I am trying to add all the query values to an array.
here is my code:
$value = $_POST['hospitalname'];
$from = $_POST['from'];
$to = $_POST['to'];
if($_POST["Submit"]=="Submit") {
for ($i=0; $i<sizeof($value); $i++) {
$sql = "SELECT sl_id from mfb_servicelog where h_id LIKE ('".$value[$i]."')";
$result = mysql_query($sql);
while ($row = mysql_fetch_assoc($result)) {
$slid = $row["sl_id"];
for ($x=0; $x<sizeof($slid);$x++) {
echo $slid[$x];
}
}
}
}
If I print the result of $slid, it gives me this
1333853863873885215251126112711281129113023392488248924902491249224932494249524962497
These all are sl_id, and result of the query $sql. This is fine.
Now I want to put all these value into an array so that I can call this from a query like I am calling the $value in the above $sql query.
But my echo $slid($x) gives me this output, whic is the first digit of each value.
13333551111122222222222
Please suggest me the right way to do this.
Just store them in an array instead of a normal variable. Try with -
$slid[] = $row["sl_id"];
Update
if (!in_array($row["sl_id"], $slid)) {
$slid[] = $row["sl_id"];
}
And define $slid before the loop starts - $slid = array();
Or you can use array_unique()
For your code it should be -
$slid = array();
while ($row = mysql_fetch_assoc($result)) {
if (!in_array($row["sl_id"], $slid)) {
$slid[] = $row["sl_id"];
}
}
foreach($slid as $id) {
echo $id."<br>";
}
Related
I created a function that read data from a mysql db.
I want to put the data into a array and read that outside of the PHP function.
function showCategory($con) {
$sql = "SELECT * FROM kategorien";
$kategorien = array();
$result = $con->query($sql);
while($row = $result->fetch_assoc()) {
$kategorien[] = $row["kategorie"];
return $kategorien;
}
}
To load the data outside from function:
$kategorien = showCategory($con);
echo $kategorien['kategorie'][0];
It doesn't work. Whats wrong?
The
return $kategorien;
will exit the loop and the function, so move this to the end of the function and not in the loop.
function showCategory($con) {
$sql = "SELECT kategorie FROM kategorien";
$kategorien = array();
$result = $con->query($sql);
while($row = $result->fetch_assoc()) {
$kategorien[] = $row["kategorie"];
}
return $kategorien;
}
Rather than using *, it's also worth specifying the column names if you only need some of them.
Display the data using...
$kategorien = showCategory($con);
print_r( $kategorien );
or use a foreach()...
$kategorien = showCategory($con);
foreach ( $kategorien as $kat ) {
echo $kat.PHP_EOL;
}
Use this instead, because returning $kategorien will exit the loop, so it will only run once.
function showCategory($con) {
$sql = "SELECT * FROM kategorien";
$kategorien = array();
$result = $con->query($sql);
while($row = $result->fetch_assoc()) {
$kategorien[] = $row["kategorie"];
}
return $kategorien;
}
$a_forms = array("a_GG", "a_FF");
$sql = "SELECT name, field FROM categories WHERE enabled = '1' ";
$result = mysqli_query($con,$sql);
$Others = array();
while($row = mysqli_fetch_array($result)) {
$Other_names[] = $row['name'];
$Other_fields[] = $row['db_field'];
}
for ($i=0;$i<count($a_forms);$i++) {
if ($a_forms[$i] == "a_FF") {
$dforms_sql = "SELECT *
FROM a_FF
where id=".$id;
$dforms_result = mysqli_query($con,$dforms_sql);
while ($forms_row = mysqli_fetch_array($dforms_result)) {
for ($i=0; $i<count($Other_fields); $i++) {
echo "<tr><td colspan='3'>".$Other_names[$i]."</td></tr>";
}
}
} elseif ($a_forms[$i] == "a_GG") {
$dforms_sql = "SELECT *
FROM a_GG where id=".$id;
$dforms_result = mysqli_query($con,$dforms_sql);
while($forms_row = mysqli_fetch_array($dforms_result)) {
echo 'Other cool stuff';
}
}
} //END (first) For Loop
So, for some reason, if that second for loop, $Other_field is there it will only show the IF statement for a_FF. But if the array = a_FF and a_GG and the for loop for $other_field is NOT there it displays them both. So it's obviously that for loop that is breaking something, I have no idea what though. Anyone have any thoughts?
