Loop for numbering weeks of the year [duplicate] - php

I'm trying to list all months between two dates.
For example; start date is: 2010-12-02 and last date is: 2012-05-06
I want to list something like this:
2010-12
2011-01
2011-02
2011-03
2011-04
.
.
.
2012-04
2012-05
This is what I have tried and it is not working at all:
$year_min = 2010;
$year_max = 2012;
$month_min = 12;
$month_max = 5;
for($y=$year_min; $y<=$year_max; $y++)
{
for($m=$month_min; $m<=$month_max; $m++)
{
$period[] = $y.$m;
}
}

PHP 5.3
$start = new DateTime('2010-12-02');
$start->modify('first day of this month');
$end = new DateTime('2012-05-06');
$end->modify('first day of next month');
$interval = DateInterval::createFromDateString('1 month');
$period = new DatePeriod($start, $interval, $end);
foreach ($period as $dt) {
echo $dt->format("Y-m") . "<br>\n";
}
See it in action
PHP 5.4 or newer
$start = (new DateTime('2010-12-02'))->modify('first day of this month');
$end = (new DateTime('2012-05-06'))->modify('first day of next month');
$interval = DateInterval::createFromDateString('1 month');
$period = new DatePeriod($start, $interval, $end);
foreach ($period as $dt) {
echo $dt->format("Y-m") . "<br>\n";
}
The part where we modify the start and end dates to the first of the month is important. If we didn't, and the current day higher then the last day in February (i.e. 28 in non-leap years, 29 in leap years) this would skip February.

function getMonthsInRange($startDate, $endDate)
{
$months = array();
while (strtotime($startDate) <= strtotime($endDate)) {
$months[] = array(
'year' => date('Y', strtotime($startDate)),
'month' => date('m', strtotime($startDate)),
);
// Set date to 1 so that new month is returned as the month changes.
$startDate = date('01 M Y', strtotime($startDate . '+ 1 month'));
}
return $months;
}

You must make a difference between two months of the same year and two months of different years.
$year_min = substr($row['contractStart'], 0, 4);
$year_max = substr($row['contractEnd'], 0, 4);
$month_min = substr($row['contractStart'], 5, 2);
$month_min = substr($row['contractEnd'], 5, 2);
$period = array();
try {
if ($year_min > $year_max)
throw new Exception();
else if ($year_min == $year_max)
if ($month_min > $month_max)
throw new Exception();
for ($month = $month_min; $month <= $month_max; $month++) {
$period[] = $month . '-' . $year;
}
else {
for ($month = $month_min; $month <= 12; $month++) {
$period[] = $month . '-' . $year_min;
}
for ($year = $year_min + 1; $year < $year_max; $year++) {
for ($month = $month_min; $month <= $month_max; $month++) {
$period[] = $month . '-' . $year;
}
}
for ($month = 1; $month <= $month_max; $month++) {
$period[] = $month . '-' . $year_max;
}
}
implode("<br />\r\n", $period);
}
catch (Exception $e) {
echo 'Start date occurs after end date.'
}
That's for the hard way. Now there is a quick and easy way that is already given as an answer which I recommend you to choose.

This was my solution since DateTime is not available in my server environment.
$a = "2007-01-01";
$b = "2008-02-15";
$i = date("Ym", strtotime($a));
while($i <= date("Ym", strtotime($b))){
echo $i."\n";
if(substr($i, 4, 2) == "12")
$i = (date("Y", strtotime($i."01")) + 1)."01";
else
$i++;
}
Try it out: http://3v4l.org/BZOmb

In Laravel,
$period = \Carbon\CarbonPeriod::create('2017-06-28', '1 month', '2019-06-01');
foreach ($period as $dt) {
echo $dt->format("Y-m") . "<br>\n";
}

