Get Results of a search form- MySQL PHP - php

Question

I have a joined table and it gives all books of my database. And all books are displaying properly. But I need to work it according to search queries entered in form.
this is my query for join.
$rs = mysqli_query($connection,"SELECT DISTINCT bk.title As Title, YEAR(bk.date_released) AS Year, bk.price AS Price, cat.name AS Category, pub.name AS Publisher, aut.name AS Author,co.name AS Cover, cp.count AS Copies
FROM books bk
JOIN (SELECT book_id, COUNT(*) as count FROM copies GROUP BY book_id) cp
ON bk.id = cp.book_id
JOIN category cat
ON cat.id = bk.category_id
JOIN publishers pub
ON pub.id = bk.publisher_id
JOIN books_covers bk_co
ON bk_co.book_id = bk.id
JOIN covers co
ON co.id = bk_co.cover_id
JOIN books_authors bk_aut
ON bk_aut.book_id = bk.id
JOIN authors aut
ON aut.id = bk_aut.author_id
JOIN books_languages bk_lan
ON bk_lan.book_id = bk.id
JOIN languages lan
ON lan.id = bk_lan.lang_id
JOIN books_locations bk_loc
ON bk_loc.book_id = bk.id
JOIN locations loc
ON loc.id = bk_loc.location_id
ORDER BY bk.title ASC
");
$copies = mysqli_query($connection,"SELECT DISTINCT COUNT(copies.book_id) FROM copies INNER JOIN books ON copies.book_id=books.id
");
$dup = mysqli_query($connection,"SELECT book_id, COUNT(*) as count FROM copies GROUP BY book_id");
$rows_copies = mysqli_fetch_array($copies);
$rows = mysqli_fetch_assoc($rs);
$tot_rows = mysqli_num_rows($rs);
And this is my variables of search form
if(!empty($_GET)){
$title = $_GET['title'];
$author = $_GET['author'];
$isbn = $_GET['isbn'];
$language = $_GET['language'];
$publisher = $_GET['publisher'];
$year = $_GET['year'];
$category = $_GET['category'];
}else{
$title = "";
$author = "";
$isbn = "";
$language = "";
$publisher = "";
$year = "";
$category = "";
$language = "";
}
And this is my code for displaying results,
<div class="jumbo">
<?php if($tot_rows > 0){ ?>
<?php do { ?>
<div class="col-md-3">
<span class="product-image">
<img src="<?php echo $rows['Cover'] ?>" class="img-thumbnail product-img" alt="">
</span>
<ul class="iteminfo">
<li><strong>Title: </strong><?php echo $rows['Title'] ?></li>
<li><strong>Category: </strong><?php echo $rows['Category'] ?></li>
<li><strong>Author: </strong><?php echo $rows['Author'] ?></li>
<li><strong>Price: </strong><?php echo $rows['Price']." Rs" ?></li>
<li><strong>Publisher: </strong><?php echo $rows['Publisher'] ?></li>
<li><strong>Copies: </strong><?php echo $rows['Copies'] ?></li>
</ul>
</div>
<?php } while($rows=mysqli_fetch_assoc($rs)); }else{ ?>
<?php echo 'No Results'; }?>
</div>
How I get results only I searched with corresponding search queries. For an example if I search a book called "Romeo Juliet" I need to display that book only
I tried to test the diplay with this code and never succeed
$titlequery = mysqli_query($connection," SELECT * FROM "$rs" WHERE Title = "$title" ");
$rows = mysqli_fetch_assoc($titlequery);
Help me to solve this.

Answer 1

You're trying to execute a subquery, but the $rs variable you are passing in is a resource, not a string. If you set the original query to a variable and pass that in, then it should work:
$sql = "SELECT DISTINCT bk.title As Title, YEAR(bk.date_released) AS Year, bk.price AS Price, cat.name AS Category, pub.name AS Publisher, aut.name AS Author,co.name AS Cover, cp.count AS Copies
FROM books bk
JOIN (SELECT book_id, COUNT(*) as count FROM copies GROUP BY book_id) cp
ON bk.id = cp.book_id
JOIN category cat
ON cat.id = bk.category_id
JOIN publishers pub
ON pub.id = bk.publisher_id
JOIN books_covers bk_co
ON bk_co.book_id = bk.id
JOIN covers co
ON co.id = bk_co.cover_id
JOIN books_authors bk_aut
ON bk_aut.book_id = bk.id
JOIN authors aut
ON aut.id = bk_aut.author_id
JOIN books_languages bk_lan
ON bk_lan.book_id = bk.id
JOIN languages lan
ON lan.id = bk_lan.lang_id
JOIN books_locations bk_loc
ON bk_loc.book_id = bk.id
JOIN locations loc
ON loc.id = bk_loc.location_id
ORDER BY bk.title ASC
";
$rs = mysqli_query($connection, $query);
$titlequery = mysqli_query($connection, " SELECT * FROM ({$query}) WHERE Title = '{$title}'");
Also, watch your quotation marks in SQL queries when you need to use PHP quotation marks as string delimiters. PHP will interpret your string of " SELECT * FROM "$rs" WHERE Title = "$title" " as SELECT * FROM, the $rs resource, WHERE Title =, the $title variable, and , but without any concatenation. You'd need to backslash your SQL quotations, like " SELECT * FROM \"$rs\" WHERE Title = \"$title\" ", so PHP doesn't think you want to end your string.