Get data except for data in a column - php

Question

So I have the following code:
require_once('db.php');
$getUsers = mysqli_query($db, 'SELECT * FROM users');
$rows = [];
while ($r = mysqli_fetch_assoc($getUsers)) {
$rows[] = $r;
$getSkills = mysqli_query($db, "SELECT * FROM skills WHERE id = '" . $r['id'] . "'");
while($r = mysqli_fetch_assoc($getSkills)) {
$rows['skills'] = $r;
}
}
print(json_encode($rows));
Which outputs:
[{"id":"1","name":"user1","skills":{"woodcutting":"6","mining":"10"}},{"id":"2","name":user2"}]
There are two problems:
I'd like to get all of the data in the table skills EXCEPT for the id, or at-least cut it off before encoding it with json.
For some reason I can't get the "skills" shown after the first user. user2 should also have a skills object.
What am I doing wrong?

Answer 1

To get all the columns except the id from table skills, you can either list all the columns that you want to select, like this:
mysqli_query($db, "SELECT column1, column2, another_column FROM `skills` WHERE id = '" . $r['id'] . "'");
Or, you can SELECT everything and use unset() to weed out the id column before json-encoding:
$getSkills = mysqli_query($db, "SELECT * FROM skills WHERE id = '" . $r['id'] . "'");
while ($r = mysqli_fetch_assoc($getSkills))
{
unset($r['id']);
// whatever it is that you want to do.
}
The skills are not shown except for the last user (?) because you are re-assigning it in every iteration of the while loop. Here is something you can do instead:
require_once('db.php');
$getUsers = mysqli_query($db, 'SELECT * FROM users');
$rows = array();
while ($r = mysqli_fetch_assoc($getUsers))
{
$skills = array();
$tempRow = $r;
$getSkills = mysqli_query($db, "SELECT * FROM skills WHERE id = '" . $r['id'] . "'");
while ($r = mysqli_fetch_assoc($getSkills))
{
unset($r['id']); // since you don't want the `id`.
$skills[] = $r;
}
$tempRow['skills'] = $skills;
$rows[] = $tempRow;
}
print(json_encode($rows));
Hope that helps :)

Answer 2

It looks like you need something similar to this:
while($r = mysqli_fetch_assoc($getSkills)) {
unset($r['id']);
$rows['skills'] = $r;
}

Answer 3

Point-1: Unset id like unset($r['id']) to remove from array() $r. Before unsset id keep id to a variable because you used it for next query.
Point-2: May be there is no data exist in skills those IDs. As a result you did not get skills. Suggest you to query by those IDs whether any data exist or not in skills table.
while ($r = mysqli_fetch_assoc($getUsers)) {
$id = $r['id'];
unset($r['id']);
$rows[] = $r;
$getSkills = mysqli_query($db, "SELECT * FROM skills WHERE id = '$id'");
while($r = mysqli_fetch_assoc($getSkills)) {
$rows['skills'] = $r;
}
}