It is a tracking system like DHL. Tracking shipment number from MySQL database using php form.
but I need it Search multiple row separate by comma from mysql using php.
<?php
$ship=$_POST['Consignment'];
$cons = explode(',',$ship);
?>
<?php
$sql = "SELECT * FROM tbl_courier WHERE cons_no = '$cons[]'";
$result = dbQuery($sql);
$no = dbNumRows($result);
if($no == 1){
while($data = dbFetchAssoc($result)) {
extract($data);
?>
Shipment Name: <?php echo $ship_name; ?>
Shipment Phone: <?php echo $phone; ?>
<?php }//while
}//if
else {
echo 'In else....';
?>
Consignment Number not found.Search Again.
<?php
}//else
?>
So I need my search will work with separating by comma(,).
Thanks for helping me.
You can use IN operator in that case.
<?php
$ship=$_POST['Consignment'];
?>
<?php
$sql = "SELECT * FROM tbl_courier WHERE cons_no IN(".$ship.")";
$result = dbQuery($sql);
$no = dbNumRows($result);
if($no == 1){
while($data = dbFetchAssoc($result)) {
extract($data);
?>
Hope it will help to you.
change your sql query you have written '$cons[]' in select query which is wrong . after explode you will get data as 1,2,3 so you just need to write variable in query not array and user IN Operator like this.
`$sql = "SELECT * FROM tbl_courier WHERE cons_no IN(".$ship.")";`
You should always prepare/sanitize the POST data before using it in MySql query (in terms of security):
<?php
if (isset[$_POST['Consignment']] && !empty($_POST['Consignment'])) {
$ship = $_POST['Consignment'];
$cons = explode(',', $ship);
$cons = array_filter($cons, function($v){
return trim(strip_tags($v));
});
$cons = '"' . implode('","', $cons) . '"';
$sql = "SELECT * FROM tbl_courier WHERE cons_no IN ($cons)";
$result = dbQuery($sql);
$no = dbNumRows($result);
if ($no == 1) {
while ($data = dbFetchAssoc($result)) {
extract($data);
....
}
....
}
?>
Please Use Find IN SET
SELECT * FROM tbl_courier WHERE FIND_IN_SET(cons_no,'1,2,3,4,5')
Updated
SELECT * FROM tbl_courier WHERE FIND_IN_SET(cons_no,'$ship')
Note :- $ship Comma Separated Value not an array
I found the Answer:
if(isset($_POST['Consignment'])){
$ship=$_POST['Consignment'];
$shipment= explode(',',$_POST['Consignment']);
$ship = implode("', '",$shipment) ;
$query = "SELECT * FROM `tbl_courier` WHERE `cons_no` IN('$ship')";
$results = $mysqli->query($query);
if($results){
print '<table border="1">';
while($row = $results->fetch_assoc()) {
print '<tr>';
print '<td>'.$row["cons_no"].'</td>';
print '<td>'.$row["customerName"].'</td>';
print '<td>'.$row["customerPhone"].'</td>';
print '</tr>';
}
print '</table>';
// Frees the memory associated with a result
$results->free();
}
else {
echo "Query Not Match";
}
$mysqli->close();
}
Thanks to Answer.
Related
I try to retrive all rows related to the specific category(continent table) but it only shows one and not all.
<?php
$townid = $_GET['id'];
$query = "SELECT * FROM towns INNER JOIN continents ON towns.catid = continents.id WHERE continents.id = '$townid'";
$row = mysqli_fetch_assoc(mysqli_query($link, $query));
// The category/Continent
echo '<h1>';
echo $row['catname'];
echo '</h1>';
//The post name/Town name
echo $row['title'];
?>
You need to call mysqli_fetch_assoc() in a loop.
$result = mysqli_query($link, $query);
$first = true;
while ($row = mysqli_fetch_assoc($result)) {
if ($first) { // Only show the category header once.
// The category/Continent
echo '<h1>';
echo $row['catname'];
echo '</h1>';
$first = false;
}
//The post name/Town name
echo $row['title'];
}
You can do something like:
<?php
$townid = $_GET['id'];
$query = "SELECT * FROM towns INNER JOIN continents ON towns.catid = continents.id WHERE continents.id = '$townid'";
$rows = mysqli_fetch_all(mysqli_query($link, $query), MYSQLI_ASSOC);
// The category/Continent
foreach ($rows as $row) {
echo '<h1>';
echo $row['catname'];
echo '</h1>';
//The post name/Town name
echo $row['title'];
}
?>
On another note, its better to parameterised your query since you are getting the $townid from a GET params.
This is how to do it in PHP https://www.php.net/manual/en/mysqli-stmt.bind-param.php
I've hit a little wall in something I'm trying to do.
I have a table, entitled 'projects', in a database in SQL.
My issue is that I can't seem to select every row in a specific column.
