I need to search filtering different columns from DB table, those filtering columns are groupA, groupb and groupC, each column has one of following values high, low, moderate in db table
But front end user have anther value called "none", but that value is not contain in database.
This is my current query
public function show($groupA, $groupB, $groupC)
{
$FodMaps = FodMap::where('groupA', '=', $groupA)->where('groupB', '=', $groupB)->where('groupC', '=', $groupC)->get();
return $FodMaps;
}
What I want is if user search with value which does not contain in db (high/low/moderate) it should search the other columns except the one which have unmatching values
ex: http://url/api/fodmap/groupA=low/groupB=low/groupC=high
if user enter above way it should display the results according to the values
but if user inputs like following
http://url/api/fodmap/groupA=low/groupB=low/groupC=none
since "none" value in groupC column does not exit it should search only other two columns without considering the value of groupC
please advice
You can add query condition dynamically like this.
public function show($groupA, $groupB, $groupC)
{
$query = FodMap::query();
if ($groupA !== 'none') {
$query->where('groupA', '=', $groupA)
}
if ($groupB !== 'none') {
$query->where('groupB', '=', $groupB)
}
if ($groupC !== 'none') {
$query->where('groupC', '=', $groupC)
}
return $query->get();
}
Related
Currently I'm working on a ajax search filters on Laravel, but I cannot get the correct info, this is the scenario:
I have 2 tables:
Table1: SoftwareRequest
Table2: DenyCategory
with a select option I get the name as Value
and I added that select option like in top of the query on the controller function:
$deniedReason = $request->get('deniedReason');
if($deniedReason == "All"){
$deniedReason = "";
}
So that means that every time I select "All" it will be empty so I can get all data like empty (this is the problem).
This is my current query:
$request_data = SoftwareRequest::leftJoin('DenyCategory', 'SoftwareRequest.DenyCategoryId', '=', 'DenyCategory.Id')->where('DenyCategory.Name', 'like', '%' . $deniedReason . '%')->paginate(20);
So the thing is that if I select another option rather than "All", for example "Already Available", I do get the excepted data, meaning all objects from table 1 joined with table 2 that has that option, but the problem comes when I select "All" it doesn't bring all the data it should and that's because not all objects have DenyCategoryId in Table1 meaning that some of those are Null/empty so it only brings the ones 'LIKE' Null/empty as I specified on the previous code block.
$deniedReason = $request->get('deniedReason');
if($deniedReason == "All"){
$deniedReason = "";
}
How can I get all data empty or not empty when I select the option All and as well as to get the data when I select another option? I bet it would have something to do with the query not being 'Like' but that's out of my knowledge scope.
Why not make the where clause optional?
$queryBuilder = SoftwareRequest::leftJoin('DenyCategory', 'SoftwareRequest.DenyCategoryId', '=', 'DenyCategory.Id')
// Only apply where-clause when denied reason has been provided.
if ($request->get('deniedReason') !== 'All') {
$queryBuilder = $queryBuilder->where('DenyCategory.Name', 'like', '%' . $deniedReason . '%');
}
$request_data = $queryBuilder->paginate(20);
I think you can improve your code a bit better but I'll leave that up to you with some pointers:
Eloquent relationships
Class Constants
I have an application where I want to fetch parent records based on children conditionals. Current problem is that I have Students, where they have multiple study fields and study fields belong to one faculty. Pivot table students_study_fields has attribute study_status_id.
What I need is, for example, fetch all students and their study fields which belongs to "prf" faculty AND pivot has study_status_id = 1.
So I write a query like this.
return Student::with(['studyfields' => function ($query1) use ($studyStatusId, $facultyAbbreviation) {
$query1->whereHas('pivot', function ($query2) use ($studyStatusId, $facultyAbbreviation) {
$query2->where('study_status_id', $studyStatusId);
});
$query1->whereHas('studyprogram', function ($query4) use ($facultyAbbreviation) {
$query4->whereHas('faculty', function ($query5) use ($facultyAbbreviation) {
$query5->where('abbreviation', $facultyAbbreviation);
});
});
}])->get();
But this query fetch students witch study_status_id = 2 as well because exists record where this same study field (its code) has relation with student, where study_status_id = 1.
So I don't want to include this studyfield if somewhere exists record with status = 1 in pivot but only if has status = 1 for current row
You need to chain the queries...
return Student::with(['studyfields' => function ($query1) use ($studyStatusId, $facultyAbbreviation) {
$query1->whereHas('pivot', function ($query2) use ($studyStatusId, $facultyAbbreviation) {
$query2->where('study_status_id', $studyStatusId);
})->whereHas('studyprogram', function ($query4) use ($facultyAbbreviation) {
$query4->whereHas('faculty', function ($query5) use ($facultyAbbreviation) {
$query5->where('abbreviation', $facultyAbbreviation);
});
});
}])->get();
Otherwise it will re-start the query1 so you won't get AND kind of query, only get the second part
Side Note: However, I want to warn you that whereHas is a slow query if you have many rows as it goes through each value. I personally prefer grabbing the ids with simple ->where queries and utilise ->whereIn approach.