October 2021 Update
If you have dates selected by the user, here's a solution
$from = date('Y-m-d', strtotime($_POST['from']));
$to = date('Y-m-d', strtotime($_POST['to']));
$counter = 1;
$max_date = strtotime($to);
$current_date = strtotime($from);
$dates = [];
$months = [];
$loop = true;
while($loop) {
if(strtotime(date('Y-m-d',$current_date)." +".$counter."days") >= $max_date) $loop = false;
else {
$current_date = strtotime(date('Y-m-d', $current_date)." +".$counter."days");
$date = date('Y-m-d', $current_date);
$dates[] = $date;
$months[] = date('Y-m', $current_date);
$counter++;
}
}
$months = array_unique($months);
echo '<pre>';
print_r($dates);
echo '<br>';
print_r($months);
echo '</pre>';

Related

First day between two dates in php

I want to get the first day of the year between two dates, for example if date1 is 2015-02-01 and date2 is 2017-01-07, the answer will be [2015-01-01, 2016-01-01, 2017-01-01]
I have tried the following for the data above:
$date1_rep_val=2015-02-01;
$date2_rep_val=2017-01-07;
$date1=(new DateTime("$date1_rep_val"))->modify('first day of this year');
$date2=(new DateTime("$date2_rep_val"))->modify('first day of this year');
$interval = DateInterval::createFromDateString('1 year');
$period = new DatePeriod($date1, $interval, $date2);
$f_cnt=0;
foreach ($period as $dt)
{
$tick_data[$f_cnt]= $dt->format("Y-m-d");
echo $tick_data[$f_cnt];
$f_cnt++;
}
But, the above code gives only 2015-01-01 and 2016-01-01 it is not giving 2017-01-01 , thanks for any help related to this question.
Why not simply:
$date1 = '2015-02-01';
$date2 = '2017-01-07';
$y1 = substr($date1, 0, 4);
$y2 = substr($date2, 0, 4);
$res= array();
for ($y = $y1; $y <= $y2; $y++) {
$res[] = $y . "-01-01";
}
Alternate (but essentially the same) solution with DateTime type using:
$date1_rep_val='2015-02-01';
$date2_rep_val='2017-01-07';
$date1 = new DateTime($date1_rep_val);
$date2 = new DateTime($date2_rep_val);
$year1 = $date1->format('Y');
$year2 = $date2->format('Y');
$newYearsDates = [];
if (new DateTime($year1 . '-01-01') == $date1) {
$newYearsDates[] = $date1;
}
if ($year2 > $year1) {
for ($year = $year1 + 1; $year <= $year2; $year++) {
$newYearsDates[] = new DateTime($year . '-01-01');
}
}
print_r($newYearsDates);

how to display months in descending order starting with current month in php [duplicate]

