Multiple MySQL rows with one form - php

Question

I have a form that I would like to create up to 9 different MySQL rows with one process. The code I have as of right now doesn't throw any errors, but also does not insert any information into the database.
$id = '';
$rid = $_POST['rid'];
$desc = $_POST['desc'];
$ename = $_POST['ename'];
if ($stmt = $mysqli->prepare("INSERT INTO event(id, rid, desc, ename) VALUES (?, ?, ?, ?)")) {
$stmt->bind_param("isss", $id, $rid, $desc, $ename);
for ($i = 1; $i < 10; $i++) {
$rid = $_POST['rid' . $i];
$desc = $_POST['desc' . $i];
$ename = $_POST['ename' . $i];
$stmt->execute();
}
include ("./html/schedule2.htm");
} else {
printf("Errormessage: %s\n", $mysqli->error);
}
I have edited the code to follow the comment instructions but still get an error that is very vague. Not sure what is going on...

Answer 1

The comments have pointed out that you should prepare/execute this. This is what it should look like.
$id = '';
$rid = $_POST['rid1'];
$desc = $_POST['desc1'];
$ename = $_POST['ename1'];
$stmt = $mysqli->prepare("INSERT INTO `event`(`id`, `rid`, `desc`, `ename`) VALUES (?, ?, ?, ?)");
$stmt->bind_param("ssss", $id, $rid, $desc, $ename);
$stmt->execute();
for ($i = 2; $i < 10; $i++) {
$rid = $_POST['rid' . $i];
$desc = $_POST['desc' . $i];
$ename = $_POST['ename' . $i];
$stmt->execute();
}
Also, I'd recommend using an array for your form elements. Like:
<input type="text" name="desc[]">