I'm developing an app with xcode and trying to do a select with some statement, but the query is not working. For example, I created a button in app that contains letter 'A', when I click it calls a script php (JSON) that does a select and return in a listview some result that starts with 'A'.
In xcode I try to define an api like this: #define GET_API #"http://website.16mb.com/field/testsearch.php" or this #"http://website.16mb.com/field/testsearch.php?letter=%#,letter"
In my testsearch.php I wrote:
<?php
$host = "mysql.xxxx.com";
$user = "userxxx";
$pass = "xxxxx";
$database = "udatabase";
mysql_connect($host,$user,$pass) or die("Error connection");
mysql_select_db($database) or die("Error to select database");
$letter = $_GET["letter"];
$query = "SELECT * FROM tablename where letter = '$letter' ORDER BY letter DESC";
$result = mysql_query($query) or die ("Error ");
mysql_close();
$lines = array();
while ($r = mysql_fetch_assoc($result)){
$lines[] = $r;
}
echo json_encode($linhas);
?>
Someone could tell me how I send a data from xcode to script with select and statement?
Thanks for your help.
$letter = $_GET['letter'];
$query = "SELECT * FROM `tablename` where `letter` = '".$letter."' ORDER BY letter DESC";
$result = mysql_query($query) or die (mysql_error());
$lines = array();
while ($r = mysql_fetch_array($result))
{
$lines[] = $r;
}
echo json_encode($lines);
?>
try this
Related
I'm trying to get data from mysql and show them using while loop. But problem is inside while loop there is always one less data i'm getting.
Suppose there is two row in my db , but using this code i'm getting only one row. First row always missing. Cant figure out why ! Sharing some of the code.
tried var_dump() , it shows there is right number rows in db
$ddaa = mysql_query("SELECT * FROM coupons ORDER BY id");
echo mysql_error();
$data = mysql_fetch_array($ddaa);
while ($data = mysql_fetch_array($ddaa))
{
echo $data['id'] ;
}
You are fetching one row before using while loop which you are not using anywhere, thats why you are loosing one row.
$ddaa = mysql_query("SELECT * FROM coupons ORDER BY id") or die(mysql_error());
while ($data = mysql_fetch_array($ddaa))
{
echo $data['id'] ;
}
Try to remove this line:
$data = mysql_fetch_array($ddaa);
The server and database credentials are missing in your code try this one
$server = 'server_name';
$user = 'server_username';
$pass = 'server_password';
$db = 'database_name';
$connection = new mysqli($server, $user, $pass, $db);
$aa = "SELECT * FROM coupons ORDER BY id";
$dd = mysqli_query($connection,$aa); // $connection is the variable which contains server and database credentials;
while ($data = mysqli_fetch_assoc($dd)) {
echo $data['id'];
}
It Will Work For Me. Try This...
<?php
$con=mysql_connect('localhost','root','') or die("could not connect".mysql_error());
mysql_select_db('dbname');
$query = mysql_query("SELECT * FROM Student");
$num_rows = mysql_num_rows($query);
while($row = mysql_fetch_array($query))
{
echo $row['firstname'];
}
echo "<h3>Record Selected successfully\n</h3>";
mysql_close($con);
?>
I have over 40'000 entries and each is assigned to a "list_name"
I am basically trying to get just the list_name value echo'd out
$groupq = mysqli_query($dbc, "SELECT * FROM `products-full` GROUP BY `list_name`");
$groupr = mysqli_fetch_assoc($groupq);
do {
echo $groupr['list_name'];
} while($groupr = mysqli_fetch_assoc($groupq));
however its only displaying 1 entry then no more ..
https://imgur.com/a/3rnXGet
Try this.
