How can I remove the texts in a sentence after the second comma but do nothing if it has no two commas in a sentence?
I tried the following:
substr($str, 0, strpos($str, ',', strpos($str, ',')+1))
But the problem here is if I don't have two commas in this $str, the funtion outputs nothing, I'm getting a blank area.
Is there anyway to check the existence of two commas and remove text after the second comma or do nothing otherwise.
Try this:
$commasCount = count(explode(',', $str));
if ($commasCount > 2) {
$str = substr($str, 0, strpos($str, ',', strpos($str, ',')+1));
}
A more elegant approach, without using string functions and reusing the array as we need it to count the number of commas anyway (and avoiding regex madness for readability):
$text_segments = explode(',', $str);
if( count($text_segments) > 2 ) {
$str = $text_segments[0] . ',' . $text_segments[1];
}
Just check the # of occurrences first:
if (substr_count($str, ',') >= 2)
substr($str, 0, strpos($str, ',', strpos($str, ',')+1));
Or you could do it with preg_match() but it would be slower:
if (preg_match('/([^,]*,){2}/', $str, $match))
$str = $match[1];
Or in a single step (ala adeneo above, but altered to fit the instructions)
$str = preg_replace('/((?:[^,]*,){2})?(?:.*)$/', '$1', $str);
You'll notice the initial characters with comma at the end are made optional by the question-mark at the end of (...)? so it will get the correct value regardless.
Assuming that you want to remove the second comma and all subsequent characters (because of your selected answer), using regex is very concise and direct and can be written without any pre-checking and conditions.
Match the first the first occurring comma, match one or more non-comma characters, then forget those characters with \K, then explicitly match the second comma and all remaining characters -- to be replaced with an empty string.
Code: (Demo)
$str = "a,b,c,d";
var_export(
preg_replace("/,[^,]+\K,.*/", '', $str)
);
Related
I need to know how to do this reliably with the least amount of calls.
I have a string and I need to remove the 8th character from it. It doesn't matter what the char is, I just need to remove ONLY the 8th char.
I came up with this but a little too unwieldy for me.
// 12345678901234567890
$str = '5NMSG3AB1AH353158';
// after removing char, result should be:
// 5NMSG3A1AH353158
$r = str_split($str);
unset($r[7]);
echo join('', $r);
Possibly Regex?
Here are some solutions:
$str = substr($str, 0, 7) . substr($str, 8);
$str = substr_replace($str, '', 7, 1);
$str = preg_replace('/(.{7})./', '$1', $str, 1);
$str = preg_replace('/.{7}\K./', '', $str, 1);
I'd go for substr() or better substr_replace() as this will certainly be fastest and most easy to read.
substr_replace makes this very simple.
$string = substr_replace($string, '', 7, 1);
It can also take an array of strings as its first parameter, and do the same replacement in all of them, which can be pretty handy.
Like this
$str = '5NMSG3AB1AH353158';
echo preg_replace('/^(.{7})./', '\1', $str);
Output:
5NMSG3A1AH353158
Sandbox
Explanation
^ start of string
(...) capture
. match any
{7} seven times
. match any one time
Then the replacement
\1 first capture group
Basically capture the first 7 chars, then match the 8th, and replace that with the captured 7 chars. Which effectively removes the 8th.
UPDATE
here is another way I like (I haven't used that function sense college, I think):
$s = '5NMSG3A1AH353158';
echo substr_replace($s,'',7,1); //strings are 0 based
sandbox
substr_replace() replaces a copy of string delimited by the start and (optionally) length parameters with the string given in replacement.
mixed substr_replace( mixed $string, mixed $replacement, mixed $start [, mixed $length ] )
http://php.net/manual/en/function.substr-replace.php
Simple.
I am trying to something like this.
Hiding users except for first 3 characters.
EX)
apple -> app**
google -> goo***
abc12345 ->abc*****
I am currently using php like this:
$string = "abcd1234";
$regex = '/(?<=^(.{3}))(.*)$/';
$replacement = '*';
$changed = preg_replace($regex,$replacement,$string);
echo $changed;
and the result be like:
abc*
But I want to make a replacement to every single character except for first 3 - like:
abc*****
How should I do?
