why does foreach skip 2 rows from the query result? - php

Question

For 10 rows in the query it only returns 8 rows but i get the fields right:
For Query data which returns less than 2 rows I get an error.
//create table to display all data
echo "<table border="1"> ";
echo "<tr>";
$row = mysqli_fetch_assoc($result);
foreach($row as $key => $value)
{
echo "<th>$key</th>";
}
echo "</tr>";
while (($row = $result->fetch_assoc()) !== null)
{
$output = array();
$i=1;
echo "<tr>";
foreach ($row as $columnName => $columnValue)
{
$output[] = $columnName."=>". $columnValue;
echo "<td>".$columnValue."</td>";
}
echo "</tr>";
}
echo "</table>";

Answer 1

Edit: Thanks to #Michael Berkowski for his comments on the question.
Here is a modified version of your code that should work:
//create table to display all data
echo "<table border=1 >";
echo "<tr>";
//echo "<th> ## </th>";
$row = $result->fetch_assoc(); // stick to the object-oriented form. It is cleaner.
foreach ($row as $key => $value)
{
echo "<th>$key</th>";
}
echo "</tr>";
do
{
$output = array();
echo "<tr>";
foreach ($row as $columnName => $columnValue)
{
$output[$columnName] = $columnValue; // this is neater.
echo "<td>" . $columnValue . "</td>";
}
echo "</tr>";
} while ($row = $result->fetch_assoc());
echo "</table>";
You can use your first foreach() loop to print the keys and then use a do-while() loop to get your desired output.
Additional reading:
PHP do-while loop

Answer 2

You need to use
mysqli_fetch_assoc($result);