I'm trying to list all months between two dates.
For example; start date is: 2010-12-02 and last date is: 2012-05-06
I want to list something like this:
2010-12
2011-01
2011-02
2011-03
2011-04
.
.
.
2012-04
2012-05
This is what I have tried and it is not working at all:
$year_min = 2010;
$year_max = 2012;
$month_min = 12;
$month_max = 5;
for($y=$year_min; $y<=$year_max; $y++)
{
for($m=$month_min; $m<=$month_max; $m++)
{
$period[] = $y.$m;
}
}
PHP 5.3
$start = new DateTime('2010-12-02');
$start->modify('first day of this month');
$end = new DateTime('2012-05-06');
$end->modify('first day of next month');
$interval = DateInterval::createFromDateString('1 month');
$period = new DatePeriod($start, $interval, $end);
foreach ($period as $dt) {
echo $dt->format("Y-m") . "<br>\n";
}
See it in action
PHP 5.4 or newer
$start = (new DateTime('2010-12-02'))->modify('first day of this month');
$end = (new DateTime('2012-05-06'))->modify('first day of next month');
$interval = DateInterval::createFromDateString('1 month');
$period = new DatePeriod($start, $interval, $end);
foreach ($period as $dt) {
echo $dt->format("Y-m") . "<br>\n";
}
The part where we modify the start and end dates to the first of the month is important. If we didn't, and the current day higher then the last day in February (i.e. 28 in non-leap years, 29 in leap years) this would skip February.
function getMonthsInRange($startDate, $endDate)
{
$months = array();
while (strtotime($startDate) <= strtotime($endDate)) {
$months[] = array(
'year' => date('Y', strtotime($startDate)),
'month' => date('m', strtotime($startDate)),
);
// Set date to 1 so that new month is returned as the month changes.
$startDate = date('01 M Y', strtotime($startDate . '+ 1 month'));
}
return $months;
}
You must make a difference between two months of the same year and two months of different years.
$year_min = substr($row['contractStart'], 0, 4);
$year_max = substr($row['contractEnd'], 0, 4);
$month_min = substr($row['contractStart'], 5, 2);
$month_min = substr($row['contractEnd'], 5, 2);
$period = array();
try {
if ($year_min > $year_max)
throw new Exception();
else if ($year_min == $year_max)
if ($month_min > $month_max)
throw new Exception();
for ($month = $month_min; $month <= $month_max; $month++) {
$period[] = $month . '-' . $year;
}
else {
for ($month = $month_min; $month <= 12; $month++) {
$period[] = $month . '-' . $year_min;
}
for ($year = $year_min + 1; $year < $year_max; $year++) {
for ($month = $month_min; $month <= $month_max; $month++) {
$period[] = $month . '-' . $year;
}
}
for ($month = 1; $month <= $month_max; $month++) {
$period[] = $month . '-' . $year_max;
}
}
implode("<br />\r\n", $period);
}
catch (Exception $e) {
echo 'Start date occurs after end date.'
}
That's for the hard way. Now there is a quick and easy way that is already given as an answer which I recommend you to choose.
This was my solution since DateTime is not available in my server environment.
$a = "2007-01-01";
$b = "2008-02-15";
$i = date("Ym", strtotime($a));
while($i <= date("Ym", strtotime($b))){
echo $i."\n";
if(substr($i, 4, 2) == "12")
$i = (date("Y", strtotime($i."01")) + 1)."01";
else
$i++;
}
Try it out: http://3v4l.org/BZOmb
In Laravel,
$period = \Carbon\CarbonPeriod::create('2017-06-28', '1 month', '2019-06-01');
foreach ($period as $dt) {
echo $dt->format("Y-m") . "<br>\n";
}
October 2021 Update
If you have dates selected by the user, here's a solution
$from = date('Y-m-d', strtotime($_POST['from']));
$to = date('Y-m-d', strtotime($_POST['to']));
$counter = 1;
$max_date = strtotime($to);
$current_date = strtotime($from);
$dates = [];
$months = [];
$loop = true;
while($loop) {
if(strtotime(date('Y-m-d',$current_date)." +".$counter."days") >= $max_date) $loop = false;
else {
$current_date = strtotime(date('Y-m-d', $current_date)." +".$counter."days");
$date = date('Y-m-d', $current_date);
$dates[] = $date;
$months[] = date('Y-m', $current_date);
$counter++;
}
}
$months = array_unique($months);
echo '<pre>';
print_r($dates);
echo '<br>';
print_r($months);
echo '</pre>';

Why this list just go up to september?

