apply css to specific element in array - php

Question

I am fetching data of employees from mysql database into array and displaying in table.
everything is working but i want to apply a condition in array that
If salary is greater then 30,000 then change its color to red .
Tried
$q = "select name, salary from array";
$res = mysqli_query($link, $q);
$arr = array();
while ($data = mysqli_fetch_assoc($res)) {
$arr[] = $data;
}
echo '<table class="table table-hover">
<th>Name</th><th>Salary</th>';
$keys = array_keys($arr);
foreach ($keys as $key => $value) {
echo "$value , ";
}
for ($i=0; $i < count($arr); $i++) {
echo '<tr>';
foreach ($arr[$keys[$i]] as $key => $value) {
if ($arr[$keys[$i]['salary']] > 34000) {
echo "<td style='color: red; background-color:pink;'> $key=>$value </td>";
}else{
echo "<td> $key=>$value </td>";
}
}
echo "</tr>";
}
echo '</table>';
this is how my table looks
i want to change color of salary if it is greater than 30,000...

Answer 1

Change
if ($arr[$keys[$i]['salary']] > 34000) {
to
if ($value > 30000) {

Answer 2

I think you just got a little lost when processing an array which contains another arrays. A simple foreach loop is the simplest way of dealing with this.
echo '<table class="table table-hover"><th>Name</th><th>Salary</th>';
foreach ($arr as $row) {
echo '<tr>';
// using a ternary operator here rather than an IF
$style = $row['salary'] > 30000
? ' style="color:red;background-color:pink;"'
: '';
echo "<td>{$row['name']}</td>";
echo "<td $style>{$row['salary']}</td>";
echo '</tr>';
}