How to reach the exception block - php

Question

So I am messing around with symfony router component and I created a small wrapper.
One thing that came up was how do I get a request to throw a 500 in unit tests? The method in question is:
public function processRoutes(Request $request) {
try {
$request->attributes->add($this->_matcher->match($request->getPathInfo()));
return call_user_func_array($request->attributes->get('callback'), array($request));
} catch (ResourceNotFoundException $e) {
return new RedirectResponse('/404', 302);
} catch (Exception $e) {
return new RedirectResponse('/500', 302);
}
}
And the test in question is:
public function testFiveHundred() {
$router = new Router();
$router->get('/foo/{bar}', 'foo', function($request){
return 'hello ' . $request->attributes->get('bar');
});
$response = $router->processRoutes(Request::create('/foo/bar', 'GET'));
$this->assertEquals(500, $response->getStatusCode());
}
Right now the test will fail because we are defined and the status code will be 200. Is there something special I can do to the Request object I create, to make it throw a 500?

Answer 1

I think you got several options here you can play with:
Decide that a specific path will always throw an exception.
This will force you to make some changes in your code.
public function processRoutes(Request $request) {
...
if ($request->getRequestUri() == '/path/that/throws/exception') {
throw Exception('Forced to throw exception by URL');
}
...
}
public function testFiveHundred() {
...
$response = $router->processRoutes(Request::create('/path/that/throws/exception', 'GET'));
...
}
Make a DummyRequest object that will extends your original Request class and make sure this object will raise an Exception (for example - you know for sure that you use the getPathInfo(), so you can use this).
class DummyRequest extends Request {
public function getPathInfo() {
throw new Exception('This dummy request object should only throw an exception so we can test our routes for problems');
}
}
public function testFiveHundred() {
...
$dummyRequest = new DummyRequest();
$response = $router->processRoutes($dummyRequest);
...
}
Since the function getRequestUri of our $dummyRequest throws an exception, your call to $router->processRoutes will have our dummy to throw that exception.
This is a general idea, you would probably need to play a bit with the namespaces and the functions there (I didn't test it, however this should work).