I have a dropdown HTML menu with some values which I want to insert into an input table. When the 'Insert Production' button is clicked I want it to insert these values into the relevant data table.
Previously I just entered the 'genre' details manually as text and they input into the table ok, but have now changed the input to a dropdown, but the value doesn't get entered into the table. Is there a simple way of ensuring that this value gets uploaded to the table? Sorry if this is painfully basic, but am still pretty new to all this.
<html>
<head>
<title>Inserting Production</title>
</head>
<body>
<form method="post" action="insert_product.php" enctype ="multipart/form-data">
<table width="500" height="650" align="center" border="2" bgcolor="#c6ff1a">
<tr align="center">
<td colspan="2"<h1>Insert new production:</h1></td>
</tr>
<tr>
<td align="right"><b>Production Name:</b></td>
<td><input type="text" name="prod_name" size="40"/></td>
</tr>
<tr>
<td align="right"><b>Production Genre:</b></td>
<td><select>
<option value="Drama">Drama</option>
<option value="Thriller">Thriller</option>
<option value="Comedy">Comedy</option>
<option value="Children">Children</option>
<option value="Sci-fi">Sci-fi</option>
<option value="Horror">Horror</option>
<option value="Documentary">Documentary</option>
<option value="Fantasy">Fantasy</option>
</select></form></td>
</tr>
<tr>
<td align="right"><b>Production Year</b></td>
<td><input type="text" name="prod_year"</td>
</tr>
<tr>
<td align="right"><b>Production Description</b></td>
<td><textarea name="prod_desc" cols="35" rows="10"/></textarea></td>
</tr>
<tr>
<td align="right"><b>Product Keywords</b></td>
<td><input type="text" name="prod_keywords"</td>
</tr>
<tr>
<td align="right"><b>Production Image</b></td>
<td><input type="file" name="prod_img"</td>
</tr>
<tr align="center">
<td colspan="2"><input type="submit" name="insert_production" value ="Insert Production"/></td>
</tr>
</form>
</body>
</html>
<?php
//fetches product title, cat etc and submits them to database
if(isset($_POST['insert_production'])) {
//text data variables
$product_name = $_POST['prod_name'];
$product_genre = $_POST['prod_genre'];
$product_year = $_POST['prod_year'];
$product_desc = $_POST['prod_desc'];
$product_keywords = $_POST['prod_keywords'];
//Inserting image names in db and image files saving in my htdocs/Admin_area/product_images/$product_img1
//Images names
$product_img1= $_FILES['prod_img']['name'];
//Image temporary name(we have to set image temporary names)
$temp_name1= $_FILES['prod_img']['tmp_name'];
if ($product_name == '' OR $product_genre == '' OR $product_desc == '' OR $product_year == ''){
//Simple validation alert. If user leaves any of above fields empty
//will pop-up alert box saying 'Please insert your data etc ...'
echo "<script>alert('Please complete all fields!')</script>";
exit();
}//if
else {
move_uploaded_file($temp_name1,"product_images/$product_img1");
$insert_product = "insert into productions (prod_name, prod_genre, prod_year, prod_desc, prod_keywords, prod_img)
values ('$product_name', '$product_genre', '$product_year', '$product_desc', '$product_keywords', '$product_img1')";
$run_product = mysqli_query($db, $insert_product);
//If this query runs
if ($run_product) {
echo "<script>alert('Production inserted successfully!')</script>";
echo "<script>window.open('index.php?insert_product', '_self')</script>";
}//if
}//else
}//if
?>
just add this line and try again to submit the from.
<select name="prod_genre">
You forgot to give your select tag a name. You need to give it a name if you want to use this form element for e.g. database storage etc.
So change <select> to <select name="prod_genre">
I hope this helps you!
Related
I'm trying to put info I get from a form in html into a mysql database by way of php and do it all on the same page. My code so far is thus
<?php
require('conn.php');
if( isset($_POST['send'])){
$Product_Name = htmlspecialchars($_POST["product_name"]);
$Stock = htmlspecialchars($_POST["stock"]);
$Price = htmlspecialchars($_POST["price"]);
$insert = "INSERT INTO product (Product_Name, Stock, Price) VALUES ('$Product_Name','$Stock','$Price')";
if (mysqli_query($conn,$insert)){
echo "Values inserted!\n";
}
else {
echo "Error inserting values: " . mysqli_error($conn);
}
}
mysqli_close($conn);
?>
<html>
<body>
<form action="insert.php" method="post">
<table border="1">
<tr>
<td>Product Name</td>
<td align="center"><input type="text" name="product_name" size= "30" /></td>
</tr>
<tr>
<td>In Stock</td>
<td align="center"><input type="text" name ="stock" size="30"/></td>
</tr>
<tr>
<td>Price</td>
<td align="center"><input type="text" name="price" size="30"/></td>
</tr>
<tr>
<td>Submit</td>
<td align="center"><input type="submit" value="send"></td>
<tr>
However when I try and load the page its just comes up blank. It used to at least show the form before I added in the php code but I can't pin down what I broke. What do I need to change so that this puts the users data into the database?
