While loop $_post from form - php

Question

<?php
include("dbFunctions.php");
$query ="SELECT * FROM `physical_examination` WHERE `PE_Opt_ans`= 0";//select form options name
$result = mysqli_query($link,$query);
?>
<div id="tabs-3">
<table>
<form action="<?php echo $_SERVER['PHP_SELF']?>" method="post" name="tab0">
<?php while ($arrayResult = mysqli_fetch_array($result)){ ?>
<tr>
<td><label for="input"><b><?php echo $arrayResult['PE_Opt_name']?></label></td>
<?php if ($arrayResult['PE_Opt_type'] == "textarea") { ?>
<td><textarea rows="8" cols="45"name = "other1"></textarea></td>
<?php } else { ?>
<td><input type="<?php echo $arrayResult['PE_Opt_type']?>" name="input<?php echo $arrayResult['id']?> " ></td>
</tr>
<?php } ?>
<?php } ?>
<br> <input value="Submit" type="submit" name="submit1">
</form>
</table>
<?php
include "dbFunctions.php";
if(isset($_POST['submit1'])) {
$number = $_POST['other1'];
I am stuck here.
How do I $_POST the form based on the while loop after I click on submit button? Do I need another while loop again for the name value of input <?php echo $arrayResult['id']?>

Answer 1

I didn't quiet get what you want but i assume you want the contents of the textarea generated by the while loop.
Change in your loop the names from input to input[] and other1 to other1[]
If you var_dump($_POST) afterwards you should see that they are now an array which you can loop over with foreach
PS: You should NEVER EVER eat raw $_POST/$_GET inputs and PHP_SELF is another security breach. But that's just my two cents