Don't use regex, use substr_replace:
$var = "abcdef";
$charToKeep = 3;
echo strlen($var) > $charToKeep ? substr_replace($var, str_repeat ( '*' , strlen($var) - $charToKeep), $charToKeep) : $var;
Keep in mind that regex are good for matching patterns in string, but there is a lot of functions already designed for string manipulation.
Will output:
abc***
Try this function. You can specify how much chars should be visible and which character should be used as mask:
$string = "abcd1234";
echo hideCharacters($string, 3, "*");
function hideCharacters($string, $visibleCharactersCount, $mask)
{
if(strlen($string) < $visibleCharactersCount)
return $string;
$part = substr($string, 0, $visibleCharactersCount);
return str_pad($part, strlen($string), $mask, STR_PAD_RIGHT);
}
Output:
abc*****
Your regex matches all symbols after the first 3, thus, you replace them with a one hard-coded *.
You can use
'~(^.{3}|(?!^)\G)\K.~'
And replace with *. See the regex demo
This regex matches the first 3 characters (with ^.{3}) or the end of the previous successful match or start of the string (with (?!^)\G), and then omits the characters matched from the match value (with \K) and matches any character but a newline with ..
See IDEONE demo
$re = '~(^.{3}|(?!^)\G)\K.~';
$strs = array("aa","apple", "google", "abc12345", "asdddd");
foreach ($strs as $s) {
$result = preg_replace($re, "*", $s);
echo $result . PHP_EOL;
}
Another possible solution is to concatenate the first three characters with a string of * repeated the correct number of times:
$text = substr($string, 0, 3).str_repeat('*', max(0, strlen($string) - 3));
The usage of max() is needed to avoid str_repeat() issue a warning when it receives a negative argument. This situation happens when the length of $string is less than 3.
I am running into a problem trying to do a replacement on a few strings. Essentially what I have is a bunch of prices on my page that look like
RMB148.00
What i am trying to do is run a replace on only the last 2 numbers so i can do something like
RMB14800
Preg replace works fine for the RMB part because it is always there.
My problem is the last two numbers can be anything it all depends on the price so I cant just remove and replace, I need to just wrap HTML <sup> tags around them.
$string = $product['price'];
$string = preg_replace('/[\x00-\x1F\x80-\xFF]/', '', $string);
echo preg_replace('/RMB/', '<sup class="currency-sym">RMB</sup>', $string, 1);
Assuming the last two characters are digits, you could just
$string=preg_replace('/(\d\d)$/', '<sup class="currency-sym">\1</sup>', $string);
If not,
$string=preg_replace('/(..)$/', '<sup class="currency-sym">\1</sup>', $string);
should do the trick.
Alternativly use
$string=substr($string,0,-2).'<sup class="currency-sym">'.substr($string,-2).'</sup>';
Here is a regex solution that looks for the final digit notation at the end of your string.
$string = 'RMB148.00';
$string = preg_replace('/(\d+)\.(\d{2})\z/','$1<sup>$2</sup>',$string);
echo $string;
You could use the following with the explode () function
$string = explode ('.', $product['price']);
$new_string = $string[0].'<sup>'. $string [1]. '</sup>';
And do the regex for the RMB the same way.
Code.
<?php
$string = '14842.00';
$string = substr($string, 0, strlen($string) - 2) . '<sup>' . substr($string, strlen($string) - 2, 2) . '</sup>';
echo $string;
Try online sandbox.
Explanation.
substr($s, $i, $l) gets $l symbols of $s, started from $i index (indexes starts from zero).
So first substr($string, 0, strlen($string) - 2) gets all string except last two symbols.
Second substr($string, strlen($string) - 2, 2) gets only last two symbols.
More about substr.
You should use a pattern matching regex. Note the $1 in the replacement argument matches (\d{2}) in the pattern argument. preg_replace() only replaces the matched pattern. This pattern matches . followed by any two digits. Since . is not included in the replacement argument it does not show up in your $string.