Edit: changed code based upon Jeffry's catches
You're missing the name attribute in your submit button declaration.
update
<input type="submit" value="send">
to
<input type="submit" name = "send" value="send">
just quick check, you miss the closing ) in
$Product_Name = htmlspecialchars($_POST["product_name"];
i also think you need a dot to append the string
$insert = "INSERT INTO product (Product_Name, Stock, Price) VALUES ("$Product_Name","$Stock","$Price")";
and if your product name is a varchar, you might need to quote it
I have a simple form that submit data into database that I have created with the name of stu_data. The problem is when I enter the add button without entering data in student ID, student name and degree, it automatically submit 0 in ID and -select- in Degree column. How I can prevent this problem, I need a simple solution. Thanks
<html>
<head>
<center>
<table border="5" bgcolor="lightblue"><br>
Student
Degree
Courses
<br><br>
</center>
</head>
<body>
<form method="POST" action="" name="reg" onSubmit="return validate()">
<center>
<table border="5" bgcolor="lightblue"> <h1 ><font color="blue"><b>STUDENT REGISTRATION SYSTEM</b></font></h1><br>HOME    UPDATE    DELETE    <br><br>
</center>
<tr>
<td>Student ID:</td>
<td><input type="int" name="id" /></td>
</tr>
<tr>
<td>Student Name:</td>
<td><input type="text" name="name" /></td>
</tr>
<tr>
<td>Degree:</td>
<td>
<select name="degree" input type="text" >
<option> -Select- </option>
<option>Bs Software Engineering</option>
<option>Bs Telecom Engineering</option>
<option>Bs Electrical Engineering</option>
<option>B Business Administration</option>
<option>B Economics</option>
</select>
</td>
</tr>
<tr>
<td> </td>
<td><input type="submit" name="submit" value="ADD" /></td>
</tr>
</table>
</form>
</body>
</html>
<?php
require'db.php';
$id = (isset($_POST['id']) ? $_POST['id'] : '');
$name = (isset($_POST['name']) ? $_POST['name'] : '');
$degree = (isset($_POST['degree']) ? $_POST['degree'] : '');
if(isset($_POST['submit'])){
$sql ="INSERT INTO student values('$id','$name','$degree')";
if ($conn->query($sql) === TRUE) {
echo "New record created successfully";
} else {
echo "Error: " . $sql . "<br>" . $conn->error;
}
$conn->close();
}
?>
You could deactivate the submit buttton and then use validation checks to ensure ita not empy.
You can do this using PHP or javascript, and when data is filled then reactivate the submit button to allow them to send or alternatively just dont submit data until all forms are filled
Returning false from the function will stop the form submitting.
function validate(){
/*
... Test your fields ...
Allow submitting only if fields not empty
For Example:
*/
var allow=1;
// If ID a number
if(!(document.getElementsByName("id").value>0)){
allow=0;
}
// Test Name Characters
var regex = /^[a-zA-Z ]{2,30}$/;
if (!regex.test(document.getElementsByName("name").value)) {
allow=0;
}
if (allow){
return true; // Allow the form to submit
}else{
return false; // Stop the form submitting
}
}
I am fairly new to PHP and SQL.
I want to be able to assign a task to a certain user and the update that row in the database with the user's name assigned to that task.
Here is my code:
<table border="0" width="1100px" style= "font-size: 12px" >
<thead>
<tr valign="top" align="left">
<th height="20"></th>
<th height="20">Customer</th>
<th>Vehicle</th>
<th>Appt Time</th>
<th>Notes</th>
<th>Assign</th>
<th>Action</th>
<tr><td valign="top" colspan="6"><hr><br></td></tr>
</tr>
</thead>
<tbody>
<?php
while( $row = mysql_fetch_assoc( $result ) ){
echo
"<tr valign='center'>
<td width='50'><b>{$row['id']}</td>
<td width='220' height='70'><b>{$row['firstname']}
</td>
<td width='240'><b>{$row['car']}</b> <br>{$row['reg']}</td>
<td width='170'>Monday<br>24 September<br>17:00</td>
<td width='240'>{$row['notes']}<br><b>Status:</td>
<td width='240'>
<form action='bookings.php' method='post'>
<select style='width:90px' class='reg' name='assign'required>
<option value=''></option>
<option value='User1'>User1</option>
<option value='User2'>User2</option>
<option value='User3'>User3</option>
<option value='User4'>User4</option>
<option value='User5'>User5</option>
</select><input type='submit' value='>' class='assignButton'/></form>
</td><td>
<button class='myButton'>Edit</button>
</td>
<tr><td colspan='6'><hr class='hrTitle'></td></tr>
</tr>\n";
}
?>
</tbody>
</table>
As you can see, I have a number of users that can be selected, I want to be able to assign that task to a user from the select list.
