insert html table multiple row to database - php

I have tried to insert html table multiple row data to database but not success without error.
Please refer below for my code and kindly advice what do I missed.
Retrieve data for dropdown selection
<?php
//including the database connection file
include_once("config_db.php");
$gettminfo=mysql_query("SELECT * FROM tb_tm ORDER BY tm_abb");
?>
Html Code for the table
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
<link rel="stylesheet" type="text/css" href="css/spa_invoice.css"/>
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.3/jquery.min.js"></script>
</head>
<body>
<!--Add & delete rows from table dynamically-->
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.3/jquery.min.js"></script>
<script>
$(function(){
$('#addRow').click(function(){
var html = $('#row_template').html();
$('#dataTable').append(html);
$(".tablerow").each(function(index) {
$(this).html(index + 1);
});
});
$('#deleteRow').click(function(){
$('#dataTable .mychkbox:checked').parents('tr').remove();
calc_ttl();
});
$('#dataTable').on('change','.select-desc',function(){
var cur_val = $(this).val();
$(this).parents('tr').find('input[name="order_unit_prc[]"]').val(cur_val);
});
$('#dataTable').on('keyup','input[name="order_qty[]"]', function(){
var qty = +$(this).val();
var unit = +$(this).parents('tr').find('input[name="order_unit_prc[]"]').val();
$(this).parents('tr').find('input[name="order_amt[]"]').val(qty*unit);
calc_ttl();
});
});
</script>
<form action="" method="post" name="form_spa_inv">
<fieldset class="row3">
<table>
<tr>
<td><input type="button" value="Add Treatment" id="addRow" /></td>
<td><input type="button" value="Remove Treatment" id="deleteRow" /></td>
</tr>
</table>
<table id="dataTable" class="form" border="1">
<tr>
<td></td>
<td>No</td>
<td>Description</td>
<td>Qty</td>
<td>Unit Price</td>
<td>Amount</td>
</tr>
</table>
<!-- table row template here -->
<table id="row_template" style="display:none">
<tr>
<td><input type="checkbox" name="chk[]" class="mychkbox" /></td>
<td class="tablerow"></td>
<td>
<select name="order_desc[]" id="order_desc" class="select-desc">
<option value="">-- Select Treatment --</option>
<?php
while($dd=mysql_fetch_array($gettminfo)) {
?>
<option value="<?php echo $dd['tm_unit_prc']?>"><?php echo $dd['tm_abb'] ?> - <?php echo $dd['tm_desc'] ?></option>
<?php
}
?>
</select>
</td>
<td>
<input type="text" name="order_qty[]" id="order_qty" size="10">
</td>
<td>
<input type="text" name="order_unit_prc[]" id="order_unit_prc" readonly>
</td>
<td>
<input type="text" name="order_amt[]" id="order_amt" readonly>
</td>
</tr>
</table>
</fieldset>
<p style="text-align: center;"><input type="submit" name="Submit" value="Create">
</form>
</body>
</html>
Insert mysql query
<?php
//including the database connection file
include_once("config_db.php");
if(isset($_POST['Submit']))
{
for($i=0; $i < count($_POST['order_desc']); $i++) {
$order_desc = addslashes($_POST['order_desc'][$i]);
$order_qty = addslashes($_POST['order_qty'][$i]);
$order_unit_prc = addslashes($_POST['order_unit_prc'][$i]);
$order_amt = addslashes($_POST['order_amt'][$i]);
//insert data to database tb_odr_dtl
$insert_odrdtl=mysql_query("INSERT INTO tb_odr_dtl(order_desc,order_qty,order_unit_prc,order_amt) VALUES('$order_desc','$order_qty','$order_unit_prc','$order_amt')");
mysql_query($insert_odrdtl);
//display success message
if($insert_odrdtl) {
echo "<script>alert('Invoice created successfully!')</script>";
echo "<script>window.open('cv.php','_self')</script>";
}
}
}
?>