I have this code
<?php
$startYear = 2011;
while ($startYear <= date('Y')) {
echo "$startYear <br>";
for ($m=1; $m<=12; $m++) {
$theDate = $startYear . $m;
if ($theDate <= date('Yn')) {
$month = date('F', mktime(0,0,0,$m, 1, $startYear));
echo $month. '<br>';
}
}
$startYear++;
};
?>
because I would like to write a list of the type
2013
January
February
March
April
May
June
July
August
September
October
November
December
until the current year and the present month
but every list of months of every year just goes until september, why?
You have to change your if statement from this:
if ($theDate <= date('Yn')) {
to this:
if ($theDate <= date('Ym')) {
//^ See here the placeholder for month with leading zero
For more information about date() see the manual: http://php.net/manual/en/function.date.php
Because 201410 > 21049. This is what happens when you use date() for date math for which it is not suited.
DateTime() and its related functions are better suited for this:
$startYear = 2011;
$start = (new DateTime())->setDate($startYear,1,1);
$end = (new DateTime())->setDate($startYear,1,1)->modify('+1 year');
$interval = new DateInterval('P1M');
$period = new DatePeriod($start, $interval, $end);
foreach ($period as $dt) {
echo $dt->format('F') . "\n";
}
Demo
If you're using PHP 5.5+ it is a little cleaner
$startYear = 2011;
$start = (new DateTimeImmutable())->setDate($startYear,1,1);
$end = $start->modify('+1 year');
$interval = new DateInterval('P1M');
$period = new DatePeriod($start, $interval, $end);
foreach ($period as $dt) {
echo $dt->format('F') . "\n";
}
Demo
i edited my code to add a leading zero to the variable who will represent the month number, edited the current date from date('Yn') to date('Ym') and works.
<?php
$startYear = 2011;
while ($startYear <= date('Y')) {
echo "$startYear <br>";
for ($m=1; $m<=12; $m++) {
$f = sprintf('%02d', $m);
$theDate = $startYear . $f;
if ($theDate <= date('Ym')) {
$month = date('F', mktime(0,0,0,$f, 1, $startYear));
echo $month. '<br>';
}
}
$startYear++;
};
?>
Thanks for the answer guys.

