mysql / php: Update multiple rows - php

Question

I try to use the below code to update multiple rows, the below code can view the results of rows but it can not be updated, where is wrong place? How to modify it ?
<?php
$host="localhost"; // Host name
$username="abc"; // Mysql username
$password="abc123"; // Mysql password
$db_name="abc"; // Database name
$tbl_name="BRAddress"; // Table name
// Connect to server and select databse.
mysql_connect("$host", "$username", "$password")or die("Cannot connect");
mysql_select_db("$db_name")or die("Cannot select Database");
$sql="SELECT * FROM $tbl_name WHERE br_no='62779457'";
$result=mysql_query($sql);
// Count table rows
$count=mysql_num_rows($result);
?>
<table width="100%" border="0" cellspacing="1" cellpadding="0">
<form name="form1" method="post" action="">
<tr>
<td>
<table width="100%" border="0" cellspacing="1" cellpadding="0">
<tr>
<td align="center"><strong>BR No.</strong></td>
<td align="center"><strong>Date of Register</strong></td>
<td align="center"><strong>Address</strong></td>
</tr>
<?php
while($rows=mysql_fetch_array($result)){
?>
<tr>
<td align="center">
<? $br_no[]=$rows['br_no']; ?><? echo $rows['br_no']; ?>
</td>
<td align="center">
<input name="br_date_of_register[]" type="date" id="br_date_of_register" value="<? echo $rows['br_date_of_register']; ?>">
</td>
<td align="center">
<input name="br_address[]" type="text" size="60" id="br_address" value="<? echo $rows['br_address']; ?>">
</td>
</tr>
<?php
}
?>
<tr>
<td colspan="3" align="center"><input type="submit" name="Submit" value="Submit"></td>
</tr>
</table>
</td>
</tr>
</form>
</table>
<?php
// Check if button name "Submit" is active, do this
if($Submit){
for($i=0;$i<$count;$i++){
$sql1="UPDATE $tbl_name SET
br_date_of_register='$br_date_of_register[$i]',
br_address='$br_address[$i]'
WHERE br_no='$br_no[$i]'";
$result1=mysql_query($sql1);
}
}
if($result1){
header("location:update_sample.php");
}
mysql_close();
?>
Thank you very much for your help & support !

Answer 1

I think that you need to change this part
if($Submit){
to
if($_POST('Submit')){
I haven't run the whole or looked at entire code, but you have nothing that defines $Submit variable though from what I see.
Or you can put in
$Submit = $_POST('Submit');
before the if statement.
Let me know how you go.
Cheers

Answer 2

Your POST variable are empty. $br_date_of_register has no value. You must use this like following
$br_date_of_register = $_POST[br_date_of_register];
$br_address = $_POST[br_address];
for($i=0;$i<$count;$i++){
$sql1="UPDATE $tbl_name SET
br_date_of_register='$br_date_of_register[$i]',
br_address='$br_address[$i]'
WHERE br_no='$br_no[$i]'";
$result1=mysql_query($sql1);
}
Edit
if($Submit)
To
if($_SERVER['REQUEST_METHOD'] == "POST")

Answer 3

Considering your Submit check,
you can use this,
if(isset($_POST["Submit"]))
{
}
Further in your SQL statement, do this,
$sql1='UPDATE ' . $tbl_name . ' SET
br_date_of_register = ' . $br_date_of_register[$i] .
' , br_address = ' . $br_address[$i] .
' WHERE br_no = ' . $br_no[$i];