possible ?: mysql row to an if condition - php

hi guys im trying to insert a mysql data to a variable that will set an if condition depending on the result. is this possible, am i doing it right? what is the right way to do it ? what i want to achieve is to validate if there's a equal value given by the user inside my mysql rows.
$db = mysql_connect('localhost','test','');
if (!$db)
{
print "<h1>Unable to Connect to MySQL</h1>";
}
$dbname = 'test';
$btest = mysql_select_db($dbname);
if (!$btest)
{
print "<h1>Unable to Select the Database</h1>";
}
$sql_statement = "SELECT * ";
$sql_statement .= "FROM registered_email ";
$result = mysql_query($sql_statement);
$outputDisplay = "";
$myrowcount = 0;
if (!$result) {
$outputDisplay .= "<br /><font color=red>MySQL No: ".mysql_errno();
$outputDisplay .= "<br />MySQL Error: ".mysql_error();
$outputDisplay .= "<br />SQL Statement: ".$sql_statement;
$outputDisplay .= "<br />MySQL Affected Rows: ".mysql_affected_rows()."</font><br />";
}
else{
$numresults = mysql_num_rows($result);
for ($i = 0; $i < $numresults; $i++)
{
$row = mysql_fetch_array($result);
$id = $row['id'];
$sentEmailClients = $row['email'];
$outputDisplay.= "".$sentEmailClients."<br />";
}
}
and here what im trying to achieve, btw is $clientEmail has a default values so dont worry about that.
if($clientEmail === $outputDisplay){
...... some codes..........
}
else{
....... some codes.......
}

you can use mysql row to compare with your user input. you can add condition, while you'r getting row value for the email inside the loop.
$email_exist = 0;//define the default value.
for ($i = 0; $i < $numresults; $i++)
{
$row = mysql_fetch_array($result);
$id = $row['id'];
$sentEmailClients = $row['email'];
$outputDisplay.= "".$sentEmailClients."<br />";
//my code start here
if($sentEmailClients == $clientEmail)
$email_exist = 1;
}
//outside the loop
if($email_exist == 1) {
//..........write some code.......
}else{
//........write some code.......
}

why don't you use a while loop?
make sure to update to mysqli_* because mysql_* is deprecated and is going to get removed on php 7.0
$email_exist = 0;//define the default value.
while ( $row = mysql_fetch_assoc($result) ) // you are using associative array and not the indexed once tho you should go for mysql_fetch_assoc
{
$id = $row['id'];
$sentEmailClients = $row['email'];
$outputDisplay.= "".$sentEmailClients."<br />";
//my code start here
if($sentEmailClients == $clientEmail)
$email_exist += 1; //maybe it exist more than once?
}
//outside the loop
if($email_exist == 1) {
//..........write some code.......
}else{
//........write some code.......
}
or you can do something more simple like this
$query = "select email from tablename where email='$clientemail'";
$result = mysql_query($query);
$count = mysql_num_rows($result);
if($count > 0) {
// email exists
} else {
// doesn't exist
}