$string = preg_replace('/\.(\d{2})$/', '<sup>$1</sup>', $string);
Of course, you could use one preg_replace to do what you want:
$string = preg_replace('/^(RMB)(\d+)(\.(\d{2}))?$/', "<sup class='currency-sym'>$1</sup>$2<sup>$4</sup>", $string);
The second example may be a good idea if you want DOM integrity, otherwise it creates an empty <sup></sup> when there is no decimal.
I have values like below:
$var1 = car-123-244343
$var2 = boat-2-1
$var3 = plane-311-23
I need to remove everything and keep the last digit/ditgits after the second hyphen
Expecting values:
244343
1
23
This is what I've got
$stripped = preg_replace('^[a-z]+[-]$', '', 'car-123-244343');
I got a big red error No ending delimiter '^' found
Without regex:
$var1 = substr($var1, strrpos($var1, '-') + 1);
What this does is the same as:
$pos = strrpos($var1, '-') + 1 takes the last postion of '-' and adds 1 for starting at the next character
substr($var, $pos) takes the $var and returns the substring starting in $pos.
I think is less expensive than using regex.
Edit:
As pointed below by konforce, if you are not sure which all the strings have that format, you have to verify it.
this function will work:
function foo($value)
{
$split = explode('-', $value);
return $split[count($split)-1];
}
Here is a fun version with explode:
list($vehicle, $no1, $no2) = explode('-', $data);
First, that error means your regex needs to be enclosed in delimiters (below I use the classic /).
Second, I would rewrite your regex to this:
$stripped = preg_replace('/.+?(\d+)$/', '$1', 'car-123-244343');
If you can operate on the assumption that what comes after the last - is always a number, the other solutions also work.
With regex:
$endnumber = preg_replace('/.*[^0-9]/', '', $input);
Remove everything up till, and including, the last non-digit.
I need to know how I can replace the last "s" from a string with ""
Let's say I have a string like testers and the output should be tester.
It should just replace the last "s" and not every "s" in a string
how can I do that in PHP?
if (substr($str, -1) == 's')
{
$str = substr($str, 0, -1);
}
Update: Ok it is also possible without regular expressions using strrpos ans substr_replace:
$str = "A sentence with 'Testers' in it";
echo substr_replace($str,'', strrpos($str, 's'), 1);
// Ouputs: A sentence with 'Tester' in it
strrpos returns the index of the last occurrence of a string and substr_replace replaces a string starting from a certain position.
(Which is the same as Gordon proposed as I just noticed.)
All answers so far remove the last character of a word. However if you really want to replace the last occurrence of a character, you can use preg_replace with a negative lookahead:
$s = "A sentence with 'Testers' in it";
echo preg_replace("%s(?!.*s.*)%", "", $string );
// Ouputs: A sentence with 'Tester' in it
$result = rtrim($str, 's');
$result = str_pad($result, strlen($str) - 1, 's');
See rtrim()
Your question is somewhat unclear whether you want to remove the s from the end of the string or the last occurence of s in the string. It's a difference. If you want the first, use the solution offered by zerkms.
This function removes the last occurence of $char from $string, regardless of it's position in the string or returns the whole string, when $char does not occur in the string.
function removeLastOccurenceOfChar($char, $string)
{
if( ($pos = strrpos($string, $char)) !== FALSE) {
return substr_replace($string, '', $pos, 1);
}
return $string;
}
echo removeLastOccurenceOfChar('s', "the world's greatest");
// gives "the world's greatet"
If your intention is to inflect, e.g singularize/pluralize words, then have a look at this simple inflector class to know which route to take.
$str = preg_replace("/s$/i","",rtrim($str));
The very simplest solution is using rtrim()
That is exactly what that function is intended to be used for:
Strip whitespace (or other characters) from the end of a string.
Nothing simpler than that, I am not sure why, and would not follow the suggestions in this thread going from regex to "if/else" blocks.
This is your code:
$string = "Testers";
$stripped = rtrim( $string, 's' );
The output will be:
Tester