Change server site code to following:
<?php
//including the database connection file
include_once("config_db.php");
if(isset($_POST['Submit']))
{
for($i=0; $i < count($_POST['order_desc']); $i++) {
$order_desc = addslashes($_POST['order_desc'][$i]);
$order_qty = addslashes($_POST['order_qty'][$i]);
$order_unit_prc = addslashes($_POST['order_unit_prc'][$i]);
$order_amt = addslashes($_POST['order_amt'][$i]);
//insert data to database tb_odr_dtl
$insert_odrdtl=mysql_query("INSERT INTO tb_odr_dtl(order_desc,order_qty,order_unit_prc,order_amt) VALUES('$order_desc','$order_qty','$order_unit_prc','$order_amt')");
//mysql_query($insert_odrdtl); //delete this line of code
//display success message
if($insert_odrdtl) {
echo "<script>alert('Invoice created successfully!')</script>";
echo "<script>window.open('cv.php','_self')</script>";
}
}
}
?>

Related

Uploading file is not working in this page

It saves every thing in data but not the name of updated file. It shows undefined index in line 17,18,19,20 it does not show anything in PIC column in database & nothing is stored in subjects_pic folder.
Code is shown here:
<?php
include('conect.php');
$d = '';
$qre = mysql_query("select * from courses1");
while ($res = mysql_fetch_array($qre)) {
$d .='<option value="' . $res['cid'] . '">' . $res['cname'] . '</option>';
}
?>
<?php
include('auth.php');
include('conect.php');
$msg = '';
if (isset($_POST['save'])) {
$course = $_POST['courses1'];
$subjects = $_POST['subjects'];
$name = $_POST['name'];
$file_name = $_FILES['f1']['name'];
$file_type = $_FILES['f1']['type'];
$file_size = $_FILES['f1']['size'];
$file_tmp = $_FILES['f1']['tmp_name'];
$file_path = '../subject_pic/' . $file_name;
move_uploaded_file($file_tmp, $file_path);
mysql_query("INSERT INTO up_file (cid,subid,name,pic)
VALUES ('$course','$subjects','$name','$file_name')");
$msg = '<h3>Record Saved</h3>';
}
?>
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
<title>subjects</title>
<link rel="stylesheet" type="text/css" href="headerstyle.css" />
<script type="application/javascript" src="prototype.js"></script>
<script type="text/javascript">
function abc()
{
var a = $('courses1').value;
$("k").innerHTML = '<img src="ajax-loader.gif">';
new Ajax.Request("ajax1.php", {
method: 'post',
postBody: "e=" + a,
onComplete: Update_abc
});
}
function Update_abc(req)
{
var data = req.responseText;
$("k").innerHTML = '';
$("k").innerHTML = data;
//alert(data);
}
</script>
</head>
<body>
07/25/2014
<div class="fixx"><?php include('header.php'); ?></div>
<div class="tabl">
<table width="700" border="0">
<tr>
<td>
<form method="post" action="filupload.php">
<table width="700" border="1" cellpadding="10">
<tr>
<td colspan="2"><h3> ADD Files To Subjects | EDIT </h3></td>
</tr>
<tr>
<td colspan="2"><?php echo $msg; ?></td>
</tr>
<tr>
<td width="174"><h4>Select Course </h4></td>
<td width="674"><label for="courses"></label>
<select name="courses1" id="courses1" onchange="abc()">
<option value="">Select Course</option>
<?php echo $d; ?>
</select> </td>
</tr>
<tr>
<td width="174"><h4>Select Subject </h4></td>
<td width="674"><label for="subjects"></label>
<div id="k">
<select name="subjects" id="subjects"><option value="">Select Subject</option></select>
</div> </td>
</tr>
<tr>
<td><h4>File Name</h4></td>
<td><input type="text" name="name" id="name" /></td>
</tr>
<tr>
<td><h4>Upload Pic</h4></td>
<td><label for="f1"></label>
<input type="file" name="f1" id="f1" /></td>
</tr>
<tr>
<td><input type="submit" name="save" id="save" value="Submit" /></td>
</tr>
</table>
</form>
</td>
</tr>
</table>
</div>
</body>
</html>
use enctype="multipart/form-data" in form tag like:
<form action="filupload.php" method="post" enctype="multipart/form-data">
To upload images or any files 'enctype' should be assigned
<form method="post" action="filupload.php" enctype="multipart/form-data">