Related

Dropdown of tables to show content

This script allows the user to choose a table from the dropdown and then displays the contents of the chosen table.
At the moment the DB connection is working.
A list of tables is shown in the dropdown.
Problem: No content from the database table is shown.
I have checked through the code and everything looks OK, but it still only seems to partially work.
<?php
//update this to your DB connection details.
$dbh = "localhost";
$dbn = "dbname";
$dbu = "dbuser";
$dbp = "dbpass";
$conn = mysql_connect($dbh,$dbu,$dbp) or die("Unable to connect do database.");
mysql_select_db($dbn, $conn) or die("Unable to select database.");
//Some vars for Order by and Limit.
if (!isset($ordBy)){
$ordBy = 1;
}
if (!isset($ps)){
$ps = 0;
}
if (!isset($ord)){
$ord = 1;
}
if ($ord == 1){
$tOrder = "ASC";
} else {
$tOrder = "DESC";
}
//Tables drop-down
$result = mysql_query("SHOW TABLES FROM $dbn") or die("Cannot list table names.");
echo "
<form name=\"table_browser\" action=\"".$PHP_SELF."\" method=\"GET\" >
<select name=\"t\" onChange=\"javascript:submit();\">
<option>Select a table</option>
";
while ($row = mysql_fetch_row($result)){
echo " <option value=".$row[0].">".$row[0]."</option>\n";
}
echo " </select>
</form>\n";
if (!isset($t)){
die("Please select a table");
}
//Get number of rows in $t and then select
$result = mysql_query("SELECT COUNT(*) FROM $t") or die("The requested table doesn't exist.");
$total = mysql_result($result,0);
$qry = "SELECT * FROM $t ORDER BY ".$ordBy." ".$tOrder." LIMIT ".($ps*20).",20 ";
if (isset($qry)) {
$result = mysql_query($qry) or die("The requested table doesn't exist.");
$i = 0;
while ($i < mysql_num_fields($result)) {
$meta = mysql_fetch_field($result);
if (!$meta) {
echo "No information available on the table<br />\n";
}
$name[$i] = $meta->name;
$i++;
}
//Display table details
echo "Rows ".($ps*20+1)." to ".((($ps+1)*20 < $total) ? (($ps+1)*20) : ($total))." of $total from table:
<b>$meta->table</b>\n<br /><br />\n";
//Count results
if ($ps > 0) {
echo "20 Previous - ";
} else {
echo "20 Previous - ";
}
if ((($ps+1)*20) < $total ){
echo "Next 20\n";
} else {
echo "Next 20\n";
}
//Column names
echo "<br /><br />\n<table>\n <tr>\n";
for ($j = 0; $j < $i; $j++){
echo " <td><b>$name[$j]</b>";
if ($ordBy == $name[$j]) {
echo "<img src=\"images/arrow$ord.gif\">";
}
echo "</td>\n";
}
echo " </tr>\n";
//Data
while ($row = mysql_fetch_array($result)){
echo " <tr onmouseover=\"this.style.background='#DDDDDD'\" onmouseout=\"this.style.background=''\">";
for ($j = 0; $j < $i; $j++){
echo "<td>".$row[$name[$j]]."</td>";
}
echo "</tr>\n";
}
echo "</table>\n";
}
mysql_close();
?>
#gentlebreeze - my eyes hurt from trying to read that - but I can't see where you are actually setting the variable called $t - which is used to determine the table. You should have
$t = $_GET['t'];
somewhere before the line:
....if (!isset($t)){....
because you need to use it in the line:
....$result = mysql_query("SELECT COUNT(*) FROM $t"....
and you should not be using mysql_query either - old and now deprecated. You should switch to PDO and bound variables.

Why Getting only 1 array instead of many arrays?

I am a completely newbie in programming php I would like to make this code below return many arrays(to flash as3), however I only receive one array.Can anyone please pinpoint what is my mistake here? thanks.
$data_array = "";
$i = 0;
//if(isset($_POST['myrequest']) && $_POST['myrequest'] == "get_characters")
//{
$sql = mysqli_query($conn, "SELECT * FROM ns_users ORDER BY Char_id");
while($row = mysqli_fetch_array($sql))
{
$i++;
$fb_name = $row["Username"];
$fb_id = $row["Fb_id"];
$fb_at = $row["Access_token"];
$fb_sig = $row["Fb_sig"];
$char_id = $row["Char_id"];
if($i == 1)
{
$data_array .= "$fb_name|$fb_id|$fb_at|$fb_sig|$char_id";
}
else
{
$data_array .= "(||)$fb_name|$fb_id|$fb_at|$fb_sig|$char_id";
}
echo "returnStr=$data_array";
exit();
}
When you write your exit insight your loop you stop executing your program and you get only one record. You should set the echo and exit after your while loop.
$data_array = "";
$i = 0;
$sql = mysqli_query($conn, "SELECT * FROM ns_users ORDER BY Char_id");
while($row = mysqli_fetch_array($sql)) {
$i++;
$fb_name = $row["Username"];
$fb_id = $row["Fb_id"];
$fb_at = $row["Access_token"];
$fb_sig = $row["Fb_sig"];
$char_id = $row["Char_id"];
if($i == 1) {
$data_array .= "$fb_name|$fb_id|$fb_at|$fb_sig|$char_id";
} else {
$data_array .= "(||)$fb_name|$fb_id|$fb_at|$fb_sig|$char_id";
}
}
echo "returnStr=$data_array";
exit();
Those two last line of your should be outside of your loop:
$data_array = "";
$i = 0;
//if(isset($_POST['myrequest']) && $_POST['myrequest'] == "get_characters")
//{
$sql = mysqli_query($conn, "SELECT * FROM ns_users ORDER BY Char_id");
while($row = mysqli_fetch_array($sql))
{
$i++;
$fb_name = $row["Username"];
$fb_id = $row["Fb_id"];
$fb_at = $row["Access_token"];
$fb_sig = $row["Fb_sig"];
$char_id = $row["Char_id"];
if($i == 1)
{
$data_array .= "$fb_name|$fb_id|$fb_at|$fb_sig|$char_id";
}
else
{
$data_array .= "(||)$fb_name|$fb_id|$fb_at|$fb_sig|$char_id";
}
}
echo "returnStr=$data_array";
exit();
If you would name the columns that you want in the SELECT then it's much simpler. Make sure to use MYSQLI_ASSOC in the fetch:
$sql = mysqli_query($conn, "SELECT Username, Fb_id, Access_token, Fb_sig, Char_id FROM ns_users ORDER BY Char_id");
while($row = mysqli_fetch_array($sql, MYSQLI_ASSOC))
{
$data_array[] = implode('|', $row);
}
echo "returnStr=" . implode('(||)', $data_array);
exit();

