PHP JSON multiple echo value - php

Question

In addition to the question yesterday: Question
I got multiple (3) Items in the json file:
results.json
["{\"Produkt\":{\"Produktkategorie\":\"Artikel1\",\"Optionen\":{\"MaxBreite\":\"250\",\"MaxHoehe\":\"150\",\"MinBreite\":\"10\",\"MinHoehe\":\"5\",\"ProduktStaerke\":\"3\",\"KantenAuswahl\":\"Kante1\"}}}","{\"Produkt\":{\"Produktkategorie\":\"Artikel2\",\"Optionen\":{\"MaxBreite\":\"250\",\"MaxHoehe\":\"150\",\"MinBreite\":\"10\",\"MinHoehe\":\"5\",\"ProduktStaerke\":\"3\",\"KantenAuswahl\":\"Kante2\"}}}","{\"Produkt\":{\"Produktkategorie\":\"Artikel3\",\"Optionen\":{\"MaxBreite\":\"250\",\"MaxHoehe\":\"150\",\"MinBreite\":\"10\",\"MinHoehe\":\"5\",\"ProduktStaerke\":\"3\",\"KantenAuswahl\":\"Kante3\"}}}"]
I want echo all three value from "Produktkategorie" and the value "MaxBreite"
It should look like this:
Artikel1 - 250
Artikel2 - 250
Artikel3 - 250
My code looks like this:
$json = file_get_contents('results.json');
$json = json_decode($json, true);
$anzahl = count($json) -1;
$anzahlstart = 0;
while ($anzahlstart < $anzahl) {
$json = json_decode($json[$anzahlstart], true);
$ProduktkategorieFile = $json['Produkt']['Produktkategorie'];
$MaxBreiteFile = $json['Produkt']['Optionen']['MaxBreite'];
echo $ProduktkategorieFile. "-" .$MaxBreiteFile;
$anzahlstart ++;
}
Unfortunately my Code throws a error after passing first line:
Notice: Undefined offset: 1 in
After that I don't get any result.
Kings of coding, could you help me again please :)

Answer 1

Do you need like this?:-
<?php
$json_string = file_get_contents('results.json');
$json = json_decode($json_string, true);
// I hope the above line gives you exact json what you shown to us
foreach ($json as $jso){
$array = json_decode($jso, true);
echo $array['Produkt']['Produktkategorie'].' - '.$array['Produkt']['Optionen']['MaxBreite'];
echo PHP_EOL;
}
Output:-https://eval.in/728430
Note:- If yes then I hope you are able to get other values easily.Thanks

Answer 2

The problem is with the $json variable name: You're reassigning it on this line: $json = json_decode($json[$anzahlstart], true);
Rename this variable and you're good to go!
I would also replace the while loop with a foreach loop as shown in my example:
<?php
//With foreach
$original = '["{\"Produkt\":{\"Produktkategorie\":\"Artikel1\",\"Optionen\":{\"MaxBreite\":\"250\",\"MaxHoehe\":\"150\",\"MinBreite\":\"10\",\"MinHoehe\":\"5\",\"ProduktStaerke\":\"3\",\"KantenAuswahl\":\"Kante1\"}}}","{\"Produkt\":{\"Produktkategorie\":\"Artikel2\",\"Optionen\":{\"MaxBreite\":\"250\",\"MaxHoehe\":\"150\",\"MinBreite\":\"10\",\"MinHoehe\":\"5\",\"ProduktStaerke\":\"3\",\"KantenAuswahl\":\"Kante2\"}}}","{\"Produkt\":{\"Produktkategorie\":\"Artikel3\",\"Optionen\":{\"MaxBreite\":\"250\",\"MaxHoehe\":\"150\",\"MinBreite\":\"10\",\"MinHoehe\":\"5\",\"ProduktStaerke\":\"3\",\"KantenAuswahl\":\"Kante3\"}}}"]';
$decoded = json_decode($original);
foreach($decoded as $encodedProduct){
$product = json_decode($encodedProduct,true)['Produkt'];
echo $product['Produktkategorie'] . " - " . $product['Optionen']['MaxBreite'] . "\n";
}
//Original fixed code
$json = json_decode($original, true);
$anzahl = count($json);
$anzahlstart = 0;
while ($anzahlstart < $anzahl) {
$decodedJson = json_decode($json[$anzahlstart], true);
$ProduktkategorieFile = $decodedJson['Produkt']['Produktkategorie'];
$MaxBreiteFile = $decodedJson['Produkt']['Optionen']['MaxBreite'];
echo $ProduktkategorieFile. " - " .$MaxBreiteFile . "\n";
$anzahlstart ++;
}

Answer 3

Your problem is, that you are trying to decode an array of json string, instead of the string itself.
so that would be like this now.
$json = file_get_contents('results.json');
$json = json_decode($json[0], true); // notice [0];on this line.
...
After reading the other question, I have had this problem before, but you essentially need to do two things. in your ajax.
$.ajax({
...
data : JSON.stringify(data)
})
This changes an object into a json string,
Then on your server you do the decode.
something like this
$json = json_decode($jsonstringGoesHERE , true);
For more information in understanding the issue, have a look at this other post.
jQuery ajax, how to send JSON instead of QueryString