** Table Inputs**
(id_inpits, name, quantity_inputs)
Table Outputs
`(id_outputs, name_outputs, quantity_outputs, quantity_disponible)
when I want to update the quantity_output, and calculate the quantity_disponbile
knowing that : quantity_disponbile = quantity_inputs - quantity_output
I tried with :
if(!empty($_POST['do'])) {
$m_id = $_POST['id_output'];
$quantity_outputs = $_POST["quantity_outputs"];
$sql = $db->query("UPDATE outputs AS o INNER JOIN inputs As i ON i.id_input = o.inputs_id SET o.quantity_dispo = 'select quantity_inputs from inputs - FROM (select quantity_outputs from outputs )', o.quantity_outputs = '$quantity_outputs' WHERE o.id_output =' $m_id'");
if(!$sql) {
die(mysql_error());
}
}
One suggestion: quantity_disponbile is supposed a calculated field from both table. So split the logic into two: one select query and one update query. The update query just need to update the quantity_output, and the select query can be like:
select
i.quantity_inputs - o.quantity_output = quantity_disponible
from output o
inner join input i on i.id_inpits = o.inputs_id
I don't correct the typo anyway
Related
This my query in model:
return $this->db->join('tbl_customer', 'tbl_customer.cus_code = tbl_cus_account.custcode')
->where("status", 1)
->where("DATE_FORMAT(nextbillingdate,'%Y-%m') <= ", date('Y-m'))
->select('*,MAX(issuewithmain) AS issuewithmain, SUM(monthlyfee) AS monthlyfee, count(accountcode) as rows')
->group_by('custcode')
->get('tbl_cus_account');
The below are my table for join query:
-The result I want as the image below:
Your query can be something like this
SELECT t.*, t2.rows, t2.monthlyfee from tbl_cus_account t join (SELECT MAX(issuewithmain) AS issuewithmain, custcode, count(accountcode) as rows, SUM(monthlyfee) AS monthlyfee from tbl_cus_account JOIN tbl_customer ON tbl_customer.cus_code = tbl_cus_account.custcode where status = 1 AND DATE_FORMAT(nextbillingdate,"%Y-%m") <= DATE_FORMAT(now(),"%Y-%m") GROUP BY custcode) t2 on t.issuewithmain = t2.issuewithmain and t.custcode = t2.custcode
Here you made an extra join to the same table, to only get the exactly records that match with your max(issuewithmain)
You need to transform this query to codeigniter and add the conditions of the where to the corresponding table.
Maybe something like this, I haven't test it
UPDATE
return $this->db->join('(SELECT MAX(issuewithmain) AS issuewithmain, custcode, count(accountcode) as rows, SUM(monthlyfee) AS monthlyfee from tbl_cus_account where status = 1 AND DATE_FORMAT(nextbillingdate,"%Y-%m") <= "'.date('Y-m').'" GROUP BY custcode) t2', 'tbl_cus_account.issuewithmain = t2.issuewithmain AND t2.custcode = tbl_cus_account.custcode')->select('tbl_cus_account.*, t2.monthlyfee, t2.rows') ->join('tbl_customer', 'tbl_customer.cus_code = t2.custcode') ->group_by('t2.custcode') ->get('tbl_cus_account');
i have a question. my english isn't well. so i hope i explain well...
i have two tables, tbl_home and tbl_office, the question is
how do i make a select statement from 2 tables which have identical value from column 'case_no' where it is referenced in both table..
$a=$_POST['home_id']
the code above is where i get the home_id from,
while the statement below is how i try to select both tables based on value in column 'case_no' of both table. but it is based on variable $a which i retrieved from form
<?php
$sql2 = "SELECT * FROM tbl_office WHERE case_no IN (SELECT * FROM tbl_home WHERE home_id = '$
$result2=$conn->query($sql2);
while($row = $result2->fetch_assoc()){
$a=$row['case_no'];
$bc=$row['colour'];
echo " $a <br/> ";
echo " $bc2 <br/>";
?>
is the select statement above correct??