Trouble pulling data out of an sql table

I have a html form tat my user can use to search through a table in my MYSQL database.
By default if you just hit go it will display the entire table, however I would like them to be able select certain fields and my php form to search via the fields that are filled in.
I seem to be unable to find a way of doing this without writing a seperate query for all 11 inputs in the different combinations they could be entered in, which comes out at a total of 76 queries..
If anyone has a way to simplify this I would love any advice.
I have tried just running a query with the AND operator but that doesnt work as some variables can be left empty and that will return no result, not sure if that is what is upposed to happen, but that is what is happening.
my html and php:
http://jsbin.com/oquwid/1/edit
PHP
$sql = "SELECT * FROM ".$tbl_name."
WHERE fname='".$fname."'
and lname='".$lname."'
and city='".$city."'
and phone='".$pohne."'
and interest_inet='".$internet."'
and interest_tv='".$television."'
and interest_voice='".$voice."'
and submission_ip='".$ip."'
and inquiry_handled='".$handled."'";
$result = mysql_query($sql);
echo "<table border='1'>";
echo "<tr>";
$i = 0;
while ($i < mysql_num_fields($result))
{
$meta = mysql_fetch_field($result, $i);
echo "<th>".$meta->name."</th>";
$i++;
}
while ($row = mysql_fetch_row($result))
{
echo '<tr>';
foreach($row as $item)
{
echo "<td>".$item."</td>";
}
echo '</tr>';
echo $row;
}
echo "</table>";
You could append parts to the query depending on which are filled in:
if(!empty($fname) || !empty($lname) || !empty($city) || etc.etc.) {
$sql = "SELECT * FROM $tbl_name WHERE ";
$queryParts = array();
if($fname != "") {
$queryParts[] = " fname='$fname'";
}
if($lname != "") {
$queryParts[] = " lname='$lname'";
}
etc.etc.
$sql .= implode(" AND ", $queryParts);
// do query, etc.
}
else {
// Don't do query if no parameters are specified
}
You also need to make sure that you escape all of your query parameters before you use them or risk having someone ravage your data.
The following uses loops to avoid duplicate code:
$fieldIsSpecified = false;
$queryFields = array('fname' => $fname, 'lname' => $lname, 'city' => $city, etc...);
foreach($queryFields as $column => $value) {
if(!empty($value){
$fieldIsSpecified = true;
break;
}
}
if($fieldIsSpecified) {
$sql = "SELECT * FROM $tbl_name WHERE ";
$queryParts = array();
foreach($queryFields as $column => $value) {
if(!empty($value)) {
$queryParts[] = " $column = '$value'";
}
}
$sql .= implode(" AND ", $queryParts);
// do query, etc.
}
else {
// Don't do query if no parameters are specified
}
The reason you're query isn't working if a value is not filled in, is probably because the query results in this (given first name is empty)
SELECT * FROM $tbl_name WHERE fname=''
And there probably isn't a user having no first name.
Further, you considered adding a flag per requested info, and on base of that either add or remove the needed part to the select part of the query ?
For example,
$sql = "SELECT * FROM $tbl_name WHERE ";
$queryChanged = false;
if (isset($fname)){
if (!empty($fname)){
$sql .= "fname='$fname' ";
$queryChanged=true;
}
}
if (isset($lname)){
if (!empty($lname)){
$sql .= ($queryChanged) ? " AND lname='$lname'" : "lname='$lname'";
$queryChanged = true;
}
}
... //Continue the logic
I'd recommend you to read this post about select * as well as this about user input and how to handle it
this is how i am going to have to do it
php:`
//if just lname is set
if(empty($start_date) && empty($end_date) && empty($fname) && isset($lname) && empty($city) &&
empty($internet) && empty($television) && empty($voice) && empty($phone) && empty($ip) &&
empty($handled) && empty($not_handled)){
$sql = "SELECT * FROM ".$tbl_name."
WHERE lname='".$lname."'";
$result = mysql_query($sql);
echo "<table border='1'>";
echo "<tr>";
$i = 0;
while ($i < mysql_num_fields($result))
{
$meta = mysql_fetch_field($result, $i);
echo "<th>".$meta->name."</th>";
$i++;
}
while ($row = mysql_fetch_row($result))
{
echo '<tr>';
foreach($row as $item)
{
echo "<td>".$item."</td>";
}
echo '</tr>';
}
echo "</table>";
exit();
}
//if just city is selected
if(empty($start_date) && empty($end_date) && empty($fname) && empty($lname) && isset($city) &&
empty($internet) && empty($television) && empty($voice) && empty($phone) && empty($ip) &&
empty($handled) && empty($not_handled)){
$sql = "SELECT * FROM ".$tbl_name."
WHERE city='".$city."'";
$result = mysql_query($sql);
echo "<table border='1'>";
echo "<tr>";
$i = 0;
while ($i < mysql_num_fields($result))
{
$meta = mysql_fetch_field($result, $i);
echo "<th>".$meta->name."</th>";
$i++;
}
while ($row = mysql_fetch_row($result))
{
echo '<tr>';
foreach($row as $item)
{
echo "<td>".$item."</td>";
}
echo '</tr>';
}
echo "</table>";
exit();
}
And etc... i am going to have to repeat this process until i cover all, 76 i believe, possibilites. thnkfully its just a lot of copy paste. thanks for the help everyone
First don't use MYSQL_*. Use PDO
Second, with your code, your are requiring all fields to be filled.
If you don't wanna do that then go this way:
You can use WHERE 1=1 , but it's not recommended !!!!!
$sql = "SELECT * FROM ".$tbl_name." WHERE confirm = '0' ";
$sql .= "AND fname = ".$fname."";
$sql .= "AND lname = ".$lname."";
$sql .= "AND city = ".$city."";
$sql .= "AND phone = ".$pohne."";
$sql .= "ORDER BY date DESC";
$result = mysql_query($sql);
echo "<table border='1'>";
echo "<tr>";
$i = 0;
while ($i < mysql_num_fields($result))
{
$meta = mysql_fetch_field($result, $i);
echo "<th>".$meta->name."</th>";
$i++;
}
while ($row = mysql_fetch_row($result))
{
echo '<tr>';
foreach($row as $item)
{
echo "<td>".$item."</td>";
}
echo '</tr>';
echo $row;
}
echo "</table>";