This is the code that I've got so far relevant to this question (keep in mind that '$conn' is the connection to the SQL database, and the include command on the second line is just to include that connection):
//CONNECTION FILE
include "../include/dbh-inc.php";
//ASSIGNING QUERY VALUES TO VARIABLES
$q1 = mysqli_query($conn,"SELECT pid FROM projects;");
$q2 = mysqli_query($conn,"SELECT ptitle FROM projects;");
$q3 = mysqli_query($conn,"SELECT plink FROM projects;");
//SETTING ARRAYS FROM VARIABLES
$ids = mysqli_fetch_array($q1);
$titles = mysqli_fetch_array($q2);
$links = mysqli_fetch_array($q3);
mysqli_close($conn);
file_put_contents("newtest.txt","$titles\n");
foreach($titles as $title) {
file_put_contents("newtest.txt","$title\n", FILE_APPEND); //Testing
}
if(count($ids) > 0) {
file_put_contents("TEST.txt","");
for($i = 0; $i < count($ids)-1; $i+=1) {
$count = count($ids);
$title = $titles[$i];
$id = $ids[$i];
$link = $links[$i];
file_put_contents("TEST.txt","$i: $title, $id ($count), $link\n",FILE_APPEND);
echo("
<div class=\"projlink\">
<a href=\"$link\" style=\"width:190px;height:90px\">
<h2>$title</h2>
</a>
</div>
");
}
}
else {
echo("
<h2>Nothing here currently!<br>Be patient!</h2>
");
}
Any thoughts?
Thanks!
- Raphael
You are only fetching one row with mysqli_fetch_array. Also, you can get all columns in one query:
$q1 = mysqli_query($conn,"SELECT pid, ptitle, plink FROM projects;");
$rows = mysqli_fetch_all($q1, MYSQLI_ASSOC);
If you don't have mysqli_fetch_all then:
while($rows[] = mysqli_fetch_assoc($q1));
Then just loop $rows and use the columns:
foreach($rows as $row) {
echo $row['pid'] . ' ' . $row['ptitle'] . ' ' . $row['plink'];
}
If you really need separate arrays (this is rarely necessary):
$ids = array_column($rows, 'pid');
$titles = array_column($rows, 'ptitle');
$links = array_column($rows, 'plink');
<?php
include ("db.php");
$id2 = "SELECT MAX(id) FROM osalejad;";
$id = $conn->query($id2);
if (id<= 8){
while($id<= 7) {
$min = 1;
$max = 20;
$suvanumber = rand($min, $max);
$bar = (string) $suvanumber;
$prii= "vaba2" . $bar;
$sql="INSERT INTO osalejad (name) VALUES ('$prii')";
$result = $conn->query($sql);
if (!$result) {
die('Invalid query: ' . mysql_error());
}
}
}
else {
echo '8 osalejat on juba kirjas';
}
?>
I have a question, i want to insert data into MYSQl table, word with a random number, but problem is, it never work as it should - if i have 3 records in name column, then till, it adds 8 more records, instead of 5 records. Is something outside of scope atm?
I will use the DB in this code.
<?php
include("db.php");
$sql = "SELECT * FROM `osalejad`;";
$result = $conn->query($sql);
$var = array();
if ($result->num_rows > 0) {
// output data of each row
while ($row = mysqli_fetch_array($result)) {
$var[] = $row["name"];
}
} else {
/// echo "0 results";
}
//shuffle the array, and encode into json.
shuffle($var);
$brack=json_encode($var);
$testbrack= json_encode(array_chunk($var,2));
$final = '{';
$final .= '"teams":';
$final .= $testbrack;
$final .= ',"results":[[[[0,0],[null,null]],[[null,null],[null,null]]]]}';
//updating last tournament bracket.
$sql1 = "UPDATE lan_brackets SET json='$final' ORDER BY tid DESC LIMIT 1;";
$roundOne=$conn->query($sql1);
?>
Any idea why this is showing a result of null? I'm guessing it has to do with where I put $link before I did the query, but it has to be done that way, correct?
function getcatposts($cat_id) {
$qc = #mysqli_query($link, "SELECT * FROM topics WHERE topic_cat='$cat_id'");
while($row = mysqli_fetch_array($qc)) {
$topic_title=$row['topic_subject'];
$topic_id=$row['topic_id'];
}
$qc2 = #mysqli_query($link, "SELECT * FROM categories WHERE cat_id='$cat_id'");
while($row2 = mysqli_fetch_array($qc2)) {
$cat_name=$row2['cat_name'];
}
Updated code:
function getcatposts($cat_id) {
$link = mysqli_connect("localhost", "lunar_lunar", "", "lunar_users");
$qc = mysqli_query($link, "SELECT * FROM topics WHERE topic_cat='$cat_id'");
while($row = mysqli_fetch_array($qc)) {
$topic_title=$row['topic_subject'];
$topic_id=$row['topic_id'];
}
$qc2 = mysqli_query($link, "SELECT * FROM categories WHERE cat_id='$cat_id'");
while($row2 = mysqli_fetch_array($qc2)) {
$cat_name=$row2['cat_name'];
}
echo $cat_name;
echo '<br />';
echo $topic_title;
echo '<br />';
echo $topic_id;
}
New issue is that its displaying like this:
http://gyazo.com/43e8a91b9e0cf4f5e413536907891dcf.png
When the DB looks like this:
http://gyazo.com/1ead8bd0f150838dae3ee4a476419679.png
It should be displaying all three of them and this is a function meaning it will keep redoing all the code until it can't query anymore data. Any ideas?
