Conditional Logic on MySQL Query with PHP - php

Question

I am doinga MySQL query to retreive data using PHP. I need to have a logic that if the data set returned is empty it shows a warning message else it displays the results:
$searchQuery = mysql_escape_string($_POST['searchQuery']);
$sql="SELECT * FROM db.tblname WHERE column1 = '".$searchQuery."'";
$result = mysqli_query($conn,$sql);
while($row = mysqli_fetch_array($result)){
echo $row["column1"];
}
mysqli_close($conn);

Answer 1

You need num_rows on the object
$result = mysqli_query($conn,$sql);
if ($result->num_rows == 0) {
echo 'result empty';
} else {
while($row = mysqli_fetch_array($result)){
echo $row["column1"];
}
}
http://php.net/manual/en/mysqli-result.num-rows.php

Answer 2

Change mysql_escape_string to mysqli_escape_string here
$where = "";
if(isset($_POST['searchQuery']) && trim($_POST['searchQuery'])){
$searchQuery = mysqli_escape_string($conn,$_POST['searchQuery']);
$where =" WHERE column1 = '".$searchQuery."'";
}
$sql="SELECT * FROM db.tblname ".$where;

Answer 3

It's as simple as this:
if ($result) {
//Your code
} else {
echo "Error: ".mysqli_error($conn);
}

Answer 4

First check with mysqli_num_rows(). Here is how to
$searchQuery = mysql_escape_string($_POST['searchQuery']);
$sql="SELECT * FROM db.tblname WHERE column1 = '".$searchQuery."'";
$result = mysqli_query($conn,$sql);
if(mysqli_num_rows($result) > 0) {
while($row = mysqli_fetch_array($result)){
echo $row["column1"];
}
}
else {
echo "No records found";
}
mysqli_close($conn);

Answer 5

$searchQuery = mysql_escape_string($_POST['searchQuery']);
$sql="SELECT * FROM db.tblname WHERE column1 = '".$searchQuery."'";
$result = mysqli_query($conn,$sql);
if(mysqli_num_rows($result) > 0) {
while($row = mysqli_fetch_array($result)){
echo $row["column1"];
}
} else {
echo "No results found";
}
mysqli_close($conn);