mysql_fetch_array not fetching complete data?

I have a code which fetches data from a mysql table and converts it into pdf document, the code is working fine except it is skipping row 1.
Here is the code from which i have removed the pdf generation process since the problem is in the loop which is fetching data.
Please help.
<?php
session_start();
if(isset($_SESSION['user']))
{
$cr = $_POST['cour'];
$s = $_POST['sem'];
require('fpdf.php');
include('../includes/connection.php');
$sql = "SELECT * FROM `student` WHERE AppliedCourse ='$cr'";
$rs = mysql_query($sql) or die($sql. "<br/>".mysql_error());
if(!mysql_fetch_array($rs))
{
$_SESSION['db_error'] = "<h2><font color = 'RED'>No such course found! Pease select again.</font></h2>";
header('Location: prinrepo.php');
}
else {
for($i = 0;$i <= $row = mysql_fetch_array($rs);$i++)
{
$formno[$i] = $row ['FormNo'];
$rno[$i] = $row ['rollno'];
$snm[$i] = $row ['StudentNm'];
$fnm[$i] = $row ['FathersNm'];
$mnm[$i] = $row ['MothersNm'];
$addr[$i] = $row['Address'];
$pic[$i] = $row['imagenm'];
$comm[$i] = $row['SocialCat'];
echo $formno[$i]."<br />";
echo $rno[$i]."<br />";
echo $snm[$i]."<br />";
echo $fnm[$i]."<br />";
echo $mnm[$i]."<br />";
echo $addr[$i]."<br />";
echo $pic[$i]."<br />";
echo $comm[$i]."<br />";
echo "<br />";
}
}
mysql_close($con);
}
?>
You are fetching the first row outside of your for() loop then you miss it.
After mysql_query() your should use mysql_num_rows() to check if there are any rows in your result and then fetch them in the for loop.
More info here : http://php.net/manual/fr/function.mysql-num-rows.php
Your code would look like this :
$sql = "SELECT * FROM `student` WHERE AppliedCourse ='$cr'";
$rs = mysql_query($sql) or die($sql. "<br/>".mysql_error());
if(0 == mysql_num_rows($rs)) {
$_SESSION['db_error'] = "<h2><font color = 'RED'>No such course found! Pease select again.</font></h2>";
header('Location: prinrepo.php');
} else {
for($i = 0;$i <= $row = mysql_fetch_array($rs);$i++)
{
// Your code
}
}

