Return PHP MySQL select as json - php

Question

So I have a SQL database with a number of objects in that contain name price and images, I would like to know how I can select them using php and output the result into json
<?php
$db = mysqli_connect ('localhost', 'root', '', 'car_rental') or die ("SQL is Off");
$car = (isset($_GET['car']) ? $_GET['car'] : null);
mysqli_select_db($db,"car_rental");
$SQL = "SELECT * FROM `products` WHERE name LIKE \'%$car%\'";
$result = mysql_query($SQL);
while ( $db_field = mysql_fetch_assoc($result) ) {
print $db_field['sku'] . "<BR>";
print $db_field['name'] . "<BR>";
print $db_field['img'] . "<BR>";
print $db_field['price'] . "<BR>";
}
?>
This is my current code car variable will change dependent on car selected
thanks

Answer 1

For getting all values in json format, you need to use like that:
<?
$newArr = array();
while ( $db_field = mysql_fetch_assoc($result) ) {
$newArr[] = $db_field;
}
echo json_encode($newArr); // get all products in json format.
?>
UPDATE 1:
You are mixing mysqli extension with mysql. Change mysql into mysqli
UPDATE 2:
Why are you connecting database twice in code?
Modified Code:
<?php
$link = mysqli_connect("localhost", "root", "", "car_rental");
/* check connection */
if (mysqli_connect_errno()) {
printf("Connect failed: %s\n", mysqli_connect_error());
exit();
}
$car = (isset($_GET['car']) ? $_GET['car'] : null);
$query = "SELECT * FROM `products` WHERE name LIKE '%$car%'";
if ($result = mysqli_query($link, $query)) {
$newArr = array();
/* fetch associative array */
while ($db_field = mysqli_fetch_assoc($result)) {
$newArr[] = $db_field;
}
echo json_encode($newArr); // get all products in json format.
}
?>
Side Note:
Also on PHP error reporting in development phase for saving your time.