The problem here is that you're trying to echo the values outside your loop. The variables inside the loop will get overwritten on each iteration and at the end of looping, the variable will hold the value of the last iteration.
If you want to display all the values, move the echo statement inside your loop, like so:
while($row = mysqli_fetch_array($qc))
{
$topic_title = $row['topic_subject'];
$topic_id = $row['topic_id'];
echo $topic_title.'<br/>';
echo $topic_id.'<br/>';
}
$qc2 = mysqli_query($link, "SELECT * FROM categories WHERE cat_id='$cat_id'");
while($row2 = mysqli_fetch_array($qc2))
{
$cat_name = $row2['cat_name'];
echo $cat_name.'<br/>';
}
If you care about the order, you could store the titles, ids and cat_names in arrays like so:
while($row = mysqli_fetch_array($qc))
{
$topic_title[] =$row['topic_subject'];
$topic_id[] = $row['topic_id'];
}
$qc2 = mysqli_query($link, "SELECT * FROM categories WHERE cat_id='$cat_id'");
while($row2 = mysqli_fetch_array($qc2))
{
$cat_name[] =$row2['cat_name'];
}
And then loop through them:
for ($i=0; $i < count($topic_id); $i++) {
if( isset($topic_id[$i], $topic_title[$i], $cat_name[$i]) )
{
echo $cat_name[$i].'<br/>';
echo $topic_title[$i].'<br/>';
echo $topic_id[$i].'<br/>';
}
}
Your function displays only one result because your echo is outside the while loop...
Put the Echo statements inside the loop, or you will print only the last result!
while($row = mysqli_fetch_array($qc)) {
$topic_title=$row['topic_subject'];
$topic_id=$row['topic_id'];
echo $topic_title;
echo '<br />';
echo $topic_id;
}
$qc2 = mysqli_query($link, "SELECT * FROM categories WHERE cat_id='$cat_id'");
while($row2 = mysqli_fetch_array($qc2)) {
$cat_name=$row2['cat_name'];
echo $cat_name;
echo '<br />';
}
I have a table named members with 3 rows. The following code attempts to display all the rows in the members table. It displays the 1'st record 3 times instead of displaying each record once.
<?php
$con = new mysqli("localhost", "root", "jce123", "profile");
if (mysqli_connect_errno()) {
printf("Connection failed: %s\n", mysqli_connect_error());
exit();
}
$sql = "SELECT * FROM members";
$res = mysqli_query($con,$sql);
$num = mysqli_num_rows($res);
$array = mysqli_fetch_assoc($res);
$keysarray = array_keys($array);
$valuearray = array_values($array);
for ($i=0; $i < $num; $i++) {
for($j = 0; $j < count($array); $j++) {
echo "<table>";
echo "<tr><td>".$keysarray[$j].": </td><td>".$valuearray[$j]."</td></tr>";
echo "</table>";
}
echo "<br><br>";
}
mysqli_close($con);
?>
I've updated this per suggestions:
$sql = "SELECT * FROM members";
$res = mysqli_query($con,$sql);
$num = mysqli_num_rows($res);
$array = mysqli_fetch_assoc($res);
while ($row = mysqli_fetch_assoc($res)) {
foreach($array as $key => $value){
echo "<table>";
echo "<tr><td>".$key.": </td><td>".$value."</td></tr>";
echo "</table>";
}
echo "<br><br>";
}
That's because, your $num = 3, count($array) = 3 and the outer for loop has no bearing on inner for loop.
Where you have $array = mysqli_fetch_assoc($res);, you will only receive one row from your database. You need something like:
while ($row=mysqli_fetch_assoc($res))
{
// processing for each row
}
Any basic tutorial will tell you this. Even the PHP docs provide an example.
you can use do something like this..
while ($row=mysqli_fetch_assoc($res))
{
// processing for each row
e.g
echo $row['id'];
echo $row['name'];
etc
}
try this... this peace of code is not tested but just to give you an idea...
$sql = "SELECT * FROM members";
$res = mysqli_query($con,$sql);
$num = mysqli_num_rows($res);
while ($row = mysqli_fetch_assoc($res)) {
echo "<table>";
echo '<tr><td> id = "'.$row['id'].'":
</td><td> name = "'.$row['name'].'"</td></tr>";
echo "</table>";
}