So the task is:
Do a query like Select * from table.
Take some cell value
Insert this value to a new query.
What do I have so far:
$Conn = odbc_connect("...");
$Result = odbc_exec("Select ...");
while($r = odbc_fetch_array($Result))
// showing result in a table
Here it looks like I should use the r array and insert data like
$var = r['some_field'];
$query = 'Select * from table where some_field = {$var}";
But how can I fill this array with values and how to make it available out of while loop?
Here I'm using odbc, but it doesn't matter, I need the algorithm. Thanks.
The whole code looks like:
<?php
$data = array();
$state = 'false';
if($_REQUEST['user_action']=='')
{
$Conn = odbc_connect("...");
$data = array();
if($_REQUEST['name']!='')
{
$Result = odbc_exec($Conn, "select ...");
//Showing result table
while($r = odbc_fetch_array(Result))
{
array_push($data, $r['cardgroup']);
$state = 'true';
}
// print_r($data); WORKS;
}
}
if ($_REQUEST['user_action'] == 'action1')
{
//I need to use $data HERE. Doesn't work
// $state = 'false' here...
}
?>
Define array outside while loop
$data = array();//defining
while($r = odbc_fetch_array($Result))
use array_push() inside while loop
array_push($data, $r['some_field']);
then try to print array of complete data outside loop
print_r($data);
Updates
Place $data = array(); at the top of first IF statement. Try this code:
$data = array();//at top
if($_REQUEST['user_action']=='')
{
$Conn = odbc_connect("...");
if($_REQUEST['name']!='')
{
$Result = odbc_exec($Conn, "select ...");
//Showing result table
while($r = odbc_fetch_array(Result))
{
array_push($data, $r['cardgroup']);
}
// print_r($data); WORKS;
}
}
if ($_REQUEST['user_action'] == 'action1')
{
//print_r($data) works here also
}
try something like this to store data in array
$allrows = array();
while($r = odbc_fetch_array( $result )){
$allrows[] = $r;
}
use foreach loop to print or use as per your choice
foreach($allrows as $singlerow) {
//use it as you want, for insert/update or print all key value like this
foreach($singlerow as $key => $value) {
//echo $key . '=='. $value;
}
}
You can try this as i understand your query hope this is your answer
$arr ='';
while($row = odbc_fetch_array($Result)) {
$arr .= '\''.$row['some_field'].'\',';
}
$arr = trim($arr, ",");
$query = "SELECT * from table where some_field IN ($arr)";
Your all task can be completed in single query
INSERT INTO table2 (col1, col2, ..., coln)
SELECT col1, col2, ..., coln
FROM table1
I need the $data to return from the database if the data was found from the database, but unfortunately, my code is not working to return the data.
I tried to enter non-exist data, it managed to return the error message but if the data exist, the page displays nothing.
May I know where did I go wrong in my if statement?
Below is my code that contain after the $data return the script will execute.
$day = $_POST['day'];
$month = $_POST['month'];
$year = $_POST['year'];
$dob = implode('/', array($day,$month,$year));
if(isset($_POST['submit'])){
if(empty($_POST['day']) || empty($_POST['month']) || empty($_POST['year'])){
echo "You need to fill in each field.<br /><br />Click here to <b>fill in each field</b> again";
exit;
}
}
//Date that user keyin
$userDate = $dob;
$dateTime = DateTime::createFromFormat('d/m/Y', $userDate);
$myFormat = $dateTime->format('Y-m-d');
//Query string and put it in a variable.