soo, i just want anybody to take a look a this specific statement and how to make it right
$sql2 = "SELECT * FROM tbl_office WHERE case_no IN (SELECT * FROM tbl_home WHERE home_id = '$a'";
You need inner join to use:
" SELECT t_office.home_id,t_office.case_no,t_office.name FROM tbl_office
t_office INNER JOIN tbl_home t_home ON t_office.case_no = t_home.case_no;
where t_office.case_no ='$a'";
u can use "inner join" for example:
"SELECT t.home_id,t.case_no,t.name FROM tbl_office
t INNER JOIN tbl_home h ON h.case_no = h.case_no"
**select tbl_home.name,tbl_office.case_no,tbl_office.color from tbl_office
INNER JOIN tbl_home on tbl_office.case_no = tbl_home.case_no
where tbl_office.case_no ='$a';**
I hope this will be working fine until $a(case_no) value is existed in tbl_home or else it doesn't give any rows
i'm in the process of joining two tables together under two different conditions. For primary example, lets say I have the following nested query:
$Query = $DB->prepare("SELECT ID, Name FROM modifications
WHERE TYPE =1 & WFAbility = '0'");
$Query->execute();
$Query->bind_result($Mod_ID,$Mod_Name);
and this query:
$Query= $DB->prepare("SELECT `ModID` from `wfabilities` WHERE `WFID`=?");
$Query->bind_param();
$Query->execute();
$Query->bind_result();
while ($Query->fetch()){ }
Basically, I want to select all the elements where type is equal to one and Ability is equal to 0, this is to be selected from the modifications table.
I further need to select all the IDs from wfabilities, but transform them into the names located in modifications where WFID is equal to the results from another query.
Here is my current semi-working code.
$Get_ID = $DB->prepare("SELECT ID FROM warframes WHERE Name=?");
$Get_ID->bind_param('s',$_GET['Frame']);
$Get_ID->execute();
$Get_ID->bind_result($FrameID);
$Get_ID->fetch();
$Get_ID->close();
echo $FrameID;
$WF_Abilties = $DB->prepare("SELECT ModID FROM `wfabilities` WHERE WFID=?");
$WF_Abilties->bind_param('i',$FrameID);
$WF_Abilties->execute();
$WF_Abilties->bind_result($ModID);
$Mod_IDArr = array();
while ($WF_Abilties->fetch()){
$Mod_IDArr[] = $ModID;
}
print_r($Mod_IDArr);
$Ability_Name = array();
foreach ($Mod_IDArr AS $AbilityMods){
$WF_AbName = $DB->prepare("SELECT `Name` FROM `modifications` WHERE ID=?");
$WF_AbName->bind_param('i',$AbilityMods);
$WF_AbName->execute();
$WF_AbName->bind_result($Mod_Name);
$WF_AbName->fetch();
$Ability_Name[] = $Mod_Name;
}
print_r($Ability_Name);
See below:
SELECT ModID,
ID,
Name
FROM modifications M
LEFT JOIN wfabilities WF
ON WF.ModID = M.ID
WHERE TYPE =1 & WFAbility = '0'
To do this, you need to join your tables, I'm not quite sure what you are trying to do so you might have to give me more info, but here is my guess.
SELECT ID, Name, ModID
FROM modifications
JOIN wfabilities
ON WFID = ID
WHERE TYPE = '1'
AND WFAbility = '0'
In this version I am connecting the tables when WFID is equal if ID. You will have to tell me exactly what is supposed to be hooking to what in your requirements.
To learn more about joins and what they do, check this page out: MySQL Join
Edit:
After looking at your larger structure, I can see that you can do this:
SELECT modifications.Name FROM modifications
JOIN wfabilities on wfabilities.ModID = modifications.ID
JOIN warframes on warframes.ID = wfabilities.WFID
WHERE warframes.Name = 'the name you want'
This query will get you an array of the ability_names from the warframes name.
This is the query:
"SELECT A.ID, A.Name,B.ModID,C.Name
FROM modifications as A
LEFT JOIN wfabilities as B ON A.ID = B.WFID
LEFT JOIN warframes as C ON C.ID = B.WFID
WHERE A.TYPE =1 AND A.WFAbility = '0' AND C.Name = ?"