checkbox value inserted in mysql

I'm struggling now for a few days to get the value of a checkbox in my code.
Basically I have an admin-page where the customer can select and deselect images that will put online.
You can select and deselect images that will be shown on the homepage, and separate on the gallery-page. Both checked is also possible.
I have another checkbox that can be selected to remove the image from the list(image_deleted).
There is still a database entry and the images are still on file-system but later on I'll create a cleanup-job.
Here is my code:
<?php
ini_set('display_errors', 1);
error_reporting(E_ALL);
ob_start();
require('../../lib/dbconnection.php');
require("../../lib/checklogin.php");
require("includes/upload.inc.php");
$query = 'SELECT * FROM gallery where image_deleted != 1 order by id desc';
$result=$conn->query($query);
$count=$result->num_rows;
?>
<!DOCTYPE html>
<html>
<head>
<title>Classic Nails - CMS</title>
<meta charset="utf-8">
<meta http-equiv="X-UA-Compatible" content="IE=edge,chrome=1">
<meta name="description" content="ClassicNails">
<meta name="viewport" content="width=device-width, initial-scale=1">
<link rel="stylesheet" href="../css/screen.css">
<link rel="stylesheet" href="../css/libs/magnific-popup.css">
<script src="../js/libs/min/jquery-min.js" type="text/javascript"></script>
<script src="../js/min/custom-min.js" type="text/javascript"></script>
<script src="js/jquery.magnific-popup.js"></script>
<script>
$(document).ready(function() {
$('.image-link').magnificPopup({
type:'image',
gallery:{
enabled:true
}
});
});
</script>
</head>
<body>
<?php include('includes/header.inc.php'); ?>
<?php include('includes/nav.inc.php'); ?>
<div class="wrapper">
<article class="content">
<h1>Foto gallery</h1>
<?php
if (isset($uploadResult)) {
echo "<p><strong>$uploadResult</strong></p>";
}
?>
<form action="" method="post" enctype="multipart/form-data" name="uploadImage" id="uploadImage">
<p>
<label for="image">Upload image:</label>
<input type="hidden" name="MAX_FILE_SIZE" value="<?php echo MAX_FILE_SIZE; ?>" />
<input type="file" name="images" id="imagesd" />
</p>
<p>
<input type="submit" name="upload" id="upload" value="Upload" />
</p>
</form>
<div id="maincontent">
<h2>Foto informatie</h2>
<form name="FotoInformatie" id="fotoInformatie" method="post" action="">
<table>
<tr>
<td align="center"><strong>Foto<strong></td>
<td align="center"><strong>Titel</strong></td>
<td align="center"><strong>Beschrijving</strong></td>
<td align="center"><strong>Homepage</strong></td>
</tr>
<?php
while ($rows=$result->fetch_assoc()) {
?>
<tr>
<td class="hide" align="center"><?php $id[]=$rows['id']; ?><?php echo $rows['id']; ?></td>
<td><img src="../img/thumbs/<?php echo $rows['filename']; ?>"></td>
<td align="center"><input name="title[]" type="text" id="title" value="<?php echo $rows['title']; ?>"></td>
<td align="center"><input name="caption[]" type="text" id="caption" value="<?php echo $rows['caption']; ?>"></td>
<td><input type="checkbox" name="checkboxHome[]" id="checkBoxHome" value="<?php echo ($rows['home'] == 1) ? 'checked="checked"' : ''; ?>"/></td>
</tr>
<?php
}
?>
<tr>
<td colspan="4" align="center">
<input type="submit" name="submit" value="Submit">
</tr>
</table>
</form>
</div>
</article> <!-- end of content -->
</div> <!-- end of container -->
<?php include('includes/footer.inc.php'); ?>
</body>
</html>
<?php
if(isset($_POST['submit'])) {
$title = $_POST['title'];
$caption = $_POST['caption'];
if ($_POST['checkboxHome'] == "") {
$checkboxHome[] = '0';
} else {
$checkboxHome[] = '1';
}
for($i=0;$i<$count;$i++){
$result1=mysqli_query($conn, "UPDATE gallery SET title='$title[$i]', caption='$caption[$i]', home='$checkboxHome[$i]' WHERE id='$id[$i]'");
header("location:/admin/foto-admin.php");
}
}
?>
The checkbox only works on the first row in my DB. When I select another record, only the first record in my db will be updated.
Another issue is that my checkbox won't be checked so I don't know based on my screen when a image is online or not. in the database I see a 1 of a 0.
I know that sql-injection is possible and I have to prepare the statements, but that is the next step when I get this checkbox-issue working.
Hope someone can help me with my code. It's giving me a headache.
Check these
Attribute name="id[]" for id field is not given. And it should get inside
if(isset($_POST['submit'])) {
$id = $_POST['id'];
}
Incorrect spelling in getting Post value
change
$checkboxHome = $_POST['checkboxHome'];
$checkboxFotoboek= $_POST['checkboxFotoboek'];
$checkboxDelete = $_POST['image_deleted'];
to
$checkboxHome = $_POST['checkBoxHome'];
$checkboxFotoboek= $_POST['checkBoxFotoboek'];
$checkboxDelete = $_POST['checkboxDelete'];
You are trying to get wrong value.
Your check-box name is checkBoxHome and you are trying to get $_POST['checkboxHome'] instead of $_POST['checkBoxHome'] .
Try $_POST['checkBoxHome'] and print it as print_r('checkBoxHome')
Same mistake in checkBoxFotoboek check-box.
try this
if(isset($_POST['submit'])) {
$title = $_POST['title'];
$caption = $_POST['caption'];
$checkboxHome = $_POST['checkBoxHome'];
$checkboxFotoboek= $_POST['checkBoxFotoboek'];
$checkboxDelete = $_POST['checkboxDelete'];
for($i=0;$i<$count;$i++){
$result1=mysqli_query($conn, "UPDATE gallery SET title='$title[$i]', caption='$caption[$i]', home='$checkboxHome[$i]', fotoboek='$checkboxFotoboek[$i]', image_deleted='$checkboxDelete[$i]' WHERE id='$id[$i]'");
header("location:/admin/foto-admin.php");
}
}
?>

