Parsing MySQL Data using JSON - php

Question

Am using MAMP local host server and am trying to get the data from the table below
I don't get any syntax errors or stack errors but when a blank browser page and yes the display_errors and all are all turned On in the php.in file.
Below are the function files am using:
For the config.php file :
<?php
define("DB_HOST", "MyLocalHost");
define("DB_USER", "user");
define("DB_PASSWORD", "");
define("DB_DATABASE", "db");
?>
For DB_Connect File
<?php
class DB_Connect {
// constructor
function __construct() {
}
// destructor
function __destruct() {
// $this->close();
}
// Connecting to database
public function connect() {
require_once 'include/Config.php';
// connecting to mysql
$con = mysqli_connect(DB_HOST, DB_USER, DB_PASSWORD) or die(mysqli_error());
// selecting database
mysqli_select_db($con,DB_DATABASE) or die(mysqli_error());
// return database handler
return $con;
}
// Closing database connection
public function close() {
mysql_close();
}
}
?>
For DB_Functions File:
<?php
class DB_Functions {
private $db;
//put your code here
// constructor
function __construct() {
require_once 'DB_Connect.php';
// connecting to database
$this->db = new DB_Connect();
$this->db->connect();
}
// destructor
function __destruct() {
}
public function getAppointments($did) {
$result = mysqli_query($this->db->connect(),"SELECT * FROM appointment WHERE did='$did'");
$appointments=array();
if($result){
while($row = mysqli_fetch_assoc($result)) {
$appointments[]=$row;
}
return $appointments;
}
else{
return false;
}
}
public function getAppointmentsByJSON($did){
echo json_encode($this->getAppointments($did));
}
}
?>
And for my getAppointmentsJson file :
<?php
//include "include/DB_Connect.php";
include "include/DB_Functions.php";
if(isset($_GET["did"])){
if(is_numeric($_GET["did"])){
$testObject = new DB_Functions();
$testObject->getAppointmentsByJSON($_GET["did"]);
echo json_encode($testObject);
}
}
?>
And help advices or tips provided will be greatly appreciated.
Thank you

Answer 1

After replicating your code and replicating the database.
The only conclusion i can come to is that, your getAppointmentsJson.php script expects a get parameter.
If you browsed to getAppointmentsJson.php?did=1
you would see an output.
Also i edited two lines in your DB_Connect class as mysqli_error(); expects exactly 1 parameter and you didn't pass it one.
$con = mysqli_connect(DB_HOST, DB_USER, DB_PASSWORD) or die(mysqli_error($con));
// selecting database
mysqli_select_db($con,DB_DATABASE) or die(mysqli_error($con));

Answer 2

I'm sorry to imform you but a blank PHP page is 99% of the time an error in php and usually the syntax. While you can enable error reporting in your ini file I would suggest doing that above the constant definitions in your case.
error_reporting(-1); // enable error reporting on known and future defined errors
ini_set('display_errors', 'On');
In your getAppointmentsJson is an error, specifically echo json_encode($testObject,);
PHP expects an additional argument giving the ,.