Any help is much appreciated.
Try the following steps.
Give a name to your submit button.
<input type='submit' value='>' name='submit' class='assignButton'>
Add a hidden input field to your form. Give it the value of the id of the current row. Give it a name. I chose id.
This is very important so you can know which customer to edit. Please double check the value that you will set. From your code, I see it is $row['id'].
<input type="hidden" name="id" value='$row["id"]''>
In your PHP file bookings.php (assuming you have a connection to your database), process the submitted form.
if(isset($_POST["submit"])){ //checks if the form was submitted
$id = $_POST["id"]; //id of the customer
$assign = $_POST["assign"]; //your selected value
$query = "UPDATE table SET columnToModify = '$assign' WHERE id = '$id'";
$result = $connection->query($query); //run the query
}
Hope it helps.
I am using this code to serach database and I am using 4 fields in this code but this code does not serach database value.
where problem in this code tell me plz edit my code for full working serach with 4 fields
my code :
<?php
{
include ('connection.php');
if(isset($_REQUEST['submit'])){
$optid = $_POST['OPRID'];
$optdec = $_POST['OPRDEFNDESC'];
$empid = $_POST['EMPLID'];
$empmail = $_POST['EMAILID'];
$query ="SELECT * FROM OPERATOR WHERE OPRID LIKE '%".$optid."%'
or OPRDEFNDESC LIKE '%".$optdec."%' or EMPLID LIKE '%".$empid."%'
or EMAILID LIKE '%".$empmail."%' ";
}
else{
$query="SELECT * FROM OPERATOR";
$objParse = oci_parse ($ora_conn, $query);
}
?>
<form action="multi.php" method="get" action="<?=$_SERVER['SCRIPT_NAME'];?>">
<table width="500" border="1" align="center">
<tr>
<th>Operator ID
<input name="OPRID" type="text" id="OPRID" value="";>
<tr>
<th>Operator Name
<input name="OPRDEFNDESC" type="text" id="OPRDEFNDESC" value="";>
<tr>
<th>Person ID
<input name="EMPLID" type="text" id="EMPLID" value="";>
<tr>
<th>Email ID
<input name="EMAILID" type="text" id="EMAILID" value="";>
<input type="submit" value="Search"></th>
</tr>
</table>
</form>
<table>
<tr>
<td>Operator ID</td>
<td>Operator Name</td>
<td>Person ID</td>
<td>Email ID</td>
</tr>
<?
$success = oci_execute($objParse);
//while($objResult = oci_fetch_array($objParse,OCI_BOTH))
while($objResult = oci_fetch_array($objParse, OCI_RETURN_NULLS+OCI_ASSOC))
{
?>
<tr>
<td><div align="center"><?=$objResult["OPRID"];?></div></td>
<td><?=$objResult["OPRDEFNDESC"];?></td>
<td><?=$objResult["EMPLID"];?></td>
<td><div align="center"><?=$objResult["EMAILID"];?></div></td>
<td align="center"><a href="Optr_Edit.php?OprID=
<?=$objResult["OPRID"];?>">Edit</a></td>
</tr>
<?
}
?>
</table>
<?
oci_free_statement($objParse);
oci_close($ora_conn);
}
?>
Try like this
<tr>
<td><div align="right"><strong>Password Encrypted:</strong></div></td>
<td>
<select name="txtENCRYPTED">
<option value="">Select</option>
<option <?php if ($objResult["ENCRYPTED"] == "Y") {echo 'selected';} ?>value="Y">Y</option>
<option <?php if ($objResult["ENCRYPTED"] == "N") {echo 'selected';} ?> value="N">N</option>
</select>
</td>
</tr>
You are doing it wrong
Select element do not have value attribute
You have value attribute only in options element.
For eg:
<select name="txtENCRYPTED" id="txtENCRYPTED">
<option value="">Select</option>
<option value="Y">Y</option>
<option value="N">N</option>
</select>
In your code you have provided the db-retrived-data in tags setting .
