How to get URL last part with php - php

Question

I was searching for solutions to display the current URL of the page, and I found a few ones but I don't know how to implement them and call them, so this was the best solution I've found for me because it already has the echo thingy.
function curPageURL() {
$pageURL = 'http';
if ($_SERVER["HTTPS"] == "on") {$pageURL .= "s";}
$pageURL .= "://";
if ($_SERVER["SERVER_PORT"] != "80") {
$pageURL .= $_SERVER["SERVER_NAME"].":".$_SERVER["SERVER_PORT"].$_SERVER["REQUEST_URI"];
} else {
$pageURL .= $_SERVER["SERVER_NAME"].$_SERVER["REQUEST_URI"];
}
return $pageURL;
}
And to call it, I'm calling it like this
echo curPageURL();
But I want to get only the last part of the URL, for exemple:
http://stackoverflow.com/posts/29237151/thequestion
I want to get thequestion part of the URL. how can I do this?

Answer 1

As stated in the comments, the best way is to explode() then array_pop() your URL.
Like so:
function curPageURL() {
$url = $_SERVER['REQUEST_URI'];
$url = explode('/', $url);
$lastPart = array_pop($url);
return $lastPart;
}
#Vineet answer is suitable too.

Answer 2

In your case. Please change like
$url = curPageURL();
It will give you complete URL and then write lines as below
$new = explode("/", $url);
$last_part = end($new);
It will give your desired output.

Answer 3

You could try this as well
echo substr(strrchr(curPageURL(), "/"), 1);

Answer 4

http://php.net/manual/en/function.parse-url.php
PHP has a function called parse_url() that will ... parse an URL.
What you are looking for is the path part of the result.
<?php
$url = 'http://stackoverflow.com/posts/29237151/thequestion?arg=value#anchor';
$pathParts = parse_url($url, PHP_URL_PATH);
$lastPart = array_pop(explode('/', $pathParts));
echo $lastPart;

Answer 5

The shortest way I think is:
end(explode('/', $url));