$groupq = mysqli_query($dbc, "SELECT * FROM `products-full` GROUP BY `list_name`");
while($groupr = mysqli_fetch_assoc($groupq)){
echo $groupr['list_name'];
}
$database = "sample" //replace your database name here
$conn=new mysqli("localhost","root","",$database); // here username is root and password is null , change it according to yours
if($conn->connect_error)
{
echo $conn->connect_error;
die("sorry database connection failed");
}
$sql = "SELECT * FROM products-full GROUP BY list_name";
$result = $conn->query($sql);
if ($result->num_rows > 0) {
while($row = $result->fetch_assoc()) {
echo $row['list_name'];
}
}
thats it
try this
$groupq = mysqli_query($dbc, "SELECT list_name, count(*) FROM `products-full` GROUP BY
`list_name`");
while($groupr = mysqli_fetch_assoc($groupq)) {
echo $groupr['list_name'];
}
Here I have a php code that connects to a database, selects a row by id and creates an associative array from this row using a while loop. Do I have to write this code over and over again to create arrays from other rows by id? Maybe there is a chance to simplify this php code somehow? Please look at my code. BTW I am new in php...
<?php
$dbhost = 'localhost';
$dbuser = 'root';
$dbpass = '';
$db = '_erica';
$conn = new mysqli($dbhost, $dbuser, $dbpass,$db);
$sql1 = "SELECT * FROM pics WHERE id = 1;";
$sql2 = "SELECT * FROM pics WHERE id = 2;";
$sql3 = "SELECT * FROM pics WHERE id = 3;";
$sql4 = "SELECT * FROM pics WHERE id = 4;";
$sql5 = "SELECT * FROM pics WHERE id = 5;";
$sql6 = "SELECT * FROM pics WHERE id = 6;";
$result1 = $conn->query($sql1);
$result2 = $conn->query($sql2);
$result3 = $conn->query($sql3);
$result4 = $conn->query($sql4);
$result5 = $conn->query($sql5);
$result6 = $conn->query($sql6);
while($row1 = $result1->fetch_assoc()) {
$bcgrnd = $row1["link"];
}
while($row2 = $result2->fetch_assoc()) {
$recipes = $row2["link"];
}
while($row3 = $result3->fetch_assoc()) {
$header = $row3["link"];
}
while($row4 = $result4->fetch_assoc()) {
$menu = $row4["link"];
}
while($row5 = $result5->fetch_assoc()) {
$beauty = $row5["link"];
}
while($row6 = $result6->fetch_assoc()) {
$kids = $row6["link"];
}
?>
You can do this in one query:
$sql = "SELECT * FROM pics WHERE id IN (1,2,3,4,5,6);";
$result = $conn->query($sql);
And then you can loop over all results like this:
$data = array();
while ($row = $result->fetch_assoc()) {
$id = $row["id"];
$link = $row["link"];
$data[$id]["link"] = $link;
// add more fields if you want
}
To access for example the link of ID 1, just do:
$data[1]["link"];
You can write one or two simple functions for this. Moreover, please note that your code is vulnerable to SQL Injection. Here is an example how you can achieve this with some simple functions:
<?php
function DB() {
$dbhost = 'localhost';
$dbuser = 'root';
$dbpass = '';
$db = '_erica';
return new mysqli($dbhost, $dbuser, $dbpass,$db);
}
function query($id) {
$query = "SELECT * FROM `pics` WHERE `id` = $id";
return DB()->query($query);
}
$result = query(1); // will fetch records for ID 1
while($row = $result->fetch_assoc()) {
$bcgrnd = $row["link"];
}
$result = query(2); // will fetch records for ID 2
while($row = $result->fetch_assoc()) {
$bcgrnd = $row["link"];
}
?>
By adapting this approach, you can fetch data for a specific ID. If you don't like this solution, consider using MySQL IN clause.
Try this.
<?php
$dbhost = 'localhost';
$dbuser = 'root';
$dbpass = '';
$db = '_erica';
$conn = new mysqli($dbhost, $dbuser, $dbpass,$db);
$sql = "SELECT * FROM pics WHERE id IN (1,2,3,4,5,6);";
$result = $conn->query($sql);
while($row = $result->fetch_assoc()) {
$bcgrnd[$row["id"]][] = $row["link"];
}
?>
Why not try a Query and Limit it to 6 results, it takes up less resources just pulling 6 results:
SELECT * FROM `pics` ORDER BY `[PRIMARY KEY]` LIMIT 6
MySQL in() function finds a match in the given arguments, you can use it
select pics where id IN(1,2,3,4,5,6)
i'm a newbie to php still.
