PHP / MySQL: Login form doesn't work - php

Question

I've got a login.php file which looks like this:
include "myfuncs.php";
$connect = dbConnection();
$username = $_POST["username"];
$passwort = md5($_POST["password"]);
$query = "SELECT username, password FROM user WHERE username LIKE '$username' LIMIT 1";
$ergebnis = mysql_query($query);
$row = mysql_fetch_object($result);
if($row->password == $passwort)
{
echo "Hi $username";
$_SESSION["username"] = $username;
echo "Login successfully";
}
else
{
echo "Login doesn't work";
}
and a myfuncs.php file which looks like this:
function dbConnection()
{
$servername = "...";
$username = "...";
$password = "...";
$dbname = "...";
$db_connect = new mysqli($servername, $username, $password, $dbname);
if ($db_connect->connect_error)
{
die("Connection failed: " . $db_connect->connect_error);
}
return $db_connect;
}
Unfortunately the login form doesn't work - it always gives the error "Login doesn't work" even when the username and password matches with the database entry.

Answer 1

Arg, you are mixing a mysqli with class mysql functions. I dont think it works...
It works this way : PHP MySQLI
$stmt = $mysqli->prepare($query)
while ($stmt->fetch()) {
(...)
}

Answer 2

I see you have error in your variable name in line #6.
try this:
$query = "SELECT username, password FROM user WHERE username LIKE '$username' LIMIT 1";
$result= mysql_query($query);
$row = mysql_fetch_object($result);

Answer 3

There are several problems with your code. In myfuncs.php you use mysqli and after that, in your code you use mysql (without "i"). mysql (without "i") is deprecated, so you should use mysqli everywhere.
More than that, in your code you have:
$query = "SELECT username, password FROM user WHERE username LIKE '$username' LIMIT 1";
$ergebnis = mysql_query($query);
$row = mysql_fetch_object($result);
Please see the bold text from next two lines (it should be the same variable):
$ergebnis = mysql_query($query);
$row = mysql_fetch_object($result);
You should have
$result = mysql_query($query);
if you will use mysql.