PHP Failed to update database - php

Question

it's my first time working with php and after 2h of searching for my problem i came to the conclusion that i cant find and fix it.
I hope you guys can help me!
<?php
require "./config/_sqlconnect.php";
$temp = $_POST;
$vname = "Peter";
$nname = "Hans";
$straße ="XY";
$strnr ="8";
$plz = "9031";
$ort = "würzburg";
$land ="deutschland";
$tel ="1334134";
$email ="asdas#aasd.com";
$datum ="21.03.1942";
$anrede ="herr";
$connection = mysql_connect($dbhost, $dbuser, $dbpass, $dbname) or die
("Verbindungsversuch fehlgeschlagen");
mysql_select_db($dbname, $connection) or die('DB FAIL');
$sql = "INSERT INTO tadresse (vname,nname,straße,strnr,plz,ort,land,tel,email,datum,anrede) VALUES($temp)";
$eintrag = "INSERT INTO tadresse (vname,nname,straße,strnr,plz,ort,land,tel,email,datum,anrede) VALUES ('$vname','$nname','$straße','$strnr','$plz','$ort','$land','$tel','$email','$datum','$anrede')";
$eintragen = mysql_query($eintrag);
if($eintragen == true)
{
echo 'RICHTIG';
}
else
{
echo 'FEHLER';
}?>
the Result:
Notice: Array to string conversion in C:\xampp\htdocs\aufgabe\text.php on line 23
FEHLER

Answer 1

As the error suggest you are passing an array, but there is needed of a string. Your $temp is an array because it's the same as $_POST. So if you are sure that you want to pass there the $temp you have to change like this:
$sql = "INSERT INTO tadresse (vname,nname,straße,strnr,plz,ort,land,tel,email,datum,anrede) VALUES('" . implode("','", $temp) . "')";
But I see that you also have all the variables also so you can pass one by one here in VALUES like this:
$sql = "INSERT INTO tadresse (vname,nname,straße,strnr,plz,ort,land,tel,email,datum,anrede) VALUES('$vname', '$nname', '$straße', ....)";
And my suggestion is to use only English characters so to change $straße to something else