The tag defines the menu. It can have the following settings
The name setting adds an internal name to the field so the program that handles the form can identify the fields.
The size option defines how many items should be visible at a time. Default is one item.
The multiple setting will allow for multiple selections if present.
The tag defines the single items in the menu.
The value setting defines what will be submitted if the item is selected.
one solution :-
<form method="post" action="" >
<select name="encrypt" value="encrypted" id='select'>
<option value="">Select</option>
<option value="<?php if($objResult["ENCRYPTED"]=='Y'){ echo 'Y'; } ?>">Y</option>
<option value="<?php if($objResult["ENCRYPTED"]=='N'){ echo 'N'; } ?>">N</option>
</select>
<input type="submit" value="submit" id='form'/>
</form>
</td>
</tr>
//script type jquery.js
//script type javascript
$(document).ready(function(){
$('form').submit(function(){
alert($('#select').val());
});
});
</script>
I figured out how to update a table with multiple columns using checkboxes, except when more than one checkbox is selected the update will only happen for one of the columns not both. Could someone please help? Thank you!
Here is the working code for the table:
<table width="100%" border="0" cellspacing="1" cellpadding="0">
<tr>
<td><form name="frmactive" method="GET" action="assigncases1.php">
<table width="100%" border="0" cellpadding="3" cellspacing="1">
<tr>
<select name="assigned_to">
<option value=""></option>
<option value="Kristin Dodd"> Kristin Dodd </option>
<option value="Matt Ursetto"> Matt Ursetto </option>
<option value="Derek Bird"> Derek Bird </option>
<option value="John Castle"> John Castle </option>
<option value="Martin Delgado"> Martin Delgado </option>
</select>
<br>
<input type='submit' value = 'Assign'>
</tr>
<tr>
<td> </td>
<td colspan="4" align="center"><strong>Update multiple rows in mysql with checkbox<br>
</strong></td>
</tr><tr>
<td align="center" bgcolor="#FFFFFF"></td>
<td align="left"><strong>Name</strong></td>
<td align="left"><strong>SSO</strong></td>
<td align="left"><strong>case_status</strong></td>
<td align="left"><strong>Assigned To:</strong></td>
</tr>
<?php
$result=mysql_query($sql);
$count=mysql_num_rows($result);
while($rows=mysql_fetch_array($result)){
?>
<tr>
<td align="center"><input name="checkbox" type="checkbox" id="checkbox[]" value="<?
echo $rows['id']; ?>"></td>
<td><? echo $rows['full_name']; ?></td>
<td><? echo $rows['sso']; ?></td>
<td><? echo $rows['case_status']; ?></td>
<td><? echo $rows['assigned_to']; ?></td>
</tr>
<?php
}
?>
<tr>
<td colspan="5" align="center"> </td>
</tr>
</table>
</form>
</td>
</tr>
</table>
And this is what I have for the php page that take the info.
// Retrieve data from database
$checkbox = $_GET['checkbox'];
$assigned_to = $_GET['assigned_to'];
// update data in mysql database
$sql="UPDATE rmstable2 SET assigned_to='$assigned_to' WHERE id='$checkbox'";
$result = mysql_query($sql);
$count = mysql_numrows($result);
{
mysql_query("UPDATE `rmstable2` SET `assigned_to` = '$assigned_to'
WHERE `id` = '$checkbox'")
or die(mysql_error());
}
//If they did not enter a search term we give them an error
if ($assigned_to == "")
{
echo "<h3>You forgot to enter a required field. Please try again.</h3><br>";
}
// if successfully updated.
else if($assigned_to !== "")
{
echo "<b>Update Successful</b><br>";
echo "<br>This case was assigned to:<b> $assigned_to</b><br>";
echo "<br>To see the change go back and click on <b>Refresh Page</b> if you assigned it
to someone other than you, the case will disappear and show up in their list of
assigned cases.";
}
else {
echo "ERROR";
}
?>
In your HTML, you're defining your checkboxes with the name checkbox - so only one value will be sent to PHP. To get an array of values, update the checkboxes to be created with name="checkbox[]" and when the form is submitted, you can use the selected values like an array.
In that case, you'll be able to loop through each item with:
$checkbox = $_GET['checkbox'];
$assigned_to = $_GET['assigned_to'];
foreach ($checkbox as $id) {
// do a very basic validation to see if the ID is numeric
if (!is_numeric($id)) continue;
$sql = 'UPDATE rmstable2 SET assigned_to="' . mysql_real_escape_string($assigned_to) . '" WHERE id=' . (int)$id;
mysql_query($sql);
}
Also, as always worth noting, the mysql_* functions are being deprecated and you should consider to start using either mysqli_* or PDO methods.