How to list all months between two dates

I'm trying to list all months between two dates.
For example; start date is: 2010-12-02 and last date is: 2012-05-06
I want to list something like this:
2010-12
2011-01
2011-02
2011-03
2011-04
.
.
.
2012-04
2012-05
This is what I have tried and it is not working at all:
$year_min = 2010;
$year_max = 2012;
$month_min = 12;
$month_max = 5;
for($y=$year_min; $y<=$year_max; $y++)
{
for($m=$month_min; $m<=$month_max; $m++)
{
$period[] = $y.$m;
}
}
PHP 5.3
$start = new DateTime('2010-12-02');
$start->modify('first day of this month');
$end = new DateTime('2012-05-06');
$end->modify('first day of next month');
$interval = DateInterval::createFromDateString('1 month');
$period = new DatePeriod($start, $interval, $end);
foreach ($period as $dt) {
echo $dt->format("Y-m") . "<br>\n";
}
See it in action
PHP 5.4 or newer
$start = (new DateTime('2010-12-02'))->modify('first day of this month');
$end = (new DateTime('2012-05-06'))->modify('first day of next month');
$interval = DateInterval::createFromDateString('1 month');
$period = new DatePeriod($start, $interval, $end);
foreach ($period as $dt) {
echo $dt->format("Y-m") . "<br>\n";
}
The part where we modify the start and end dates to the first of the month is important. If we didn't, and the current day higher then the last day in February (i.e. 28 in non-leap years, 29 in leap years) this would skip February.
function getMonthsInRange($startDate, $endDate)
{
$months = array();
while (strtotime($startDate) <= strtotime($endDate)) {
$months[] = array(
'year' => date('Y', strtotime($startDate)),
'month' => date('m', strtotime($startDate)),
);
// Set date to 1 so that new month is returned as the month changes.
$startDate = date('01 M Y', strtotime($startDate . '+ 1 month'));
}
return $months;
}
You must make a difference between two months of the same year and two months of different years.
$year_min = substr($row['contractStart'], 0, 4);
$year_max = substr($row['contractEnd'], 0, 4);
$month_min = substr($row['contractStart'], 5, 2);
$month_min = substr($row['contractEnd'], 5, 2);
$period = array();
try {
if ($year_min > $year_max)
throw new Exception();
else if ($year_min == $year_max)
if ($month_min > $month_max)
throw new Exception();
for ($month = $month_min; $month <= $month_max; $month++) {
$period[] = $month . '-' . $year;
}
else {
for ($month = $month_min; $month <= 12; $month++) {
$period[] = $month . '-' . $year_min;
}
for ($year = $year_min + 1; $year < $year_max; $year++) {
for ($month = $month_min; $month <= $month_max; $month++) {
$period[] = $month . '-' . $year;
}
}
for ($month = 1; $month <= $month_max; $month++) {
$period[] = $month . '-' . $year_max;
}
}
implode("<br />\r\n", $period);
}
catch (Exception $e) {
echo 'Start date occurs after end date.'
}
That's for the hard way. Now there is a quick and easy way that is already given as an answer which I recommend you to choose.
This was my solution since DateTime is not available in my server environment.
$a = "2007-01-01";
$b = "2008-02-15";
$i = date("Ym", strtotime($a));
while($i <= date("Ym", strtotime($b))){
echo $i."\n";
if(substr($i, 4, 2) == "12")
$i = (date("Y", strtotime($i."01")) + 1)."01";
else
$i++;
}
Try it out: http://3v4l.org/BZOmb
In Laravel,
$period = \Carbon\CarbonPeriod::create('2017-06-28', '1 month', '2019-06-01');
foreach ($period as $dt) {
echo $dt->format("Y-m") . "<br>\n";
}
October 2021 Update
If you have dates selected by the user, here's a solution
$from = date('Y-m-d', strtotime($_POST['from']));
$to = date('Y-m-d', strtotime($_POST['to']));
$counter = 1;
$max_date = strtotime($to);
$current_date = strtotime($from);
$dates = [];
$months = [];
$loop = true;
while($loop) {
if(strtotime(date('Y-m-d',$current_date)." +".$counter."days") >= $max_date) $loop = false;
else {
$current_date = strtotime(date('Y-m-d', $current_date)." +".$counter."days");
$date = date('Y-m-d', $current_date);
$dates[] = $date;
$months[] = date('Y-m', $current_date);
$counter++;
}
}
$months = array_unique($months);
echo '<pre>';
print_r($dates);
echo '<br>';
print_r($months);
echo '</pre>';

How can I get a range of dates in php?

$start_date = '2012-01-01';
$end_date = '2012-12-31';
$total_days = round(abs(strtotime($end_date) - strtotime($start_date)) / 86400, 0) + 1;
if ($end_date >= $start_date)
{
for ($day = 0; $day < $total_days; $day++)
{
echo "<br />" . date("Y-m-d", strtotime("{$start_date} + {day} days"));
}
}
Right now that's printing '1969-12-31' over and over. The expected output should be:
2012-01-01
2012-01-02
2012-01-03
...
2012-12-30
2012-12-31
I would use the DatePeriod class (along with DateTime and DateInterval) for this:
$start_date = '2012-01-01';
$end_date = '2012-12-31';
$start = new DateTime($start_date);
$end = new DateTime($end_date);
$interval = new DateInterval('P1D'); // 1 day interval
$period = new DatePeriod($start, $interval, $end);
foreach ($period as $day) {
// Do stuff with each $day...
echo $day->format('Y-m-d'), "\n";
}
You above code will work with one extra character - you missed a $ on this line:
echo "<br />" . date("Y-m-d", strtotime("{$start_date} + {$day} days"));
// ^ This was missing
<?php
$start_date = '2012-01-01';
$end_date = '2012-12-31';
$total_days = round(abs(strtotime($end_date) - strtotime($start_date)) / 86400, 0) + 1;
if ($end_date >= $start_date)
{
for ($day = 0; $day < $total_days; $day++)
{
echo "<br />" . date("Y-m-d", strtotime("{$start_date} + {$day} days"));
// You missed the $ here ^
}
}

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