This is my question below when use codeigniter:
1: query id from DB
2: loop to call my function
public function create_all_static_page(){
$sql = "select id from information where is_static = 0";
$arr = $this->db->query($sql)->result_array();
foreach($arr as $r){
$this->create_static_temp_page($r['id']);
echo $r['id'];
}
}
private function create_static_temp_page($id){
//...another code
$html = $this->load->view('push_db_template_page', $data,true);
$html = addslashes($html);
$info['id'] = $id;
$info['static_content'] = $html;
if($this->db->replace('static_page',$info)){
$sql = "update information set is_static = 1 where id = {$id}";
$this->db->query($sql);
}
}
I have found,it loops just once. That is to say, if I output $r['id'] after $this->create_static_temp_page(); just outputs the first id and the foreach loop has been stopped, but I never use 'return' or 'exit' in my code.
Is there anything wrong with $this->load->view()?
Related
I try to insert result of query into some file.
The file is created but it contain nothing.
I check the query result and its working, i receive a result data.
here is my controller code :
$members_nik = array();
$members_nik = select_config_by('member', 'member_nik', 'WHERE 1=1');
file_put_contents("data.txt", implode(', ', $members_nik));
here is my function code :
function select_config_by($table, $obj, $where){
$query = mysql_query("SELECT $obj as result FROM $table $where");
$row = mysql_fetch_array($query);
$result = $row['result'];
return $result;}
You are returing a string from the select_config_by function but then trying to implode it as if it were an array.
Now assuming you want to return all the results and save them in your data.txt, change the function to this:
function select_config_by($table, $obj, $where)
{
$result = mysql_query("SELECT $obj as result FROM $table $where");
$temp = array();
while ($row = mysql_fetch_array($result))
{
$temp[] = $row['result'];
}
return $temp;
}
So I have my code
function GetApi($connection,$UserId){
global $Apicall;
$Apicall = array();
$Apiidquery = mysqli_query($connection, "SELECT ID FROM ` Characterapi` WHERE UserId = '$UserId'");
while($results = mysqli_fetch_assoc($Apiidquery)){
$Apicall[] = $results['ID'];
}
}
The output of this function if I call
$Apicall[0] = 3
$Apicall[1] = 11
and this is the information I want. But now I want to use a function like
function Keyquery($Apicall,$connection ){
global $keyidcall, $keyid ,$Vcode;
$Keyidquery = array();
$Keyidquery = mysqli_query($connection, "SELECT keyid, Vcode FROM `Characterapi` WHERE ID = '$Apicall'");
$results = mysqli_fetch_object($Keyidquery);
$keyid = $results->keyid;
$Vcode = $results->Vcode;
}
This code does run if i set $Apicall ="3"; The issue im having is that I want the first function to get All the IDs associated with $userId in my data base then for each Id run the second function to to get the two specific pieces of information from that query.
In response to the comment below, this is the solution which I would use. However you should be wary of using this method as it does not parameterize the values, and as such not sanitized.
<?php
function Keyquery($Apicall,$connection ){
global $keyidcall, $keyid ,$Vcode;
$string = "ID IN('";
$string.= implode("','", $Apicall);
$string.="')";
$Keyidquery = mysqli_query($connection, "SELECT keyid, Vcode FROM `Characterapi` WHERE ".$string.";");
$results = mysqli_fetch_object($Keyidquery);
$keyid = $results->keyid;
$Vcode = $results->Vcode;
}
?>
Consider this (simplified) code... Function getLevelOne is called, runs fine, calls getLevelTwo, runs fine, and then stops, without continuing the while that was called in getLevelOne... The way its written, you'd assume that the second function would be called for each number in $list1 (2,4,5,6)... Am I missing something?
$list1 = "2,4,5,6";
$table1 = 'thistable';
getLevelOne($list1, $table1);
function getLevelOne($list1, $table1){
$q = "select * from $table1 where id IN ('$list1')";
$r = mysqli_query($db, $q);
while($row = mysqli_fetch_array($r)){
echo 'oh';
$table2 = 'nexttable';
$list2 = $row[$table2];
getLevelTwo($list2, $table2);
}
}
function getLevelTwo($list2, $table2){
$q2 = "select * from $table2 where id IN ('$list2')";
$r2 = mysqli_query($db, $q2);
while($row2 = mysqli_fetch_array($r2)){
echo 'shit';
}
}
The first question is how to run a function using the URL, I have the following function:
function do_curl($start_index,$stop_index){
// Do query here to get all pages with ids between start index and stop index
$query = "SELECT * FROM xxx WHERE xxx >= $start_index and xxx <= $stop_index";
Now when I'm trying to do curl.php?start_index=0&stop_index=2 this is not working but when i delete the function and WHERE idnum = 1 it is working.
Now the second question is how 'compile' all the fields from the rows to arrays? I have the current code:
$query = "SELECT * FROM fanpages";
$result = mysql_query($query) or die(mysql_error());
while ($row = mysql_fetch_array($result))
{
$fanpages_query = '\'http://graph.facebook.com/'.$row['page_id'].'\', ';
echo $fanpages_query;
}
$fanpages = array($fanpages_query);
$fanpages_count = count($fanpages);
echo $fanpages_count;
echo $fanpages_query; returning
'http://graph.facebook.com/AAAAAA', 'http://graph.facebook.com/BBBBBBB', 'http://graph.facebook.com/CCCCCCCC',
(I don't have an idea how to do it in a different way, also when im doing it in such a way i can't delete the final comma which will return PHP-error.)
echo $fanpages_count; returns 1 and like you can see i have 3 there.