I found solution for my situation
$students = Student::with(['studyfields' => function ($q) use ($studyStatusId) {
$q->whereHas('pivot')->where('study_status_id', $studyStatusId);
}])
->whereHas('studyfields', function ($q) use ($facultyAbbreviation) {
$q->whereHas('studyprogram', function ($q) use ($facultyAbbreviation) {
$q->where('faculty_abbreviation', $facultyAbbreviation);
});
})
->get();
$students = $students->filter(function ($student) {
return count($student->studyfields) > 0;
})->values();
Query above fetch all students from specific faculty and if studyfields array doesn't contains specific study_status, leave empty array so later I can filter collection from empty arrays assuming that each student belongs to at least one studyfield.
I'm new to Laravel and here's my issue.
I have a table currentpercentage.
This is the structure of the table currentpercentage
currentpercentage(**id**, name, total_cap, current_usage, created_at, updated_at)
I'm trying to calculate percentage of current usage; based on total_cap and current usage.
total_cap = 1000,
current_usage = 237,
name = User Name
In my controller i've setup a query to get the value of total_cap and the value of current_usage then calculate that the percentage would be.
When i call my query, it returns an array with the column name (total_cap) and value (1000). Same as when i query for current_usage.
{
"currentpercentage": [
{
"total_cap": 1000
}
]
}
I just want the query to return just the number (1000) without the array.
This is my query
$totalcap = CurrentPercentageModel::select('total_cap')->where('name', '=', 'User Name')->get();
How do I just get the value. Or is there an easier way to calculate the percentage from one query?
CurrentPercentageModel //What I use to connect to the database. DB Model
The problem is that you are using the get method which returns a collection even when you only have one row.
$totalcap = CurrentPercentageModel::select('total_cap')->where('name', '=', 'User Name')->get();
If you just want one record and one column value, then use the value method to get just the value of the column, more info here (you might have to scroll a little bit)
$totalcap = CurrentPercentageModel::select('total_cap')->where('name', '=', 'User Name')->value('total_cap');
I'm trying to retrieve single column from my table grades.
For that I have used following code in my controller:
public function verify($id,$sid)
{
$grade=Grade::all('annual')->whereLoose('id',$id);
return $grade;
}
Where, annual is column name. But it is returning empty set of array [].
all() takes a list of columns to load from the database. In your case, you're fetching only one column called annual, therefore filtering on id later on does not return results. Replace your code with the following and it should work:
$grade = Grade::all('id', 'annual')->whereLoose('id', $id);
Keep in mind that it will return a collection of objects, not a single object.
NOTE: you're always loading all Grade objects from the database which is not efficient and not necessary. You can simply fetch object with given id with the following code:
$grade = Grade::find($id); // fetch all columns
$grade = Grade::find($id, ['id', 'annual']); // fetch only selected columns
The code you are using is loading all rows from the grades table and filtering them in code. It is better to let your query do the filter work.
For the columns part, you can add the columns you need to the first() function of the query, like so:
public function verify($id,$sid)
{
$grade = Grade::where('id', $id)->first(['annual']);
return $grade->annual;
}
I presently have 3 tables: Shows, Genres and Show_Genre (associates the two). I have a search form that submits a series of checkboxes with values into an array based on what genres they selected. Presently I want to associate the Shows table and the Genres table into a variable and run a query against it once for every genre checkbox selected. Then, once the selection is filtered, I can display the resulting Show objects that matched the users parameters.
My present setup is the following
public function searchShows(SearchRequest $request)
{
//$ShowsWithGenres give a collection inside a collection which I can't seem to even access its values without doing a bunch of ugly code using count() in a for loop
$ShowsWithGenres = Show::with('genres')->get();
$genres = $request->name;
if(isset($genres))
{
foreach($genres as $genre)
{
//iterate against the selection repeatedly reducing the number of results
}
}
}
Thanks.
You should use whereHas() and whereIn.
Perhaps something like this should do it:
$shows = Show::whereHas('genres', function($q) use($genre_ids)
{
$q->whereIn('id', $genre_ids);
})->get();
EDIT
Try this, however I'm unsure about the performance.
$query= Show::query();
foreach($genre_ids as $id){
$query->whereHas('genres', function($q) use($id)
{
$q->where('id', $id);
})
}
$shows = $query->get();
Using Eloquents whereHas() function you can query results based on the relation's data. http://laravel.com/docs/5.0/eloquent#querying-relations
public function searchShows(SearchRequest $request)
{
// Start a query (but don't execute it at this point as we may want to add more)
$query = Show::with('genres');
$genreNames = (array) $request->name;
// Check there are some genre names, if theres not any it'll cause an SQL syntax error
if (count($genreNames) > 0)
{
$query->whereHas('genres', function($subQuery) use ($genreNames)
{
$subQuery->whereIn('genre_name', $genreNames);
}
}
// Finally execute the query. $shows now contains only shows with the genres that the user has searched for, if they didn't search with any genres, then it contains all the results.
$shows = $query->get();
}