Wamp Warning for deprecated mysql code [duplicate] - php

Question

This question already has answers here:
Deprecated: mysql_connect() [duplicate]
(12 answers)
Closed 6 years ago.
How can I make this query or script work properly with having these deprecated errors I am getting when using Wamp I am not getting the errors while using Xampp though. The errors or warning i'm getting is on this pic
this is my php script
<?php
$con = mysql_connect("localhost","root","");
if (!$con) {
die('Could not connect: ' . mysql_error());
}
mysql_select_db("db", $con);
$result = mysql_query("SELECT gender as gender_occupation, COUNT(*) as total FROM hostel_blocks GROUP BY gender");
$rows = array();
while($r = mysql_fetch_array($result)) {
$row[0] = $r[0];
$row[1] = $r[1];
array_push($rows,$row);
}
print json_encode($rows, JSON_NUMERIC_CHECK);
mysql_close($con);
?>
when i changed some connection code i got a blank page.

Answer 1

PHP mysql was deprecated in PHP 5.5 and removed starting PHP 7
You should move to mysqli instead.
Your code using mysqli would look like this:
<?php
$con = mysqli_connect("localhost","root","");
if (!$con) {
die('Could not connect: ' . mysqli_error($con));
}
mysqli_select_db( $con, "db");
$result = mysqli_query($con, "SELECT gender as gender_occupation, COUNT(*) as total FROM hostel_blocks GROUP BY gender");
$rows = array();
while($r = mysqli_fetch_array($result)) {
$row[0] = $r[0];
$row[1] = $r[1];
array_push($rows,$row);
}
print json_encode($rows, JSON_NUMERIC_CHECK);
mysqli_close($con);
?>