Update Multiple Rows (PHP + MySQL)

I am working on a lead management system - and as the database for it grows the need for more bulk functions appears - and unfortunately I am getting stuck with one of them. The database stores many different leads - with each lead being assigned to a specific closer; thus the database stores for each lead the lead id, name, closer name, and other info. The main lead list shows a checkbox next to each lead which submits the lead id into an array:
<input type=\"checkbox\" name=\"multipleassign[]\" value=\"$id\" />
Now this all goes to the following page:
<?php
include_once"config.php";
$id = $_POST['multipleassign'];
$id_sql = implode(",", $id);
$list = "'". implode("', '", $id) ."'";
$query = "SELECT * FROM promises WHERE id IN ($list) ";
$result = mysql_query($query);
$num = mysql_num_rows ($result);
if ($num > 0 ) {
$i=0;
while ($i < $num) {
$closer = mysql_result($result,$i,"business_name");
$businessname = mysql_result($result,$i,"closer");
echo "$closer - $businessname";
echo"<br>";
++$i; } } else { echo "The database is empty"; };
echo "<select name=\"closer\" id=\"closer\">";
$query2 = "SELECT * FROM members ";
$result2 = mysql_query($query2);
$num2 = mysql_num_rows ($result2);
if ($num2 > 0 ) {
$i2=0;
while ($i2 < $num2) {
$username = mysql_result($result2,$i2,"username");
$fullname = mysql_result($result2,$i2,"name");
echo "<option value=\"$fullname\">$fullname</option>";
++$i2; } } else { echo "The database is empty"; }
echo "</select>";
?>
I want to be able to use the form on this page to select a closer from the database - and then assign that closer to each of the leads that have been selected. Here is where I have no idea how to continue.
Actually - i got it. I don't know why I didn't think of it sooner. First off I passed the original $list variable over to the new page - and then:
<?php
include_once"config.php";
$ids = $_POST['list'];
$closer = $_POST['closer'];
$query = "UPDATE `promises` SET `closer` = '$closer' WHERE id IN ($ids) ";
mysql_query($query) or die ('Error updating closers' . mysql_error());
echo "A new closer ($closer) was assigned to the following accounts:";
$query = "SELECT * FROM promises WHERE id IN ($list) ";
$result = mysql_query($query);
$num = mysql_num_rows ($result);
if ($num > 0 ) {
$i=0;
while ($i < $num) {
$businessname = mysql_result($result,$i,"business_name");
echo "<li>$businessname";
++$i; } } else { echo "The database is empty"; };
?>
The updated page before this:
$query = "SELECT * FROM promises WHERE id IN ($list) ";
$result = mysql_query($query);
$num = mysql_num_rows ($result);
if ($num > 0 ) {
$i=0;
while ($i < $num) {
$closer = mysql_result($result,$i,"business_name");
$businessname = mysql_result($result,$i,"closer");
echo "$closer - $businessname";
echo"<br>";
++$i; } } else { echo "The database is empty"; };
echo "<form name=\"form1\" method=\"post\" action=\"multiple_assign2.php\">";
echo "<input type=\"hidden\" name=\"list\" value=\"$list\" />";
echo "<select name=\"closer\" id=\"closer\">";
$query2 = "SELECT * FROM members ";
$result2 = mysql_query($query2);
$num2 = mysql_num_rows ($result2);
if ($num2 > 0 ) {
$i2=0;
while ($i2 < $num2) {
$username = mysql_result($result2,$i2,"username");
$fullname = mysql_result($result2,$i2,"name");
echo "<option value=\"$fullname\">$fullname</option>";
++$i2; } } else { echo "The database is empty"; }
echo "</select>";
echo "<input name=\"submit\" type=\"submit\" id=\"submit\" value=\"Reassign Selected Leads\">";
?>
After you select the leads and submit the form , your script should show them in a list with hidden inputs (with name=leads[] and value=the_lead's_id) and next to each lead there will be a dropdown box () which will be populated with all the closers.
After choosing and sending the second form your script will "run" all-over the leads' ids array and update each and every one of them.
Got the idea or you want some code?

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