Why does array_diff_uassoc compares keys whose value do not match - php

Question

I just read that question about strange php behaviour, and even though I could research a bit more, I'm nowhere near understanding it.
I assume the reader has read the original question and is aware of OP's code block and sample, but in short, OP is trying to compare those two arrays, and while the result is good, the compare function seems to be called erratically:
$chomik = new chomik('a');
$a = array(5, $chomik, $chomik, $chomik);
$b = array($chomik, 'b', 'c', 'd');
array_diff_uassoc($a, $b, 'compare');
The documentation is a bit obscure... but it does state that:
The comparison function must return an integer less than, equal to, or greater than zero if the first argument is considered to be respectively less than, equal to, or greater than the second.
As I understand it, that means that the compare() function should be more like this:
function compare($a, $b) {
echo("$a : $b<br/>");
if($a === $b) return 0;
else if ($a > $b) return 1;
else return -1;
}
however this still gives very strange results, with even more "duplicates"
1 : 0
1 : 2
3 : 1
2 : 1
3 : 2
1 : 0
1 : 2
3 : 1
2 : 1
3 : 2
0 : 0
1 : 0
1 : 1
2 : 0
2 : 1
2 : 2
3 : 0
3 : 1
3 : 2
3 : 3
faced with many doubts, I read the compat php function, and the part where the check actually happens is interesting:
foreach ($args[0] as $k => $v) {
for ($i = 1; $i < $array_count; $i++) {
foreach ($args[$i] as $kk => $vv) {
if ($v == $vv) { // compare keys only if value are the same
$compare = call_user_func_array($compare_func, array($k, $kk));
if ($compare == 0) {
continue 3; // value should not be added to the result
}
}
}
}
$result[$k] = $v;
}
here's the actual source (per comment)
The way this code executes the compare function should not be outputting the result we see. Foreach is not able to move back and forth in the keys (AFAIK???), as seems to be the case in the order of the first key here:
1 : 2
3 : 1
2 : 1
moreover, it shouldn't check the keys if the value do not match, so why do all these are checked:
1 : 2
3 : 1
2 : 1
3 : 2
etc...
How can the topmost foreach() in the source code loop back and forth through the keys?!
Why are keys whose values do not match still compared?
Do foreach loops actually continue executing even when they've been continued?
Is this an example of concurrency? can call_user_func_array somehow be launched and actually execute the echo("$a : $b<br/>"); of the compare function not in the same order they were "launched"??

Answer 1

I believe you've pinpointed a bug, my friend. I just ran the code in the question you referenced, and sure enough, it compared keys for values that weren't the same. However, I wanted to test if the source code itself contained the mistake, so I added the official source for array_diff_uassoc this to the top his code, inside my own namespace:
<?php
namespace mine;
// Code obtained from https://pear.php.net/reference/PHP_Compat-latest/__filesource/fsource_PHP_Compat__PHP_Compat-1.6.0a3CompatFunctionarray_diff_uassoc.php.html
function array_diff_uassoc()
{
// Sanity check
$args = func_get_args();
if (count($args) < 3) {
user_error('Wrong parameter count for array_diff_uassoc()', E_USER_WARNING);
return;
}
// Get compare function
$compare_func = array_pop($args);
if (!is_callable($compare_func)) {
if (is_array($compare_func)) {
$compare_func = $compare_func[0] . '::' . $compare_func[1];
}
user_error('array_diff_uassoc() Not a valid callback ' .
$compare_func, E_USER_WARNING);
return;
}
// Check arrays
$array_count = count($args);
for ($i = 0; $i !== $array_count; $i++) {
if (!is_array($args[$i])) {
user_error('array_diff_uassoc() Argument #' .
($i + 1) . ' is not an array', E_USER_WARNING);
return;
}
}
// Compare entries
$result = array();
foreach ($args[0] as $k => $v) {
for ($i = 1; $i < $array_count; $i++) {
foreach ($args[$i] as $kk => $vv) {
if ($v == $vv) {
// echo ("$v\n");
// echo ("$vv\n");
// echo ("$k\n");
// echo ("$kk\n");
// die();
$compare = call_user_func_array($compare_func, array($k, $kk));
if ($compare == 0) {
continue 3;
}
}
}
}
$result[$k] = $v;
}
return $result;
}
class chomik {
public $state = 'normal';
public $name = 'no name';
public function __construct($name) {
$this->name = $name;
}
public function __toString() {
return $this->name . " - " . $this->state;
}
}
function compare($a, $b) {
echo("$a : $b\n");
if($a != $b) {
return 0;
}
else return 1;
}
$chomik = new chomik('a');
$a = array(5, $chomik, $chomik, $chomik);
$b = array($chomik, 'b', 'c', 'd');
array_diff_uassoc($a, $b, 'mine\compare');
This time, it only compared keys for values that were equal:
1 : 0
2 : 0
3 : 0
Strange, huh?

Answer 2

From this comment by powerlord:
Judging from the fact that the custom compare function asks you to return -1; 0; or 1, it seems like its doing a sort either before or at the same time as a comparison between the two arrays.
I was encouraged to go and read the actual php_array_diff() source, the registered function for array_diff_uassoc(), and discovered it uses the compare function a lot of times, which I wrongly interpreted as foreach going back and forth through the keys.
How can the topmost foreach() in the source code loop back and forth through the keys?!
it doesn't. It's just that the user-supplied function
diff_data_compare_func = php_array_user_compare;
is used multiple times to sort and evaluate the data.
[...]
zend_sort((void *) lists[i], hash->nNumOfElements,
sizeof(Bucket), diff_data_compare_func, (swap_func_t)zend_hash_bucket_swap);
[...]
while (Z_TYPE(ptrs[i]->val) != IS_UNDEF && (0 < (c = diff_data_compare_func(ptrs[0], ptrs[i])))) {
[...]
if (diff_data_compare_func(ptrs[0], ptr) != 0) {
[...]
Why are keys whose values do not match still compared?
It is true the compat pear code posted in the question hints that if the valus do not match, the compare function should not even be run, but php_array_diff() acts differently.
Do foreach loops actually continue executing even when they've been continued?
Is this an example of concurrency?
Nonsense. If I were you, I'd edit that out.