Dynamically enable and disable DIV via MySQL

Last night I was trying to figure out how I can how I can dynamically enable and disable span#txtCaptchaDiv on my contact form at the very bottom, above the submit button.
So I added a new field to MySQL, called captcha where I wanted to 1 to show and 0 to hide
So if I add 1 to field captcha the following code will show on my form.php
<label for="code">Write code below > <span id="txtCaptchaDiv" style="color:#F00"></span><!-- this is where the script will place the generated code -->
<input type="hidden" id="txtCaptcha" /></label><!-- this is where the script will place a copy of the code for validation: this is a hidden field -->
<input type="text" name="txtInput" id="txtInput" size="30" />
If I add 0 to field captcha the captcha area will be blank on my form.php.
Can you guy help me out please?
here is my index.php code I currently have:
<?php
require_once("/config/database.php");
$con = mysql_connect($config["db_server"],$config["db_user"],$config["db_pass"]);
?>
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
<title>Email FORM</title>
</head>
<body>
<div style="width: 550px; text-align: center;">
<span style="filter:alpha(opacity=60); opacity:.6; padding-left: 10px;"><br />
<?php
$data = mysql_query("SELECT * FROM formrelated")
or die(mysql_error());
while($info = mysql_fetch_array( $data ))
Print " ".$info['welcomemsg'] . "";
?>
</span></div>
<form id="form1" name="form1" method="post" action="submit.php" onsubmit="return checkform(this);">
<table width="454" border="1" align="center" cellpadding="0" cellspacing="0">
<tr>
<td width="123">Name</td>
<td width="325">
<input name="name" type="text" />
</td>
</tr>
<tr>
<td height="21">Address</td>
<td><input name="adress" type="text" /></td>
</tr>
<tr>
<td height="21"> </td>
<td><input name="address2" type="text" /></td>
</tr>
<tr>
<td height="21">Email</td>
<td><input name="email" type="text" /></td>
</tr>
<tr>
<td height="21">Tel</td>
<td><input name="email" type="text" /></td>
</tr>
</table>
<!--- captcha code here--->
<center>
<table width="454" height="122" border="0" cellspacing="0" cellpadding="0" background="reCAPbg.png">
<tr>
<td height="73" colspan="2" align="center" valign="middle"><label for="code"><span id="txtCaptchaDiv" style="color:#333; font-size:18px;"></span><!-- this is where the script will place the generated code -->
<input type="hidden" id="txtCaptcha" /></label></td>
<td width="136" rowspan="2"> </td>
</tr>
<tr>
<td width="145"> type the code here:</td>
<td width="173" height="47" align="center"><input type="text" name="txtInput" id="txtInput" size="20" /></td>
</tr>
</table>
</center>
<!--- captcha code ends here--->
<input name="Submit" type="button" value="submit" />
</form>
<script type="text/javascript">
//Generates the captcha function
var a = Math.ceil(Math.random() * 9)+ '';
var b = Math.ceil(Math.random() * 9)+ '';
var c = Math.ceil(Math.random() * 9)+ '';
var d = Math.ceil(Math.random() * 9)+ '';
var e = Math.ceil(Math.random() * 9)+ '';
var code = a + b + c + d + e;
document.getElementById("txtCaptcha").value = code;
document.getElementById("txtCaptchaDiv").innerHTML = code;
</script>
<script type="text/javascript">
function checkform(theform){
var why = "";
