MySQL Prepared statement confusion - php

Question

Ok, so I am having a lot of trouble with Prepared statements. I've done hours of research and still can't seem to fully understand everything...
I really feel like I need to understand Prepared statements because I was just about to release a few new free APIs on my website (which require API Key to execute API) but I recently realized how insecure everything is.... I can simply use SQL injection to bypass API Key check, e.g. 'OR'1'='1
Here is how I validate API Key:
$apikey = $_GET['key'];
$sql = "SELECT * FROM `table` WHERE `key` = '$apikey'";
$query = mysqli_query($con, $sql);
if($query)
{
$fetchrow = mysqli_fetch_row($query);
if(isset($fetchrow[0]))
{
echo "API Key is valid!";
}
else
{
echo "API KEY is invalid";
}
}
And like mentioned above this can easily be bypassed by executing my API like this
http://website.com/api.php?key='OR'1'='1
This really scared me at first, but then I did some research and learned a good way to prevent any form of SQL injection is to use prepared statement, so I did a lot of research and it just seems quite complicated to me :/
So I guess my question is, how can I take my above code, and make it function the same way using prepared statements?

Answer 1

Probably everything you need:
class Database {
private static $mysqli;
Connect to the DB:
public static function connect(){
if (isset(self::$mysqli)){
return self::$mysqli;
}
self::$mysqli = new mysqli("DB_HOST", "DB_USER", "DB_PASS", "DB_NAME");
if (mysqli_connect_errno()) {
/*Log error here, return 500 code (db connection error) or something... Details in $mysqli->error*/
}
self::$mysqli->query("SET NAMES utf8");
return self::$mysqli;
}
Execute statement and get results:
public static function execute($stmt){
$stmt->execute();
if ($mysqli->error) {
/*Log it or throw 500 code (sql error)*/
}
return self::getResults($stmt);
}
Bind results to the pure array:
private static function getResults($stmt){
$stmt->store_result();
$meta = $stmt->result_metadata();
if (is_object($meta)){
$variables = array();
$data = array();
while($field = $meta->fetch_field()) {
$variables[] = &$data[$field->name];
}
call_user_func_array(array($stmt, "bind_result"), $variables);
$i = 0;
while($stmt->fetch()) {
$array[$i] = array();
foreach($data as $k=>$v)
$array[$i][$k] = $v;
$i++;
}
$stmt->close();
return $array;
} else {
return $meta;
}
}
Class end :)
}
Example of usage:
public function getSomething($something, $somethingOther){
$mysqli = Database::connect();
$stmt = $mysqli->prepare("SELECT * FROM table WHERE something = ? AND somethingOther = ?");
$stmt->bind_param("si", $something, $somethingOther); // s means string, i means number
$resultsArray = Database::execute($stmt);
$someData = $resultsArray[0]["someColumn"];
}
Resolving your problem:
public function isKeyValid($key){
$mysqli = Database::connect();
$stmt = $mysqli->prepare("SELECT * FROM table WHERE key = ? LIMIT 1");
$stmt->bind_param("s", $key);
$results = Database::execute($stmt);
return count($results > 0);
}
PHP automatically closes DB connection so no worries about it.

Answer 2

$sql = "SELECT * FROM `table` WHERE `key` = ?";
if(stmt = $mysqli->prepare($sql)) {
$stmt->bind_param("i", $apikey);
$stmt->execute();
$stmt->bind_result($res);
$stmt->fetch();
$stmt->close();
}
See more - http://php.net/manual/en/mysqli.prepare.php