returning null array from php file - php

Question

i am sending a value from my android app (value) using
httpClient, i need to fetch a row from DB according to that value, when i try it
it returns a null array (json array), but if i use static value like name, for
example:
$result = mysql_query("SELECT * FROM table WHERE column= 'name'");
i get the array successfully, here is the php file, please help
<?php
$con = mysql_connect("localhost","user","pass");
if (!$con) {
die("Could not connected".mysql_error());
} else {
mysql_select_db("database",$con);
if (!empty($_POST['value'])) {
$value=$_POST['value'];
$result = mysql_query("SELECT * FROM table WHERE column= '$value'");
while ($row = mysql_fetch_assoc($result)) {
$output[]=$row;
}
print(json_encode($output));
mysql_close($con);
}
}
?>

Answer 1

Try this:
$output = array();
$i=0;
while($row = mysql_fetch_assoc($result))
{
$output[$i]=$row;
$i++;
}
print(json_encode($output));

Answer 2

You have to create array before while loop as following.
$output = array();
Following is your correct code, I am assuming that you are getting value in your post variable.
<?php
$con = mysql_connect("localhost","user","pass");
if(!$con)
{
die("Could not connected".mysql_error());
}
else
{
mysql_select_db("database",$con);
if(!empty($_POST['value']))
{
$value=$_POST['value'];
$result = mysql_query("SELECT * FROM table WHERE column= '$value'");
$output = array();
while($row = mysql_fetch_assoc($result))
{
$output[]=$row;
}
print(json_encode($output));
mysql_close($con);
}
}
?>