if(theform.txtInput.value == ""){
why += "- Security code should not be empty.\n";
}
if(theform.txtInput.value != ""){
if(ValidCaptcha(theform.txtInput.value) == false){
why += "- Security code did not match.\n";
}
}
if(why != ""){
alert(why);
return false;
}
}
// Validate the Entered input aganist the generated security code function
function ValidCaptcha(){
var str1 = removeSpaces(document.getElementById('txtCaptcha').value);
var str2 = removeSpaces(document.getElementById('txtInput').value);
if (str1 == str2){
return true;
}else{
return false;
}
}
// Remove the spaces from the entered and generated code
function removeSpaces(string){
return string.split(' ').join('');
}
</script>
</body>
</html>
This will work for you... enjoy!
<?PHP
$query = mysql_query("SELECT captcha FROM formrelated WHERE id = '1'");
while ($row = mysql_fetch_assoc($query)) {
$captchathis = $row['captcha'];
if ($captchathis == "1") {
echo "YOUR HTML CODE HERE";
}
else {
echo "BLANK";
}
}
?>
Try it like this
<?PHP
if($mysqlResult['captcha'] === 1)
{
echo $myHtml;
}
?>
Where $mysqlResult is an array with the result from the query, $mysqlResult['captcha']is the value of the row captcha from your query and $myHtml is that HTML code you just showed on your answer.
Good luck! ;)
Reffer to
http://php.net/manual/en/
EDIT:
http://www.php.net/manual/en/language.types.array.php ( Array type on the manual )
http://www.php.net/manual/en/control-structures.if.php ( If control structure on the manual )
http://www.php.net/manual/en/ref.mysql.php ( MySQL native functions. deprecated. Preffer MySQLi )
http://www.php.net/manual/en/book.mysqli.php ( MySQLi extension )
http://www.php.net/manual/en/book.pdo.php ( PDO native php class )
Another answer to explain the basic construct of IF logic.
Suppose i have some condition i want to meet to do something; in this case, the following logic
SHOW my form with the basic inputs
IF condition 'captcha = 1' is met, SHOW input2 (captcha)
SHOW rest of the HTML
it would be like this in PHP
<?PHP
echo $myFormWithBasicInputs;
if($captcha === 1)
{
echo $input2;
}
echo $restOfHTML;
?>
In your case, $myFormWithBasicInput and $restOfHTML is already outputed as HTML. All you want to do is inject an PHP code in it to check if some condition is matched. It will be like this
<html>
<!-- MY FORM WITH BASIC INPUTS -->
<?PHP
$captcha = $mySQLresult['captchaRow'];
if($captcha === 1)
{
?>
<!-- CAPTCHA INPUT HERE -->
<?PHP
}
?>
<!-- REST OF HTML -->
</html>
be aware that this is an workaround with example code.
<?PHP
$mysql_query = "SELECT captcha FROM formrelated";
$captcha = $mySQLresult['captchaRow'];
if($captcha === 1)
{
?>
<!--- CODE---->
<table width="454" height="122" border="0" cellspacing="0" cellpadding="0" background="reCAPbg.png">
<tr>
<td height="73" colspan="2" align="center" valign="middle"><label for="code"><span id="txtCaptchaDiv" style="color:#333; font-size:18px;"></span><!-- this is where the script will place the generated code -->
<input type="hidden" id="txtCaptcha" /></label></td>
<td width="136" rowspan="2"> </td>
</tr>
<tr>
<td width="145"> type the code here:</td>
<td width="173" height="47" align="center"><input type="text" name="txtInput" id="txtInput" size="20" /></td>
</tr>
</table>
<?PHP
}
?>
<!-- REST OF HTML -->

