SQLSRV query to array - php

Question

I try to query a SQL database and save data into a custom array, but the array always repeats last row*num rows on database.
php:
class Cst
{
public $ParagemID;
public $Designacao;
public $DecimalDeGrauY;
public $DecimalDeGrauX;
}
require 'config.php';
$dsn = array( "Database"=>"$database", "UID"=>"$username", "PWD"=>"$password", "LoginTimeout"=> 60);
$db = sqlsrv_connect($server, $dsn);
$sql = "SELECT ParagemID, Designacao, DecimalDeGrauY, DecimalDeGrauX FROM adoParagens WHERE ParagemID >= 20000";
$stmt = sqlsrv_query($db, $sql);
$locations = new Cst();
$location=array();
$i=0;
while( $row = sqlsrv_fetch_object($stmt))
{
$locations->ParagemID = $row->ParagemID;
$locations->Designacao = $row->Designacao;
$locations->DecimalDeGrauY = $row->DecimalDeGrauY;
$locations->DecimalDeGrauX = $row->DecimalDeGrauX;
//echo json_encode($locations);
$location[$i]= $locations;
$i++;
}
echo json_encode($location);

Answer 1

It looks like you're always working with same instance of that object. Updating it for each row will also update all copies of it, as they are in fact the same object.
Try this instead.
...
$location = array();
while( $row = sqlsrv_fetch_object($stmt) )
{
$data = array();
$data['ParagemID'] = $row->ParagemID;
$data['Designacao'] = $row->Designacao;
$data['DecimalDeGrauY'] = $row->DecimalDeGrauY;
$data['DecimalDeGrauX'] = $row->DecimalDeGrauX;
$location[]= $data;
}
...

Answer 2

try using a 2 dimensional array.
$i=0;
while( $row = sqlsrv_fetch_object($stmt))
{
$location[$i][$locations->ParagemID/*put your val*/] = $row->ParagemID;
$location[$i][$locations->Designacao/*put your val*/] = $row->Designacao;
$location[$i][$locations->DecimalDeGrauY/*put your val*/] = $row->DecimalDeGrauY;
$location[$i][$locations->DecimalDeGrauX/*put your val*/] = $row->DecimalDeGrauX;
//echo json_encode($locations);
$i++;
}