Error: Unknown column 'x' in 'field list' - php

Question

I'm having some trouble inputting some data into a table.
I'm retrieving some values from a form and inputting them to a table, but this error shows up every time:
Error: Unknown column 'planner_id' in 'field list'
<?php
session_start();
include 'conexion_data.php';
if (mysqli_connect_errno()) {
echo "Failed to connect to MySQL: " . mysqli_connect_error();
}
$teacherid = $_POST["teacherid"];
$plannerid = $_POST["plannerid"];
$yeargroup = $_POST["yeargroup"];
$subject = $_POST["subject"];
$planner_event = htmlspecialchars($_POST["event_comment"]);
$event_date = $_POST["event_date"];
echo "$teacherid $plannerid $yeargroup $planner_event $event_date <br/><br />";
if (empty($event_date) or empty($planner_event)) {
echo "One of the fields was left blank! <br />";
} else {
$sql = "INSERT INTO subject_directorio (planner_id, teacher_id, subject, yeargroup, date, comment ) VALUES ('$plannerid', '$teacherid', '$subject', '$yeargroup', '$event_date', '$planner_event')";
if (!mysqli_query($con,$sql)) {
die('Error: ' . mysqli_error($con));
} else {
/* header('Location: user_area.php'); */
echo "Data was inputed to DB";
mysqli_close($con);
}
}
?>

Answer 1

It's very straight
while you are getting this type error :{Error: Unknown column 'planner_id' in 'field list'}
Troubleshoot first step will be Just Describe The Table [subject_directorio]
Desc subject_directorio and check planner_id is exist or not. According to to the error
subject_directorio not holding any column called as planner_id
Hope it helps!!

Answer 2

It's self explanatory that your table doesn't have a column planner_id. Even if you see that it has, you may have trialing spaces before or after planner_id in the column name. Check carefully.

Answer 3

Database
You are using wrong way how to connect to database and fetch its data.
Because you database may be hacked using SQL Injection
The right way how to do this is:
Using PDO
$conn = new PDO('mysql:host=localhost;dbname=myDatabase', $username, $password);
For error catching:
try {
$conn = new PDO('mysql:host=localhost;dbname=myDatabase', $username, $password);
$conn->setAttribute(PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION);
} catch(PDOException $e) {
echo 'ERROR: ' . $e->getMessage();
}
And data fetching:
$id = 5;
try {
$conn = new PDO('mysql:host=localhost;dbname=myDatabase', $username, $password);
$conn->setAttribute(PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION);
$stmt = $conn->prepare('SELECT * FROM myTable WHERE id = :id');
$stmt->execute(array('id' => $id));
while($row = $stmt->fetch()) {
print_r($row);
}
} catch(PDOException $e) {
echo 'ERROR: ' . $e->getMessage();
}
Using Mysqli
$stmt = $dbConnection->prepare('SELECT * FROM employees WHERE name = ?');
$stmt->bind_param('s', $name);
$stmt->execute();
$result = $stmt->get_result();
while ($row = $result->fetch_assoc()) {
// do something with $row
}
And your problem
I think problem is in your query and binding params to it.So try to use proper way as I shown you, and then show us results.
SQLFiddle