How do I handle variables from POST requests? Lets say I have tables like this And I want to update the votes variable wherever a specific id is.
So for the code I have this
$vote = $_POST["votes"];
$sentid = $_POST["sentid"];
along with something like this
UPDATE `my_exampleo202s`.`President Candidates` SET votes = votes + 1 WHERE `President Candidates`.`id` = sentid
And in the post request I send the sentid with a number. sentid=3
This doesn't work though. I'm not able to give any errors or anything because I'm not viewing it from a browser.
Any idea what the proper way is that I'm supposed to do this?
(Here's the code I have right now if it's needed)
<?php
$vote = $_POST["votes"];
$sentid = $_POST["sentid"];
$conn = new mysqli("localhost","exampleo202s","","my_exampleo202s");
if ($conn->connect_error) {
die("Connection failed: " . $conn->connect_error);
}
$sql = "UPDATE `my_exampleo202s`.`President Candidates` SET votes = votes + 1 WHERE `President Candidates`.`id` = sentid";
if ($conn->query($sql) === TRUE) {
echo "<br>Record updated successfully <br>";
} else {
echo "<br>Error updating record: <br>" . $conn->error;
}
$conn->close();
?>
UPDATE
<?php
$vote = $_POST["votes"];
$sentid = $_POST["sentid"];
$conn = new mysqli("localhost","jusavoting10rxx9s3","","my_jusavoting10rxx9s3");
if ($conn->connect_error) {
die("Connection failed: " . $conn->connect_error);
}
$sql = "UPDATE `my_jusavoting10rxx9s3`.`President Candidates` SET votes = votes + 1 WHERE `President Candidates`.`id` = $sentid";
if ($conn->query($sql) === TRUE) {
echo "<br>Record updated successfully <br>";
} else {
echo "<br>Error updating record: <br>" . $conn->error;
}
$conn->close();
?>
Try echo your $_POST value if it doesn't work:
<?php
$vote = $_POST["votes"];
$sentid = $_POST["sentid"];
$conn = new mysqli("localhost","exampleo202s","","my_exampleo202s");
if ($conn->connect_error) {
die("Connection failed: " . $conn->connect_error);
}
$sql = "UPDATE `my_exampleo202s`.`President Candidates` SET votes = votes + 1 WHERE `President Candidates`.`id` = $sentid";
if ($conn->query($sql) === TRUE) {
echo "<br>Record updated successfully <br>";
} else {
echo "<br>Error updating record: <br>" . $conn->error;
}
$conn->close();
?>
Related
This is the code I'm using for deleting row from my DB:
<?php
$eid = $_GET['eid'];
$con = mysqli_connect("localhost", "root", "","project") or die("Connection failed");
echo "connection is done";
$query = "delete from exam where eid='$eid'";
if ($con->query($query)==TRUE)
{
echo " record deleted";
}
else
{
echo "Error: " . $query . "<br>" . $con->error;
}
$con->close();
?>
The else statement is not getting executed. It displays "record deleted" for every value even if the value is not found in the database.
Why is this happening? how can I verify that my record has been deleted from my DB?
You can use mysqli.affected-rows.
Consider the following:
$query="delete from exam where eid='$eid'";
if ($con->query($query)==TRUE && $con->affected_rows > 0) {
echo " record deleted";
} else {
echo "Error: " . $query . "<br>" . $con->error;
}
<?php
include('session.php');
?>
<?php
$conn = new mysqli("127.0.0.1","root","","foo");
if ($conn->connect_errno) {
echo "Failed to connect to MySQL: (" . $conn->connect_errno . ") " . $conn->connect_error;
}
$sew = $_SESSION['login_user'];
$a = $_GET["en"];
$l = 1;
$d = -1;
if($a == 1)
{
$sqlw = " INSERT into dlkeuser VALUES('$a','$sew')" ;
if ($conn->query($sqlw) === FALSE)
{
echo "you have already disliked the song";
}
else
{
//query1
$sql = " DELETE FROM lkeuser WHERE userid = '$sew' AND songid = '$a' ";
//query2
$sql = "UPDATE liking
SET count = count - 1 ";
if ($conn->query($sql) === TRUE) {
echo "you disliked the song";
}
else {
echo "Error: " . $sql . "<br>" . $conn->error;
}
}
In this php code snippet, query1 is not working whereas query 2 is fine.