PHP Form Submision with jQuery Mobile

This is my code for a jquery mobile application. But the form i created with php result is not working. Form is not posting data on submit. I even tried data-ajax="flase".
<table id="stock">
<? $sql = mysqli_query($con, "SELECT * FROM products WHERE `product_id` = '1'");
while($row=mysqli_fetch_array($sql)){
$name = $row['name'];
$chamecal = $row['chamecal'];
$price = $row['selling_price'];
$bprice = $row['buying_price'];
$quantity = $row['quantity'];
$manufacturer = $row['manufacturer'];
$date = $row['date'];
$edate = $row['expire'];
$pid = $row['product_id'];
?>
<form id="stockupdate" method="post" action="medupdate.php">
<tr>
<td><?=$name;?></td>
<td><?=$chamecal;?></td>
<td><?=$manufacturer;?></td>
<td><input type="text" name="medbprice" value="<?=$bprice;?>" /></td>
<td><input type="text" name="medprice" value="<?=$price;?>" /></td>
<td><?=$date;?></td>
<td><?=$edate;?></td>
<td><input type="text" name="medstock" value="<?=$quantity;?>" /></td>
<td class="ui-screen-hidden"><input type="text" name="pid" value="<?=$pid;?>" /></td>
<td>
<input type="submit" title="Update" data-icon="gear" data-theme="f" data-inline="true" data-iconpos="notext" />
</td>
</tr>
<?
}
?>
</form>
</table>
Values Handler file medupdate.php
<?php session_start();?>
<?php include_once('include/config.php');?>
<?
$pid = $_POST['pid'];
$medbprice = $_POST['medbprice'];
$medprice = $_POST['medprice'];
$medstock = $_POST['medstock'];
$sql = mysqli_query($con, "UPDATE `products` SET `quantity` = '$medstock', `buying_price` = '$medbprice' , `selling_price` = '$medprice' WHERE `product_id` = '$pid'");
if($sql){
echo 1;
}
?>
If I was to hazard a guess, it's because you're placing
<form id="stockupdate" method="post" action="medupdate.php">
directly within a table element (which is invalid markup). Move this outside your table (before your <table>). When you create invalid markup, the browsers engine tries to correct it which can lead to issues like this.
This is what chrome does to your markup:
You cannot follow the html structure, a form inside table like,
<table>
<form>
<tr>
<td>
</td>
</tr>
</form>
</table>
Here is the working code,
Form php
<!DOCTYPE html>
<html>
<head>
<meta name="viewport" content="width=device-width, initial-scale=1">
<meta http-equiv="Content-Type" content="text/html; charset=UTF-8">
<link rel="stylesheet" href="http://code.jquery.com/mobile/1.3.2/jquery.mobile-1.3.2.min.css">
<script src="http://code.jquery.com/jquery-1.9.1.min.js"></script>
<script src="http://code.jquery.com/mobile/1.3.2/jquery.mobile-1.3.2.min.js"></script>
</head>
<body>
<form id="stockupdate" method="post" action="medupdate.php" data-ajax="false">
<table>
<tr>
<td><input type="text" name="medbprice" value="xxxx" /></td>
<td><input type="text" name="medprice" value="yyyyy" /></td>
<td><input type="text" name="medstock" value="zzzzzz" /></td>
<td class="ui-screen-hidden"><input type="text" name="pid" value="111111" /></td>
<td>
<input type="submit" title="Update" data-icon="gear" data-theme="f" data-inline="true" data-iconpos="notext" />
</td>
</tr>
</table>
</form>
</body>
</html>
medupdate.php
<?php
session_start();
$pid = $_POST['pid'];
$medbprice = $_POST['medbprice'];
$medprice = $_POST['medprice'];
$medstock = $_POST['medstock'];
echo $pid;
// your database operations
?>

