Order while loop data - php

Question

I'm making a ranking system. But what I want is to order the results I get ($kn) from highest to lowest. How can I do this?
include "includes/core.inc.php";
require "includes/connect.inc.php";
$id = $_GET["id"];
$query = "SELECT * FROM submitted WHERE id= '$id'";
$query_run = $db->query($query);
while($row = mysqli_fetch_assoc($query_run)){
$name= $row["name"];
$sql = "SELECT * FROM submitted WHERE name= '$name' AND pending = 'Accept'";
$sql_run = $db->query($sql);
$count = $sql_run->num_rows;
$nums= "SELECT * FROM ranking WHERE name= '$name'";
$nums_run = $db->query($nums);
$num = $nums_run->num_rows;
$kn = ($count * 0.4) + (($num * 0.2) * 3);
echo '$name';
echo '$kn';
}

Answer 1

Looping over a list and querying each element is almost never a good idea. Instead, you can move the entire logic to the query, and then sort it there:
$query =
"SELECT s.name AS name, (cnt_submitted * 0.4) + ((cnt_ranking * 0.2) * 3) AS kn
FROM (SELECT name, COUNT(*) AS cnt_submitted
FROM submitted
WHERE id = '$id' AND
pending = 'Accept'
GROUP BY name) s
JOIN (SELECT name, COUNT(*) AS cnt_ranking
FROM ranking
GROUP BY name) r ON r.name = s.name
ORDER BY 2 DESC";
$query_run = $db->query($query);
while ($row = mysqli_fetch_assoc($query_run)) {
$name = $row["name"];
$kn = $row["kn"];
echo '$name';
echo '$kn';
}
Note:
The $id variable should probably be a bound variable in a prepared statement to safe-guard against SQL-injection attacks.
I left it as it was in the OP, though, since this is not the point of the question and I don't want to add additional confusion.

Answer 2

You can do it also in PHP:
$result = [];
while (...) {
.....
$kn = ($count * 4) + (($num * 2) * 30);
$result[] = [
'rank' => $kn,
'name' => $name
];
}
usort($result, function($a, $b) {
return $b['rank'] - $a['rank'];
});