if(isset($_POST['dob_chi'])){
$query = "SELECT * FROM $table_n WHERE dob_chi = :date";
} else {
$query = "SELECT * FROM $table_n WHERE dob_eng = :date";
}
$stmt = $db->prepare($query);
$stmt->execute(array('date' => $myFormat));
$data = $stmt->fetchAll();
if ( !$data ) {
echo 'No data found in database!';
exit;
} else {
return $data=$userDate;
}
//Now we create a while loop for every entry in our DB where the date is match.
while ($row = $stmt->fetchObject()) {
$r1 = $row->rowone;
$r2 = $row->rowtwo;
$r3 = $row->rowthree;
$englishdate = $row->dob_eng;
$chinesedate = $row->dob_chi;
$zodiac = $row->zodiac;
//add all initial data into a matrix variable for easier access to them later
//To access rowone use $rows[0][0], rowtwo $rows[1][0] ect.
//The matrix is an array which contains multiple array. eg. 2-dimensional arrays
//To get all the variables with $r1X simply retrieve the first array of the matrix eg $rows[0]
$rows = array(array($r1),array($r2),array($r3),array());
}
//Similarities between row1 and row2 made me incorporate modulo value as an argument.
function incmod($a, $m){
return ($a % $m) + 1;
}
Thank you for your time
Get rid of the line:
return $data=$userDate;
because it's ending your script and also overwriting the $data variable.
Change:
$data = $stmt->fetchAll(PDO::FETCH_OBJ);
Then change the line:
while ($row = $stmt->fetchObject()) {
to:
foreach ($data as $row) {
The first question is how to run a function using the URL, I have the following function:
function do_curl($start_index,$stop_index){
// Do query here to get all pages with ids between start index and stop index
$query = "SELECT * FROM xxx WHERE xxx >= $start_index and xxx <= $stop_index";
Now when I'm trying to do curl.php?start_index=0&stop_index=2 this is not working but when i delete the function and WHERE idnum = 1 it is working.
Now the second question is how 'compile' all the fields from the rows to arrays? I have the current code:
$query = "SELECT * FROM fanpages";
$result = mysql_query($query) or die(mysql_error());
while ($row = mysql_fetch_array($result))
{
$fanpages_query = '\'http://graph.facebook.com/'.$row['page_id'].'\', ';
echo $fanpages_query;
}
$fanpages = array($fanpages_query);
$fanpages_count = count($fanpages);
echo $fanpages_count;
echo $fanpages_query; returning
'http://graph.facebook.com/AAAAAA', 'http://graph.facebook.com/BBBBBBB', 'http://graph.facebook.com/CCCCCCCC',
(I don't have an idea how to do it in a different way, also when im doing it in such a way i can't delete the final comma which will return PHP-error.)
echo $fanpages_count; returns 1 and like you can see i have 3 there.
Thanks in advance guys!
Do a function call to do the query
function do_curl($start_index, $stop_index){
...
}
$fanpages = do_curl($_GET['start_index'], $_GET['stop_index']);
For your second question, you can use arrays and the implode function to insert commas:
while ($row = mysql_fetch_array($result))
{
$fanpages_query[] = 'http://graph.facebook.com/'.$row['page_id'];
}
return $fanpages_query;
Then use implode to print them out:
echo implode(',', $fanpages);
The whole code:
function do_curl($start_index = 0, $stop_index = null) {
$queryIfThereIsNoStartIndex = '';
$queryIFThereIsNoStopIndex = '';
$queryIfBothStartAndStopIndexAreMissing = '';
$result = mysql_query($query) or die(mysql_error());
while ($row = mysql_fetch_array($result))
{
$fanpages_query[] = 'http://graph.facebook.com/'.$row['page_id'];
}
return $fanpages_query;
}
$fanpages = do_curl($_GET['start_index'], $_GET['stop_index']);
$fanpages_count = count($fanpages);
echo implode(',', $fanpages);
And you should totally use mysql_escape_string for escaping the values you add to the query.