I have strings like this:
$str1="YESYES|c|no|c|";
$str2="YESYES|c|not this|c|YES|c|or this|c|";
$str3="YES";
I want strings like this:
$str1="YESYES";
$str2="YESYESYES";
$str3="YES";
I thought I could use preg_replace but the fact that I'm looking at a pipe seems to cause trouble, if I go like this:
$i=preg_replace("//|c\|[\s\S]+?/|c\|/",'',$i);
I get an 'unknown modifier "|"' error. I know this must have been asked before but it's very hard to search for. What is the proper regex to use?
You have to use the next line:
$i=preg_replace("/\|c\|[\s\S]+?\|c\|/",'',$i);
which is almost identical to what you have, but using \ instead of / to scape the pipes
Related
I think I need to use the preg_replace function but not sure exactly how to type in the patterns I want to find and replace. Basically, I want to replace this:
: u"x"x",
with this:
: u"x'x",
x means that any characters can go there. But I don't know how to write the x in PHP.
Thank you!
Edit: basically, I want to replace that middle double-quote with a single-quote. And I'll be searching through a big JSON file to do it. Probably should have said this at the start.
You could use this regular expression:
$result = preg_replace('#(: u".*?)"(.*?")#', "$1'$2", $string);
i'm searching for keywords in a string via a regular expression. It works fine for all keywords, exept one which contains a forward slash in it: "time/emit" .
Even using preg_quote($find,'/'), which escapes it, i still get the message:
Unknown modifier 't' in /frontend.functions.php on line 71
If i print the find pattern, it shows /time\\/emit/ . Without preg_quote, it shows /time/emit/ and both return the same error message.
Any bit of knowledge would be useful.
Try to begin and end your regular expression with different sign than /
I personally use `
I've seen people using #
I think most chars are good. You can read more about it here: http://pl.php.net/manual/en/regexp.reference.delimiters.php
Like this:
preg_match('#time/emit#', $subject); // instead of /time/emit/
To put it another way: Your $find variable should contain rather #time/emit# than /time/emit/
looks like you have something already escaping it..
preg_quote('time/emit') // returns time\/emit
preg_quote('time\/emit') // returns time\\/emit
as a hack you could simply do:
preg_quote(stripslashes($find)) // will return time\/emit
bit of code?
the the 'regex' for that particular term should look something like '/time/emit/'. With a set of keywords there may be a more efficient method so seeing what you are doing would be good.
this should work:
$a="Hello////////";
$b=str_replace($a,"//","/");
echo $b;
EDIT: I found a solution I didn't expect. See below.
Using regex via PHP's preg_match_all , I want to match a certain url (EDIT: that is already escaped) in a string formatted as json. The search works wonderfully in Notepad++ (using regex-matching, of course) but preg_match_all() just returns an empty array.
Testing on tryphpregex.com I found out that somehow my usual approach to escaping a backslash gives a pattern error, i.e. even the simple pattern https:\\ returns an empty result.
I'm utterly confused and have been trying to debug for too long so I may miss the obvious. Maybe one of you can see the simple error?
The string.
The pattern (that works fine in Notepad++, but not in PHP):
%(https:\\/\\/play.spotify.com\\/track\\/)(.*?)(\")%
You don't need to escape the slash in PHP %(https://play.spotify.com/track/)(.*?)(\")%
The Backslash before doule quote is only needed if you enclosures are double quotes too.
Found a solution to my problem.
According to this site, I need to match every backslash with \\\\. Horrible, but true.
So my pattern becomes:
$pattern = "%(https:\\\\/\\\\/play\.spotify\.com\\\\/track\\\\/)(.*?)(\")%";
Please observe that I tried to find a pattern inside a string that didn't contain clear urls, but urls containing escape characters (it was a json-output from spotify)
im having an issue with preg_match_all. I have this string:
$product_req = "ACTIVE-6,CATEGORY-ACTIVE-8,CATEGORY-ACTIVE-4,ACTIVE-9";
I need to get the numbers preceded by "ACTIVE-" but not by "CATEGORY-ACTIVE-", so in this case the result should be 6,9. I used the statement below:
preg_match_all("/ACTIVE-(\d+)/", $product_req, $this_act);
However this will return all the numbers because all of them are in fact preceded by "ACTIVE-" but thats not what i meant because i need to leave out those preceded by "CATEGORY-ACTIVE-". How can i configure preg_match_all to do it? Or maybe there is some other function that can do the job?
EDIT:
I tried this:
preg_match_all("/CATEGORY-ACTIVE-(\d+)/", $product_req, $this_cat_act);
preg_match_all("/ACTIVE-(\d+)/", $product_req, $this_act);
$act_cat = str_replace($this_cat_act[1],"",$this_act[1]);
it kinda works, but i guess there is a better and cleaner way to do it. Besides the output is kinda weird too.
Thank you.
i'm searching for keywords in a string via a regular expression. It works fine for all keywords, exept one which contains a forward slash in it: "time/emit" .
Even using preg_quote($find,'/'), which escapes it, i still get the message:
Unknown modifier 't' in /frontend.functions.php on line 71
If i print the find pattern, it shows /time\\/emit/ . Without preg_quote, it shows /time/emit/ and both return the same error message.
Any bit of knowledge would be useful.
Try to begin and end your regular expression with different sign than /
I personally use `
I've seen people using #
I think most chars are good. You can read more about it here: http://pl.php.net/manual/en/regexp.reference.delimiters.php
Like this:
preg_match('#time/emit#', $subject); // instead of /time/emit/
To put it another way: Your $find variable should contain rather #time/emit# than /time/emit/
looks like you have something already escaping it..
preg_quote('time/emit') // returns time\/emit
preg_quote('time\/emit') // returns time\\/emit
as a hack you could simply do:
preg_quote(stripslashes($find)) // will return time\/emit
bit of code?
the the 'regex' for that particular term should look something like '/time/emit/'. With a set of keywords there may be a more efficient method so seeing what you are doing would be good.
this should work:
$a="Hello////////";
$b=str_replace($a,"//","/");
echo $b;