Thanks in advance guys!
Do a function call to do the query
function do_curl($start_index, $stop_index){
...
}
$fanpages = do_curl($_GET['start_index'], $_GET['stop_index']);
For your second question, you can use arrays and the implode function to insert commas:
while ($row = mysql_fetch_array($result))
{
$fanpages_query[] = 'http://graph.facebook.com/'.$row['page_id'];
}
return $fanpages_query;
Then use implode to print them out:
echo implode(',', $fanpages);
The whole code:
function do_curl($start_index = 0, $stop_index = null) {
$queryIfThereIsNoStartIndex = '';
$queryIFThereIsNoStopIndex = '';
$queryIfBothStartAndStopIndexAreMissing = '';
$result = mysql_query($query) or die(mysql_error());
while ($row = mysql_fetch_array($result))
{
$fanpages_query[] = 'http://graph.facebook.com/'.$row['page_id'];
}
return $fanpages_query;
}
$fanpages = do_curl($_GET['start_index'], $_GET['stop_index']);
$fanpages_count = count($fanpages);
echo implode(',', $fanpages);
And you should totally use mysql_escape_string for escaping the values you add to the query.
$qVraagGroepenOp = "SELECT * FROM $tabele WHERE $where";
$rVraagGroepenOp = mysql_query ( $qVraagGroepenOp );
$aVraagGroepenOp = mysql_fetch_assoc ( $rVraagGroepenOp )
and I converted that to a function
vraagOp("testtable","testtable_ID = $id");
function vraagOp($table,$where)
{
$qVraagOp = "SELECT * FROM $table WHERE $where";
$rVraagOp = mysql_query( $qVraagOp );
$aVraagOp = mysql_fetch_assoc( $rVraagOp );
return $aVraagOp;
}
only the problem is when i need more then one row i need to use a while loop
$qVraagGroepenOp = "SELECT * FROM testtable where testtype = test";
$rVraagGroepenOp = mysql_query ( $qVraagGroepenOp );
while ( $aVraagGroepenOp = mysql_fetch_assoc ( $rVraagGroepenOp ) )
{
echo "testing <br>";
}
It wont work anymore is there a trick to make my function work with this while loop?
This won't work but I want to reach to something like it
while (vraagOp("testtable","testtype = test"))
{
echo "testing <br>";
}
Is this possible?
This could be done with static variables in the function scope.
function vraagOp($table,$where)
{
static $rVraagOp;
if(!$rVraagOp){
$qVraagOp = "SELECT * FROM $table WHERE $where";
$rVraagOp = mysql_query( $qVraagOp );
}
return mysql_fetch_assoc( $rVraagOp );
}
That should do what you're after.
This function returns an array of rows - it's a generic pattern yu can use almost anywhere you get multiple rows from a query.
function vraagOp($table,$where)
{
$sql= "SELECT * FROM $table WHERE $where";
$query= mysql_query($sql);
if ($query != false)
{
$result = array();
while ( $row = mysql_fetch_assoc($query) )
$result[] = $row;
return $result;
}
return $false;
}
//usage
$rows = vraagOp($table,$where);
if ($rows)
{
foreach ($rows as $row)
use($row);
}
This function will 'cache' the mysql result resource from each unique $table/$where combination, and fetch the next result from it on each subsequent call. It will return an associative array for each row, or false when there are no rows left.
function vraagOp($table, $where)
{
// Holds our mysql resources in a map of "{$table}_{$where}" => resource
static $results = array();
$key = $table . '_' . $where;
if (!isset($results[$key]))
{
// first call of this particular table/where
$results[$key] = mysql_query("SELECT * FROM $table WHERE $where");
}
$row = mysql_fetch_assoc($results[$key]);
if ($row === false)
// remove this key so a subsequent call will start over with a new query
unset($results[$key]);
return $row;
}
// Usage
while ($row = vraagOp("table1", "where field > 7")) {
print_r($row);
}
This
while (vraagOp("testtable","testtype = test"))
{
echo "testing <br>";
}
will work if you change VraagOp() to return false when no matching record was found.
You would have to move the mysql_query() part out of VraagOp(), and just leave the mysql_fetch_assoc part in.
However, I can't really see what benefit there would be? You would just be building a (unnecessary) wrapper around mysql_fetch_assoc(), wouldn't you?
You'll need to turn vraagOp() into an iterator and then use foreach() in order to make this work.
Your example won’t work because the condition is executed on every iteration. That means vraagOp("testtable","testtype = test") would be called with each iteration until it returns a falsely value. mysql_fetch_assoc does that but your function doesn’t.
How can we call function inside while loop example is below :
$sql_gpfsF="SELECT * FROM emp_salary";
$result_gpfsF=mysql_query($sql_gpfsF);
while($row_gpfsF=mysql_fetch_assoc($result_gpfsF))
{
call_function();
}
function call_function()
{
echo " Function Called </ br>";
}