I'm using phpmyadmin as my database. I have a table called 'lessonno' and a column named 'lesson' in it. I tried using this code to retrieve out the number inside 'lesson'. But it's not printing out anything. Can someone help?
<?php
$server = 'localhost';
$username = '';
$password = '';
$database = 'project';
mysql_connect($server,$username,$password) or die(mysql_error());
mysql_select_db($database) or die(mysql_error());
$sql = "SELECT 'lesson' FROM 'lessonno'";
$lesson = $_POST['lesson'];
$result = mysql_query($sql);
?>
<?php
for($i = 1; $i <= $lesson; $i++) {
echo "<div>
<span>Lesson ".$i."</span>
</div>
<br>";
}
?>
You can use something like this:
$sql = "SELECT lesson FROM lessonno";
$result = mysql_query($sql);
while($row = mysql_fetch_array($result)) {
echo $row['lesson'];
}
If you would like to only print out a specific lesson with an certan ID, you can use something along the lines:
$id = $_GET['lessonid']; // If you would have something like index.php?lessonid=36 and you'd like it to only fetch the data for the lesson with the id of 36.
$sql = "SELECT lesson FROM lessonno WHERE id='$id'";
(by looking at the $_POST['lesson'] part, I suppose that's something you might be trying to do as it's in the for loop as well)
Also, I suggest you use mysqli.
And, this:
echo "<div>
<span>Lesson ".$i."</span>
</div>
<br>";
Will just echo the $i as both lesson= and the span with Lesson, which won't grab any information from the actual database but just go with the current number it's at, from the for loop you have.
i have made some changes in your code try this
<?php
$server = 'localhost';
$username = 'root';
$password = '';
$database = 'project';
$conn = mysql_connect($server,$username,$password) or die(mysql_error());
mysql_select_db($database, $conn) or die(mysql_error());
$sql = "SELECT `lesson` FROM `lessonno`";
$lesson = $_POST['lesson'];
$result = mysql_query($sql) or die(mysql_error());
while($row = mysql_fetch_assoc($result))
{
$lesson_no = $row['lesson'];
echo "<div>
<span>Lesson ".$lesson_no."</span>
</div>
<br>";
}
?>
Note : mysql_* is deprecated. use mysqli_* OR PDO
For getting Values from DB you need to use something like this
while ($row = mysql_fetch_assoc($result)) {
print_r($row);
}
For further reference please visit http://in2.php.net/manual/en/function.mysql-fetch-assoc.php
For counting the number of data in your database, just insert this code
$sql = "SELECT 'lesson' FROM 'lessonno'";
$lesson = $_POST['lesson'];
$result = mysql_query($sql);
$count=mysql_num_rows($result);//this will count the number of rows in your table.
echo "<div>
<span>Lesson ".$count."</span>
</div>
<br>";
I must be missing something simple but I don't see it. The following code works great.