I am trying to insert (songid, userid) in dlkeuser(dislike) table against user i/p($_GET["en"]) and delete the record(songid,userid) from lkeuser(like) table if it exists. (songid,userid) pair is the composite primary key here. count is the net like/dislike of a song.
let's try this,
it will work
<?php
include('session.php');
?>
<?php
$conn = new mysqli("127.0.0.1","root","","foo");
if ($conn->connect_errno) {
echo "Failed to connect to MySQL: (" . $conn->connect_errno . ") " . $conn->connect_error;
}
$sew = $_SESSION['login_user'];
$a = $_GET["en"];
$l = 1;
$d = -1;
if($a == 1)
{
$sqlw = " INSERT into dlkeuser VALUES('$a','$sew')";
if ($conn->query($sqlw) === FALSE)
{
echo "you have already disliked the song";
}
else
{
//query1
$sql = " DELETE FROM lkeuser WHERE userid = '$sew' AND songid = '$a' " ;
//query2
$sql1 = "UPDATE liking
SET count = count - 1 ";
if ($conn->query($sql) === TRUE) {
echo "deleted the song";
}
if ($conn->query($sql1) === TRUE) {
echo "you disliked the song";
}
else {
echo "Error: " . $sql . "<br>" . $conn->error;
}
}
You need to execute query1, before reuse your $sql variable.
//query1
$sql = " DELETE FROM lkeuser WHERE userid = '$sew' AND songid = '$a' " ;
$conn->query($sql);
//query2
$sql = "UPDATE liking
SET count = count - 1 ";
if ($conn->query($sql) === TRUE) {
You are not executing your query1 anywhere. Just the following code won't execute your query
$sql = " DELETE FROM lkeuser WHERE userid = '$sew' AND songid = '$a' " ;
You need another line like the following (as you did for query2)
if ($conn->query($sql) === TRUE) {
echo "you liked the song";
}
else {
echo "Error: " . $sql . "<br>" . $conn->error;
}
This executes the query and also checks for errors.
I wrote the following code:
<?php
$servername = "domain";
$insert = 12345678;
$username = "user";
$password = "password";
$dbname = "database";
// Create connection
$conn = new mysqli($servername, $username, $password, $dbname);
// Check connection
if ($conn->connect_error) {
die("Connection failed: " . $conn->connect_error);
}
$sql = "SELECT quantity FROM Eshop WHERE id = $insert";
$result = $conn->query($sql);
echo $result;
if ($result > 0) {
$result = $result + 1;
$sql2 = "UPDATE Eshop SET quantity = $result WHERE id = $insert";
if ($conn->query($sql2) === TRUE) {
echo "New record created successfully";
} else {
echo "Error: " . $sql2 . "<br>" . $conn->error;
}
} else {
$sql3 = "INSERT INTO Eshop (id, quantity) VALUES ($insert, 1)";
if ($conn->query($sql3) === TRUE) {
echo "New record created successfully";
} else {
echo "Error: " . $sql3 . "<br>" . $conn->error;
}
}
?>
What I want this script to do is select the quantity where the id is $insert and then if quantity > 0, add 1 to the quantity and update the quantity, if not insert the id and quantity = 1 into the table. The table has only two fields id(VARCHAR(32)) and quantity(DECIMAL(8,1)). I tried to do it more general in order to help as many people as possible. Could you please help me? Thanks in advance. NOTE: When I run the script in the browser(after uploading it to the server with the correct username,domain etc.) nothing shows up and I dont even get an error in the console.
You need to extract the result of your query and loop through each row:
<?php
$servername = "domain";
$insert = 12345678;
$username = "user";
$password = "password";
$dbname = "database";
// Create connection
$conn = new mysqli($servername, $username, $password, $dbname);
// Check connection
if ($conn->connect_error) {
die("Connection failed: " . $conn->connect_error);
}
$sql = "SELECT quantity FROM Eshop WHERE id = $insert";
$result = $conn->query($sql);
while($row = mysqli_fetch_array($result)) {
if ($row['quantity'] > 0) {
$new_quantity = $row['quantity'] + 1;
$sql2 = "UPDATE Eshop SET quantity = '$new_quantity' WHERE id = '$insert'";
if ($conn->query($sql2) == TRUE) {
echo "New record created successfully";
} else {
echo "Error: " . $sql2 . "<br>" . $conn->error;
}
} else {
$sql3 = "INSERT INTO Eshop (id, quantity) VALUES ('$insert', 1)";
if ($conn->query($sql3) == TRUE) {
echo "New record created successfully";
} else {
echo "Error: " . $sql3 . "<br>" . $conn->error;
}
}
}
?>
<?php
$servername = "domain";
$insert = 12345678;
$username = "user";
$password = "password";
$dbname = "database";
// Create connection
$conn = new mysqli($servername, $username, $password, $dbname);
// Check connection
if ($conn->connect_error) {
die("Connection failed: " . $conn->connect_error);
}
$sql = "SELECT quantity FROM Eshop WHERE id = $insert";
$result = $conn->query($sql);
//check if particular record exists or not
$count=mysql_num_rows($result);
if($count>0) // if records exists for the particular id
{
while($row = mysqli_fetch_array($result)) {
if ($row['quantity'] > 0) {
$new_quantity = $row['quantity'] + 1;
$update = "UPDATE Eshop SET quantity = '$new_quantity' WHERE id = '$insert'";
if ($conn->query($update ) == TRUE) {
echo "New record created successfully";
} else {
echo "Error: " . $update . "<br>" . $conn->error;
}
} else {
$insert = "INSERT INTO Eshop (id, quantity) VALUES ('$insert', 1)";
if ($conn->query($insert ) === TRUE) {
echo "New record created successfully";
} else {
echo "Error: " . $insert . "<br>" . $conn->error;
}
} // else qty is <=0
} //end while
}
else {
echo "Records do not exists for that particular id";
}
?>
I read in data from a csv file, and want to insert it into my database. The issue is that it only inserts the last row in the CSV file each time. However when i print my $sq1 to screen it shows all 48 inserts with the different values that they should have. Could anyone tell me why it only inserts one row into the database?
