Storing Function value in a variable - php

Question

My code generates only one result e.g "admin", then generates error. Would you please tell me how can i fix this and show all the result.
while($row = mysqli_fetch_assoc($query)) {
$role = $row['userrole'];
Function RoleFunction($roles){
if ($roles==1) {
echo " Admin";
}
else {
echo " User";
}
}
$test = RoleFunction($role);
echo "<tr>";
echo "<td>".$test."</td>";
echo "</tr>";
}
Result : Admin
Fatal error: Cannot redeclare RoleFunction() (previously declared in E:\xampp\htdocs\meds\delete.php:50) in
E:\xampp\htdocs\meds\delete.php on line 50

Answer 1

Keep your function RoleFunction($roles) outside of loop.
function RoleFunction($roles){
if ($roles == 1) {
return " Admin";
}
else {
return " User";
}
}
while ($row = mysqli_fetch_assoc($query)) {
$role = $row['userrole'];
// Print the role
echo "<tr><td>".RoleFunction($role)."</td></tr>";
}
Try the above code. It should be working.

Answer 2

I thin this will work...
Function RoleFunction($roles){
while($row = mysqli_fetch_assoc($query)) {
$role = $row['userrole'];
if ($roles==1) {
echo " Admin";
}
else {
echo " User";
}
$test = RoleFunction($role);
echo "<tr>";
echo "<td>".$test."</td>";
echo "</tr>";
}
}

Answer 3

your function is in loop, it should be outside loop like this:
function RoleFunction($roles){
if ($roles == 1) {
return "Admin";
} else {
return "User";
}
}
while ($row = mysqli_fetch_assoc($query)) {
$role = $row['userrole'];
// Print the role
echo "<tr><td>".RoleFunction($role)."</td></tr>";
}
It will work for sure