I have 2 tables, the unique id's in each table are the same in both tables.
How do I go about joining the data from both tables together in php?
When I normally pull data I do it like this:
$get_board_array = mysql_query("SELECT * FROM posts WHERE user_id_to = '$id' ");
while($posts = mysql_fetch_array($get_board_array))
{
$post_id = $get_post['post_id'];
$html_output .= "<p>".$post_id."</p>";
}
As for pulling the data from separate tables and not getting it all mixed up, I was thinking of doing something like this:
$get_arrayA = mysql_query("SELECT * FROM tableA WHERE age = '36' ");
while($dataA = mysql_fetch_array($get_arrayA))
{
$dataA_id = $dataA['id'];
$dataA_firstName = $dataA['FirstName'];
foreach($dataA_id)
{
$get_arrayB = mysql_query("SELECT * FROM tableB where id='".$dataA_id."'");
while($dataB = mysql_fetch_array($get_arrayB))
{
$dataB_lastName = $dataB['LastName'];
$html_output .= "<p>".$dataA_firstName.$dataB_lastName"</p>";
echo $html_output;
}
}
}
Or would this be just too weird of a thing?
I know how to do it within SQL using inner join but how do I do something like that in PHP and output html?
It is because of you misguide use of wildcard (*) characters. STOP THAT !! This is what happens when arrogant php developers imagine that they do not need to learn SQL. If you need something , then select it.
SELECT
foo.foo_id,
foo.data as paramX ,
bar.type,
bar.something_else
FROM foo
INNER JOIN bar USING (foo_id)
WHERE
foo.state = 'open'
AND bar.type = 3
This (I'm just guessing the schema and your needs) could be a better query for your situation:
SELECT a.id,a.FirstName,b.LastName
FROM tableA a
JOIN tableB b ON b.id = a.id
WHERE a.age = '36'
Hey guys need some more help
I have 3 tables USERS, PROFILEINTERESTS and INTERESTS
profile interests has the two foreign keys which link users and interests, they are just done by ID.
I have this so far
$statement = "SELECT
InterestID
FROM
`ProfileInterests`
WHERE
userID = '$profile'";
Now I want it so that it selects from Interests where what it gets from that query is the result.
So say that gives out 3 numbers
1
3
4
I want it to search the Interests table where ID is = to those...I just don't know how to physically write it in PHP...
Please help.
Using a JOIN:
Best option if you need values from the PROFILEINTERESTS table.
SELECT DISTINCT i.*
FROM INTERESTS i
JOIN PROFILEINTERESTS pi ON pi.interests_id = i.interests_id
WHERE pi.userid = $profileid
Using EXISTS:
SELECT i.*
FROM INTERESTS i
WHERE EXISTS (SELECT NULL
FROM PROFILEINTERESTS pi
WHERE pi.interests_id = i.interests_id
AND pi.userid = $profileid)
Using IN:
SELECT i.*
FROM INTERESTS i
WHERE i.interests_id IN (SELECT pi.interests_id
FROM PROFILEINTERESTS pi
WHERE pi.userid = $profileid)
You are on the right track, lets say you execute the query above using this PHP code:
$statement = mysql_query("SELECT InterestID FROM `ProfileInterests`
WHERE userID = '$profile'");
Then you can use a PHP loop to dynamically generate an SQL statement that will pull the desired IDs from a second table. So, for example, continuing the code above:
$SQL = "";
while ($statementLoop = mysql_fetch_assoc($statement)) {
//Note the extra space on the end of the query
$SQL .= "`id` = '{$statementLoop['InterestID']}' OR ";
}
//Trim the " OR " off the end of the query
$SQL = rtrim($SQL, " OR ");
//Now run the dynamic SQL, using the query generated above
$query = mysql_query("SELECT * FROM `table2` WHERE {$SQL}")
I haven't tested the code, but it should work. So, this code will generate SQL like this:
SELECT * FROM `table2` WHERE `id` = '1' OR `id` = '3' OR `id` = '4'
Hope that helps,
spryno724
Most likely you want to join the tables
select
i.Name
from
ProfileInterests p
inner join
interests i
on
p.interestid = i.interestid
where
p.userid = 1