDOException $ex) {
//or include your error statement - but echo $ex->getMessage()
die('Error!: ' . json_encode($ex->getMessage()));
}
also you should check if $_GET really is set!
LIKE THIS:
try {
$stmt = $dbh->prepare("SELECT * FROM agency WHERE city = :city");
$stmt->execute(array('city' => $city));
$rows = $stmt->FETCHALL();
if($rows) {
$response["success"] = 1;
$response["message"] = "Results Available!";
$response["agencys"] = array();
foreach ($rows as $row) {
$agency = array();
$agency["AgencyID"] = $row["AgencyID"];
$agency["AgencyName"] = $row["AgencyName"];
$agency["Address1"] = $row["Address1"];
$agency["City"] = $row["City"];
$agency["State"] = $row["State"];
$agency["Zip"] = $row["Zip"];
$agency["Lat"] = $row["Lat"];
$agency["Lon"] = $row["Lon"];
//update response JSON data
array_push($response["agencys"], $agency);
}
//Echo JSON response
echo json_encode($response);
} }
catch (PDOException $ex) {
//or include your error statement - but echo $ex->getMessage()
die('Error!: ' . json_encode($ex->getMessage()));
}
The variable $city needs to be in your query. Do something like this:
$query = "SELECT * FROM Agency WHERE City = " . $city;

Using PHP to query a MDB file, and return JSON

I have a Microsoft Access Database, and I am trying to query the table using PHP, and output valid JSON. I have an equivalent code for a MSSQL database, am I am trying to make my code do the same thing, but just for the Access database.
Here is the MSSQL code
$myServer = "server";
$myDB = "db";
$conn = sqlsrv_connect ($myServer, array('Database'=>$myDB));
$sql = "SELECT *
FROM db.dbo.table";
$data = sqlsrv_query ($conn, $sql);
$result = array();
do {
while ($row = sqlsrv_fetch_array ($data, SQLSRV_FETCH_ASSOC)) {
$result[] = $row;
}
} while (sqlsrv_next_result($data));
$json = json_encode ($result);
sqlsrv_free_stmt ($data);
sqlsrv_close ($conn);
Here is what I tried for the MDB file
$dbName = "/filename.mdb";
if (!file_exists($dbName)) {
die("Could not find database file.");
}
$db = odbc_connect("Driver={Microsoft Access Driver (*.mdb)};Dbq=$dbName", $user, $password);
$sql = "SELECT *
FROM cemetery";
$data = $db->query($sql); // I'm getting an error here
$result = array();
// Not sure what do do for this part...
do {
while ($row = fetch($data, SQLSRV_FETCH_ASSOC)) {
$result[] = $row;
}
} while (sqlsrv_next_result($data));
$json = json_encode ($result);
I kind of followed this to try to connect to the database: http://phpmaster.com/using-an-access-database-with-php/
Currently this is giving me a 500 Internal Server Error. I'm expecting a string such as this to be saved in the variable $json
[
{
"col1":"col value",
"col2":"col value",
"col3":"col value",
},
{
"col1":"col value",
"col2":"col value",
"col3":"col value",
},
{
etc...
}
]
Can someone help me port the MSSQL code I have above so I can use it with an MDB database? Thanks for the help!
EDIT: I'm commenting out the lines one by one, and it throws me the 500 error at the line $data = $db->query($sql);. I looked in the error log, and I'm getting the error Call to a member function query() on a non-object. I already have the line extension=php_pdo_odbc.dll uncommented in my php.ini file. Anyone know what the problem could be?
You only need 1 loop,
fetchAll is your iterable friend:
while ($row = $data->fetchAll(SQLSRV_FETCH_ASSOC)) {
$result[] = $row;
}
odbc_connect doesn't return an object, it returns a resource. see (http://php.net/manual/en/function.odbc-connect.php) so you would need to do something like this.
$db = odbc_connect("Driver={Microsoft Access Driver (*.mdb)};Dbq=$dbName", $user, $password);
$oexec = obdc_exec($db,$sql);
$result[] = odbc_fetch_array($oexec);
and then you can iterate over results..
see also:
http://www.php.net/manual/en/function.odbc-fetch-array.php
http://www.php.net/manual/en/function.odbc-exec.php
I finally figured it out.
<?php
// Location of database. For some reason I could only get it to work in
// the same location as the site. It's probably an easy fix though
$dbName = "dbName.mdb";
$tName = "table";
// Throws an error if the database cannot be found
if (!file_exists($dbName)) {
die("Could not find database file.");
}
// Connects to the database
// Assumes there is no username or password
$conn = odbc_connect("Driver={Microsoft Access Driver (*.mdb)};Dbq=$dbName", '', '');
// This is the query
// You have to have each column you select in the format tableName.[ColumnName]
$sql = "SELECT $tName.[ColumnOne], $tName.[ColumnTwo], etc...
FROM $dbName.$tName";
// Runs the query above in the table
$rs = odbc_exec($conn, $sql);
// This message is displayed if the query has an error in it
if (!$rs) {
exit("There is an error in the SQL!");
}
$data = array();
$i = 0;
// Grabs all the rows, saves it in $data
while( $row = odbc_fetch_array($rs) ) {
$data[$i] = $row;
$i++;
}
odbc_close($conn); // Closes the connection
$json = json_encode($data); // Generates the JSON, saves it in a variable
?>
I use this code to get results from an ODBC query into a JSON array:
$response = null;
$conn = null;
try {
$odbc_name = 'myODBC'; //<-ODBC connectyion name as is in the Windows "Data Sources (ODBC) administrator"
$sql_query = "SELECT * FROM table;";
$conn = odbc_connect($odbc_name, 'user', 'pass');
$result = odbc_exec($conn, $sql_query);
//this will show all results:
//echo odbc_result_all($result);
//this will fetch row by row and allows to change column name, format, etc:
while( $row = odbc_fetch_array($result) ) {
$json['cod_sistema'] = $row['cod_sistema'];
$json['sistema'] = $row['sistema'];
$json['cod_subsistema'] = $row['cod_subsistema'];
$json['sub_sistema'] = $row['sub_sistema'];
$json['cod_funcion'] = $row['cod_funcion'];
$json['funcion'] = $row['funcion'];
$json['func_desc_abrev'] = $row['desc_abreviada'];
$json['cod_tipo_funcion'] = $row['cod_tipo_funcion'];
$response[] = array('funcionalidad' => $json);
}
odbc_free_result($result); //<- Release used resources
} catch (Exception $e) {
$response = array('resultado' => 'err', 'detalle' => $e->getMessage());
echo 'ERROR: ', $e->getMessage(), "\n";
}
odbc_close($conn);
return $response;
And finnally encoding the response in JSON format:
echo json_encode($response);

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