<?php
$res = mysql_connect("localhost", "newuser", "");
mysql_select_db("supplydb");
function filter($data)
{
$data = trim(htmlentities(strip_tags($data)));
if (get_magic_quotes_gpc())
$data = stripslashes($data);
$data = mysql_real_escape_string($data);
return $data;
}
error_reporting(0);
require("../codebase/grid_connector.php");
$mask5 = filter($_GET["var1"]);
//Get Category ID
$cat = mysql_query("SELECT category FROM submissions WHERE submissions.submission_id='$mask5'");
$rows = mysql_fetch_array($cat, MYSQL_ASSOC);
$array = filter($rows['category']);
//Get Manufactuer ID
$man = mysql_query("SELECT manufacturer_id FROM submissions WHERE submissions.submission_id='$mask5'");
$arows = mysql_fetch_array($man, MYSQL_ASSOC);
$array1 = filter($arows['manufacturer_id']);
function formatting($row)
{
$data = $row->get_value("fda_approved");
if ($data == 1)
$row->set_value("fda_approved", Yes);
else
$row->set_value("fda_approved", No);
}
$gridConn = new GridConnector($res, "MySQL");
function myUpdate($action)
{
$data6 = $action->get_id();
$cat_id = mysql_query("SELECT category FROM submissions WHERE submissions.submission_id ='{$data6}'") or die("Error in query: $query. " . mysql_error());
$rows56 = mysql_fetch_array($cat_id, MYSQL_ASSOC);
$array = filter($rows56['category']);
$status = $action->get_value("approval_status");
$gridConn = new GridConnector($res, "MySQL");
mysql_query("UPDATE submissions SET approval_status='{$status}' WHERE submissions.submission_id='{$data6}'") or die("Error in query: $query. " . mysql_error());
$action->success;
}
$gridConn->event->attach("beforeUpdate", "myUpdate");
$gridConn->event->attach("beforeRender", "formatting");
$gridConn->render_sql("SELECT * FROM submissions JOIN products ON products.product_id = submissions.product_id and submissions.category='$array' and submissions.manufacturer_id='$array1' and submissions.approval_status='0'", "submission_id", "item_number,description,list_price,sugg_price,quantity_per_unit,fda_approved,gpo_contract_number, approval_status");
?>
This code does not
<?php
require("../site_globals/dbc_simple.php");
//$res = mysql_connect("localhost", "newuser", "");
//mysql_select_db("supplydb");
error_reporting(0);
require("../codebase/grid_connector.php");
$mask5 = filter($_GET["var1"]);
//Get Category ID
$cat = mysql_query("SELECT category FROM submissions WHERE submissions.submission_id='$mask5'");
$rows = mysql_fetch_array($cat, MYSQL_ASSOC);
$array = filter($rows['category']);
//Get Manufactuer ID
$man = mysql_query("SELECT manufacturer_id FROM submissions WHERE submissions.submission_id='$mask5'");
$arows = mysql_fetch_array($man, MYSQL_ASSOC);
$array1 = filter($arows['manufacturer_id']);
function formatting($row)
{
$data = $row->get_value("fda_approved");
if ($data == 1)
$row->set_value("fda_approved", Yes);
else
$row->set_value("fda_approved", No);
}
$gridConn = new GridConnector($res, "MySQL");
function myUpdate($action)
{
$data6 = $action->get_id();
$cat_id = mysql_query("SELECT category FROM submissions WHERE submissions.submission_id ='{$data6}'") or die("Error in query: $query. " . mysql_error());
$rows56 = mysql_fetch_array($cat_id, MYSQL_ASSOC);
$array = filter($rows56['category']);
$status = $action->get_value("approval_status");
$gridConn = new GridConnector($res, "MySQL");
mysql_query("UPDATE submissions SET approval_status='{$status}' WHERE submissions.submission_id='{$data6}'") or die("Error in query: $query. " . mysql_error());
$action->success;
}
$gridConn->event->attach("beforeUpdate", "myUpdate");
$gridConn->event->attach("beforeRender", "formatting");
$gridConn->render_sql("SELECT * FROM submissions JOIN products ON products.product_id = submissions.product_id and submissions.category='$array' and submissions.manufacturer_id='$array1' and submissions.approval_status='0'", "submission_id", "item_number,description,list_price,sugg_price,quantity_per_unit,fda_approved,gpo_contract_number, approval_status");
?>
The only difference is the include file at the top and all the include file is is:
<?php
$res = mysql_connect("localhost", "newuser", "");
mysql_select_db("supplydb");
?>
Im fairly new to php but this seems simple and I'm not sure what is getting lost in translation. This works fine on other pages by the way so it must have something to do with the $gridConn = new GridConnector($res, "MySQL"); but I dont know enough to see what. I'm using the DHTMLX javascript library. Could it have something to do with that? Ive tried everything here. Ideas?
Im getting: XML Parsing Error: XML or text declaration not at start of entity Location
Problem is not in the database connection itself, it works correctly and generates data, but result xml corrupted, because some output was started before connector's code.
Check ../site_globals/dbc_simple.php - probably it have some whitespaces|newlines after closing "?>" tag - delete them and it will fix the problem.
Such whitespaces|newlines will not cause harm for HTML pages, but for XML data any extra char at start of document can cause a problem.