Firefox does not submit my form

I have a php application that fetches the requests from mysql database and displays them for further approval. The form is fetched from send_req.php and is displayed inside the div on showrequests.php. This is the code for send_req.php
<table style="border:0;border-color:transparent">
<tr style="background-color:lightblue">
<td>Product ID</td>
<td>Name</td>
<td>Quantity</td>
<td><input type="checkbox" name="selectAll" /></td>
<td>Authorized Quantity</td>
</tr>
<form method="post" action="send_req.php">
<?php
$reqNum = $_POST['rId'];
echo "<h3>Request # $reqNum</h3>";
$showReqs = mysql_query("Select * from request where request_number='".$reqNum."' and status=0");
while($resultA = mysql_fetch_array($showReqs))
{
$rBy = $resultA['requested_by'];
$rTime = $resultA['request_time'];
$rId = $resultA['id'];
$pId = $resultA['product_id'];
$getPrName = mysql_query("select name from products where id='$pId'");
$prN = mysql_fetch_array($getPrName);
$prName = $prN['name'];
$rQuantity = $resultA['requested_quantity'];
$status = $resultA['status'];
?>
<tr>
<input type="hidden" name="rId[]" value="<?php echo $rId; ?>"/>
<td style="background-color:orange"><input type="text" name="prId[]" value="<?php echo $pId; ?>" readonly="readonly" style="border:0px"/></td>
<td style="background-color:orange"><input type="text" name="prName[]" value="<?php echo $prName; ?>" readonly="readonly" style="border:0px"/></td>
<td style="background-color:orange"><input type="text" name="quantity[]" value="<?php echo $rQuantity; ?>" readonly="readonly" style="border:0px"/></td>
<td style="background-color:orange"></td>
<td><input type="text" name="pQuantity[]" /></td>
</tr>
<?php }
?>
<tr>
<td></td>
<td></td>
<td></td>
<input type="hidden" name="rNum" value="<?php echo $reqNum; ?>" />
<td></td>
<td><input type="submit" name="submitReq" value="Send" id="submit_req" style="backgroundColor:Transparent;border:0;color:blue;width:100;"/></td>
</tr>
</form>
</table>
<?php
echo "Requested By:$rBy at ".substr($rTime,11,18)." ".substr($rTime,0,10);
?>
This is the showrequests.php page
<html>
<head>
<script type="text/javascript">
function getRequest(ob)
{
var id = ob.id;
if(window.XMLHttpRequest)
{
ajaxOb = new XMLHttpRequest();
}
else if(window.ActiveXObject)
{
ajaxOb = new ActiveXObject("Microsoft.XMLHTTP");
}
ajaxOb.open("POST", "send_req.php");
ajaxOb.setRequestHeader("Content-Type", "application/x-www-form-urlencoded");
ajaxOb.send("rId=" + id);
ajaxOb.onreadystatechange = function()
{
if(ajaxOb.readyState == 4)
{
if(ajaxOb.status == 200)
{
document.getElementById("showTable").innerHTML = ajaxOb.responseText;
}
}
}
}
</script>
</head>
<body>
<?php
$mysql_con = mysql_connect("localhost","root","") or die("Could not connect ".mysql_error());
$mysql_db = mysql_select_db("cart",$mysql_con) or die("Unable to select db ".mysql_error());
echo "<h2 align='center'>Pending Requests</h2>";
$showReq = mysql_query("Select distinct(request_number) as rNums from request where status=0");
?>
<div style="float:left;margin-right:15px;">
<br/>
<?php
while($result = mysql_fetch_array($showReq))
{
$rNum = $result['rNums'];
?>
<input type="button" name="fetchReq" id="<?php echo $rNum; ?>" value="<?php echo "Request # $rNum"; ?>" style="margin-bottom:5px;backgroundColor:Transparent;border:0;color:blue;width:100;text-Decoration:underline" onclick="getRequest(this)"/>
<?php
echo "<br/>";
}
?>
</div>
<div id="showTable" style="float: left">
</div>
</body>
</html>
My problem now is that everything works fine in chrome and IE but the form is not submitted when i click the submit button in firefox. I am using firefox 20.0.1. Update: I have removed the html,head and body tags from send_req.php
still not working
form is not allowed inside table. Please see also
Form inside a table
Regards,
Michael
Reminder : the structure of an HTML document is :
<!-- No div before html tag -->
<!DOCTYPE html> <!-- Doctype for HTML5 ; use whatever doctype you need -->
<html>
<head>
</head>
<!-- No div before body tag -->
<body>
<!-- Divs only belongs here -->
</body>
</html>
<!-- No div after html tag -->
If you don't follow this basic structure, you're forcing the browser to interpret your invalid code (+ quirks mode when you don't provide a doctype).
Some browser guess well what you tried to do, others don't, as Firefox might.
Please use a HTML validator as W3's validator to check your syntax.

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