<?php
// Did modify login values for privacy
$servername = "10.100.";
$username = "myusername";
$password = "abc123";
$dbname = "informationdata";
// Create connection
$conn = new mysqli($servername, $username, $password, $dbname);
// Check connection
if ($conn->connect_error) {
die("Connection failed: " . $conn->connect_error);
}
$file = fopen("ALMGrade.csv","r");
while(! feof($file)){
$ar =fgetcsv($file);
$sql = "INSERT INTO gradetable_copy (Grade, Grade1, Grade2, Grade3, Grade4, Grade5, Grade6)
VALUES ('$ar[0]', '$ar[1]', '$ar[2]', '$ar[3]', '$ar[4]', '$ar[5]', '$ar[6]' )";
echo $sql;
echo "<br>";
}
fclose($file);
if ($conn->query($sql) === TRUE) {
echo "New record created successfully";
} else {
echo "Error: " . $sql . "<br>" . $conn->error;
}
$conn->close();
?>
move the execution of query ($conn->query($sql) ) inside while:
while(! feof($file))
{
$ar =fgetcsv($file);
$sql = "INSERT INTO gradetable_copy (Grade, Grade1, Grade2, Grade3, Grade4, Grade5, Grade6)
VALUES ('$ar[0]', '$ar[1]', '$ar[2]', '$ar[3]', '$ar[4]', '$ar[5]', '$ar[6]' )";
echo $sql;
echo "<br>";
if ($conn->query($sql) === TRUE)
{
echo "New record created successfully";
}
else
{
echo "Error: " . $sql . "<br>" . $conn->error;
}
}
fclose($file);
When I print my code it only prints the question and description of id = 1 but not the rest of the table.
here is my code.
Please show me how to print my entire table which has like 20 questions or so...and also please show me how to make it so that the questions stay on the browser (even when I refresh the page) because currently the data does not stay on the browser when i refresh the page.
Thanks So Much!
<?php
require_once "connection.php";
if(isset($_POST['submit'])) {
$conn = new mysqli(DB_HOST, DB_USER, DB_PASS, DB_NAME );
if($conn->connect_error) {
die("connection error: " . $conn->connect_error);
} else {
echo "Submit button connected to database!";
}
$question = $_POST['question'];
$description = $_POST['description'];
$sql = " INSERT INTO `ask` (question_id, question, description) VALUES
(NULL, '{$question}', '{$description}' ) ";
if($conn->query($sql)) {
echo "it worked";
} else {
echo "error: " . $conn->error;
exit();
}
$query = "SELECT * FROM `ask` ";
if( $result = $conn->query($query)) {
$fetch = $result->fetch_assoc();
echo "<p>{$fetch['question']}</p>";
echo "<p>{$fetch['description']}</p>";
} else {
echo "failed to fetch array";
}
}
?>
You need a for each loop:
<?php
require_once "connection.php";
if(isset($_POST['submit'])) {
$conn = new mysqli(DB_HOST, DB_USER, DB_PASS, DB_NAME );
if($conn->connect_error) {
die("connection error: " . $conn->connect_error);
} else {
echo "Submit button connected to database!";
}
$question = $_POST['question'];
$description = $_POST['description'];
$sql = " INSERT INTO `ask` (question_id, question, description) VALUES
(NULL, '{$question}', '{$description}' ) ";
if($conn->query($sql)) {
echo "it worked";
} else {
echo "error: " . $conn->error;
exit();
}
$query = "SELECT * FROM `ask` ";
if( $result = $conn->query($query)) {
$fetch = mysql_fetch_array($result, MYSQL_ASSOC);
foreach($fetch as $ques) {
echo "<p>" . $ques['question'] . "</p>";
echo "<p>" . $ques['description'] . "</p>";
}
} else {
echo "failed to fetch array";
}
}
?>
All I've done there is change:
$fetch = $result->fetch_assoc();
echo "<p>{$fetch['question']}</p>";
echo "<p>{$fetch['description']}</p>";
to:
$fetch = mysql_fetch_array($result, MYSQL_ASSOC);
foreach($fetch as $ques) {
echo "<p>" . $ques['question'] . "</p>";
echo "<p>" . $ques['description'] . "</p>";
}
fetch_assoc() — Fetch a result row as an associative array
so it gets only 1 row you need to loop through the rest of the rows check the examples reference from php docs